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Interesting XOR! CodeChef Solution
Problem -Interesting XOR! CodeChef Solution
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Interesting XOR! CodeChef Solution in C++17
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define fast \
ios_base::sync_with_stdio(false); \
cin.tie(NULL); \
cout.tie(NULL);
#define fileio \
freopen("input.txt", "r", stdin); \
freopen("output.txt", "w", stdout);
#define pb push_back
#define vll vector<ll>
#define pll pair<ll, ll>
#define ff first
#define ss second
#define vpll vector<pair<ll, ll>>
#define stll set ll
#define msgll multiset<ll, greater<>>
#define msll multiset<ll>
#define mpll map<ll, ll>
void infinity()
{
ll c;
cin>>c;
ll a=log2(c);
for(ll i=0;i<a;i++)
{
c=c^(1<<i);
}
cout<<c*((1<<a)-1);
cout<<"\n";
}
int main()
{
fast
ll t;
cin >> t;
while (t--)
{
infinity();
}
return 0;
}Interesting XOR! CodeChef Solution in C++14
#include<bits/stdc++.h>
// #include<ext/pb_ds/assoc_container.hpp>
// #include<ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace chrono;
// using namespace __gnu_pbds;
#define fastio() ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)
#define MOD 1000000007
#define MOD1 998244353
#define INF 1e18
#define nline "\n"
#define pb push_back
#define ppb pop_back
#define mp make_pair
#define ff first
#define ss second
#define PI 3.141592653589793238462
#define set_bits __builtin_popcountll
#define sz(x) ((int)(x).size())
#define all(x) (x).begin(), (x).end()
#define int long long
#ifndef ONLINE_JUDGE
#define debug(x) cerr << #x<<" "; _print(x); cerr << endl;
#else
#define debug(x);
#endif
// typedef long long int;
typedef unsigned long long ull;
typedef long double lld;
// typedef tree<pair<int, int>, null_type, less<pair<int, int>>, rb_tree_tag, tree_order_statistics_node_update > pbds; // find_by_order, order_of_key
void _print(int t) {cerr << t;}
// void _print(int t) {cerr << t;}
void _print(string t) {cerr << t;}
void _print(char t) {cerr << t;}
void _print(lld t) {cerr << t;}
void _print(double t) {cerr << t;}
void _print(ull t) {cerr << t;}
template <class T, class V> void _print(pair <T, V> p);
template <class T> void _print(vector <T> v);
template <class T> void _print(set <T> v);
template <class T, class V> void _print(map <T, V> v);
template <class T> void _print(multiset <T> v);
template <class T, class V> void _print(pair <T, V> p) {cerr << "{"; _print(p.ff); cerr << ","; _print(p.ss); cerr << "}";}
template <class T> void _print(vector <T> v) {cerr << "[ "; for (T i : v) {_print(i); cerr << " ";} cerr << "]";}
template <class T> void _print(set <T> v) {cerr << "[ "; for (T i : v) {_print(i); cerr << " ";} cerr << "]";}
template <class T> void _print(multiset <T> v) {cerr << "[ "; for (T i : v) {_print(i); cerr << " ";} cerr << "]";}
template <class T, class V> void _print(map <T, V> v) {cerr << "[ "; for (auto i : v) {_print(i); cerr << " ";} cerr << "]";}
// void _print(pbds v) {cerr << "[ "; for (auto i : v) {_print(i); cerr << " ";} cerr << "]";}
/*---------------------------------------------------------------------------------------------------------------------------*/
int gcd(int a, int b) {if (b > a) {return gcd(b, a);} if (b == 0) {return a;} return gcd(b, a % b);}
int expo(int a, int b, int mod) {int res = 1; while (b > 0) {if (b & 1)res = (res * a) % mod; a = (a * a) % mod; b = b >> 1;} return res;}
void extendgcd(int a, int b, int*v) {if (b == 0) {v[0] = 1; v[1] = 0; v[2] = a; return ;} extendgcd(b, a % b, v); int x = v[1]; v[1] = v[0] - v[1] * (a / b); v[0] = x; return;} //pass an arry of size1 3
int mminv(int a, int b) {int arr[3]; extendgcd(a, b, arr); return arr[0];} //for non prime b
int mminvprime(int a, int b) {return expo(a, b - 2, b);}
bool revsort(int a, int b) {return a > b;}
void swap(int &x, int &y) {int temp = x; x = y; y = temp;}
int combination(int n, int r, int m, int *fact, int *ifact) {int val1 = fact[n]; int val2 = ifact[n - r]; int val3 = ifact[r]; return (((val1 * val2) % m) * val3) % m;}
