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# Integer to Roman LeetCode Solution

## Problem – Integer to Roman LeetCode Solution

Roman numerals are represented by seven different symbols: `I``V``X``L``C``D` and `M`.

``````Symbol       Value
I             1
V             5
X             10
L             50
C             100
D             500
M             1000
``````

For example, `2` is written as `II` in Roman numeral, just two one’s added together. `12` is written as `XII`, which is simply `X + II`. The number `27` is written as `XXVII`, which is `XX + V + II`.

Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not `IIII`. Instead, the number four is written as `IV`. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as `IX`. There are six instances where subtraction is used:

• `I` can be placed before `V` (5) and `X` (10) to make 4 and 9.
• `X` can be placed before `L` (50) and `C` (100) to make 40 and 90.
• `C` can be placed before `D` (500) and `M` (1000) to make 400 and 900.

Given an integer, convert it to a roman numeral.

Example 1:

``````Input: num = 3
Output: "III"
Explanation: 3 is represented as 3 ones.
``````

Example 2:

``````Input: num = 58
Output: "LVIII"
Explanation: L = 50, V = 5, III = 3.``````

Example 3:

``````Input: num = 1994
Output: "MCMXCIV"
Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.``````

Constraints:

• `1 <= num <= 3999`

## Integer to Roman LeetCode Solution in Java

``````public static String intToRoman(int num) {
String M[] = {"", "M", "MM", "MMM"};
String C[] = {"", "C", "CC", "CCC", "CD", "D", "DC", "DCC", "DCCC", "CM"};
String X[] = {"", "X", "XX", "XXX", "XL", "L", "LX", "LXX", "LXXX", "XC"};
String I[] = {"", "I", "II", "III", "IV", "V", "VI", "VII", "VIII", "IX"};
return M[num/1000] + C[(num%1000)/100] + X[(num%100)/10] + I[num%10];
}
``````

## Integer to Roman LeetCode Solution in C++

``````class Solution {
public:
string intToRoman(int num)
{
string res;
string sym[] = {"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"};
int val[] = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};

for(int i=0; num != 0; i++)
{
while(num >= val[i])
{
num -= val[i];
res += sym[i];
}
}

return res;
}
};
``````

## Integer to Roman LeetCode Solution in Python

``````def intToRoman1(self, num):
values = [ 1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1 ]
numerals = [ "M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I" ]
res, i = "", 0
while num:
res += (num//values[i]) * numerals[i]
num %= values[i]
i += 1
return res

def intToRoman(self, num):
values = [ 1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1 ]
numerals = [ "M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I" ]
res = ""
for i, v in enumerate(values):
res += (num//v) * numerals[i]
num %= v
return res
``````
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