void google(int t) {cout << "Case #" << t << ": ";}
vector<int> sieve(int n) {int*arr = new int[n + 1](); vector<int> vect; for (int i = 2; i <= n; i++)if (arr[i] == 0) {vect.push_back(i); for (int j = 2 * i; j <= n; j += i)arr[j] = 1;} return vect;}
int mod_add(int a, int b, int m) {a = a % m; b = b % m; return (((a + b) % m) + m) % m;}
int mod_mul(int a, int b, int m) {a = a % m; b = b % m; return (((a * b) % m) + m) % m;}
int mod_sub(int a, int b, int m) {a = a % m; b = b % m; return (((a - b) % m) + m) % m;}
int mod_div(int a, int b, int m) {a = a % m; b = b % m; return (mod_mul(a, mminvprime(b, m), m) + m) % m;} //only for prime m
int phin(int n) {int number = n; if (n % 2 == 0) {number /= 2; while (n % 2 == 0) n /= 2;} for (int i = 3; i <= sqrt(n); i += 2) {if (n % i == 0) {while (n % i == 0)n /= i; number = (number / i * (i - 1));}} if (n > 1)number = (number / n * (n - 1)) ; return number;} //O(sqrt(N))
/*--------------------------------------------------------------------------------------------------------------------------*/
void test_case() {
int n;
cin>>n;
int num1=0;
int num2=0;
bool flag=true;
for(int j=31;j>=0;j--){
if(((n>>j)&1LL)==1LL){
if(flag){
num1+=(1LL<<j);
flag=false;
}else{
num2+=(1LL<<j);
}
}else{
if(flag){
continue;
}
num1+=(1LL<<j);
num2+=(1LL<<j);
}
}
debug(mp(num1,num2))
cout<<num1*num2<<nline;
}
signed main() {
#ifndef ONLINE_JUDGE
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
// freopen("error.txt","w",stderr);
#endif
fastio();
auto start1 = high_resolution_clock::now();
int t=1;
cin>>t;
while(t--){
test_case();
}
auto stop1 = high_resolution_clock::now();
auto duration = duration_cast<microseconds>(stop1 - start1);
#ifndef ONLINE_JUDGE
cerr << "Time: " << duration . count() / 1000 << endl;
#endif
}Interesting XOR! CodeChef Solution in PYTH 3
# cook your dish here
import math
# x=7
# y=math.log(x)//math.log(2)
# print(y)
t=int(input())
while(t):
t-=1
c=int(input())
n=int(math.log(c)/math.log(2))
n+=1
j=1
k=-1
a=0
b=0
for i in range(n):
if(c%2):
b+=j
k=j
else:
a+=j
b+=j
j*=2
c//=2
if(k!=-1):
b-=k
a+=k
print(a*b)Interesting XOR! CodeChef Solution in C
#include <stdio.h>
#include <math.h>
int main()
{
int s;
scanf("%d", &s);
while (s--)
{
long long int c, A, B=0;
scanf("%lld", &c);
long long int size = log2(c);
A=1<<size;
for(long long int i=size-1; i>=0; i--)
{
if((c&1<<i)!=0)
{
B=B|(1<<i);
}
else if((c&1<<i)==0)
{
A|=(1<<i);
B|=(1<<i);
}
}
printf("%lld\n", A*B);
}
return 0;
}Interesting XOR! CodeChef Solution in JAVA
/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
BufferedReader reader=new BufferedReader(new InputStreamReader(System.in));
BufferedWriter writer=new BufferedWriter(new OutputStreamWriter(System.out));
int tt=Integer.parseInt(reader.readLine().trim());
while(tt-->0){
int n=Integer.parseInt(reader.readLine().trim());
int fOne=0, sOne=0;
int f=0, s=0;
boolean oneIsSeen=false;
for(int i=30;i>=0;i--){
int x=1<<i;
if((x&n)!=0){
if(f!=0){
s|=x;
sOne++;
}else{
f|=x;
fOne++;
}
oneIsSeen=true;
}else if(oneIsSeen){
f|=x;
s|=x;
}
}
writer.write((f*1L*s)+"\n");
}
writer.flush();
}
private static int[] parseInt(String str) {
String[] parts=str.split("\\s+");
int[] ans=new int[parts.length];
for(int i=0;i<ans.length;i++){
ans[i]=Integer.parseInt(parts[i]);
}
return ans;
}
private static long[] parseLong(String str) {
String[] parts=str.split("\\s+");
long[] ans=new long[parts.length];
for(int i=0;i<ans.length;i++){
ans[i]=Long.parseLong(parts[i]);
}
return ans;
}
}Interesting XOR! CodeChef Solution in PYPY 3
def decimaltobinary(n):
s=''
while n:
if n&1:
s+='1'
else:
s+='0'
n>>=1
return s[::-1]
t=int(input())
while t>0:
t-=1
c=int(input())
a=''
b=''
converted=decimaltobinary(c)
index=0
for i in converted:
if i=='1':
if a=='' or int(a,2)<=int(b,2):
a+='1'
b+='0'
else:
a+='0'
b+='1'
else:
a+='1'
b+='1'
print(int(a,2)*int(b,2))
Interesting XOR! CodeChef Solution in PYTH
import math
# x=7
# y=math.log(x)//math.log(2)
# print(y)
t=int(input())
while(t):
t-=1
c=int(input())
n=int(math.log(c)/math.log(2))
n+=1
j=1
k=-1
a=0
b=0
for i in range(n):
if(c%2):
b+=j
k=j
else:
a+=j
b+=j
j*=2
c//=2
if(k!=-1):
b-=k
a+=k
print(a*b)Interesting XOR! CodeChef Solution in C#
using System;
public class Test
{
public static int countBits(long num) {
int count = 0;
while (num > 0) {
count++;
num >>= 1;
}
return count;
}
public static long interestingXOR(long C) {
int n = countBits(C);
long A = (1 << (n - 1)) - 1;
long B = C ^ A;
return A * B;
}
public static void Main()
{
// your code goes here
int T = int.Parse(Console.ReadLine());
while (T-- > 0) {
long C = long.Parse(Console.ReadLine());
Console.WriteLine(interestingXOR(C));
}
}
}Interesting XOR! CodeChef Solution in NODEJS
process.stdin.setEncoding('utf8');
//let INF = Infinity;
let input = '';
process.stdin.on('data', data => input += data);
process.stdin.on('end', ()=>{
input = input.split('\n');
let index = 0, result='',
t = Number(input[index++]);
while(t--)
{
let C = N = Number(input[index++]),
binaryA = 1;
while(N != 1)
{
binaryA <<= 1;
N >>= 1;
}
//console.log('A : '+ binaryA);
binaryA--;
let B = binaryA ^ C;
//console.log('A : '+ binaryA + ' B : '+ B);
if(C <= 100000)
C = binaryA * B;
else
C = BigIntMultiplication(binaryA, B);
result += C + '\n';
}
console.log(result);
});
function BigIntMultiplication(a, b)
{
//a = a.toString().split('');
b = b.toString().split('');
let bdigits = b.length,
resultTab = [],
n = '';
for(let i = bdigits - 1; i >= 0; i--)
{
resultTab[i] = (a * b[i]) + n;
n += '0';
}
resultTab = resultTab.reduce(BigIntSum);
return resultTab;
}
function BigIntSum(first, second)
{
first = first.split('').reverse(),
second = second.split('').reverse();
let firstDigits = first.length,
secondDigits = second.length,
sum = [],
inter = '';
if(secondDigits > firstDigits)
{
inter = first;
first = second;
second = first;
}
let retenu = 0;
for(let j = 0; j < secondDigits; j++)
{
let add = ((first[j] - 0) + (second[j] - 0) + retenu);
sum[j] = (add%10);
if(add >= 10)
retenu = 1;
else
retenu = 0;
}
for(let j = secondDigits; j < firstDigits; j++)
{
let add = ((first[j] - 0) + retenu);
sum[j] = (add%10) ;
if(add >= 10)
retenu = 1;
else
retenu = 0;
}
if(retenu)
sum.push(1);
sum = sum.reverse().join('');
return sum;
}Interesting XOR! CodeChef Solution in GO
package main
import (
"bufio"
"bytes"
"fmt"
"os"
)
func main() {
reader := bufio.NewReader(os.Stdin)
tc := readNum(reader)
var buf bytes.Buffer
for tc > 0 {
tc--
n := readNum(reader)
res := solve(n)
buf.WriteString(fmt.Sprintf("%d\n", res))
}
fmt.Print(buf.String())
}
func readUint64(bytes []byte, from int, val *uint64) int {
i := from
var tmp uint64
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + uint64(bytes[i]-'0')
i++
}
*val = tmp
return i
}
func readInt(bytes []byte, from int, val *int) int {
i := from
sign := 1
if bytes[i] == '-' {
sign = -1
i++
}
tmp := 0
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + int(bytes[i]-'0')
i++
}
*val = tmp * sign
return i
}
func readString(reader *bufio.Reader) string {
s, _ := reader.ReadString('\n')
for i := 0; i < len(s); i++ {
if s[i] == '\n' {
return s[:i]
}
}
return s
}
func readNum(reader *bufio.Reader) (a int) {
bs, _ := reader.ReadBytes('\n')
readInt(bs, 0, &a)
return
}
func readTwoNums(reader *bufio.Reader) (a int, b int) {
res := readNNums(reader, 2)
a, b = res[0], res[1]
return
}
func readThreeNums(reader *bufio.Reader) (a int, b int, c int) {
res := readNNums(reader, 3)
a, b, c = res[0], res[1], res[2]
return
}
func readNNums(reader *bufio.Reader, n int) []int {
res := make([]int, n)
x := 0
bs, _ := reader.ReadBytes('\n')
for i := 0; i < n; i++ {
for x < len(bs) && (bs[x] < '0' || bs[x] > '9') && bs[x] != '-' {
x++
}
x = readInt(bs, x, &res[i])
}
return res
}
func solve(c int) int64 {
// 2 ** d > C
// let A = 2 ** (d - 1)
// and B = C ^ A
C := int64(c)
var d uint64
for 1<<d <= C {
d++
}
var A, B int64
A = (1 << (d - 1)) - 1
B = C ^ A
return A * B
}Interesting XOR! CodeChef Solution Review:
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