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# Intersection of Two Arrays LeetCode Solution

## Problem – Intersection of Two Arrays

Given two integer arrays `nums1` and `nums2`, return an array of their intersection. Each element in the result must be unique and you may return the result in any order.

Example 1:

``````Input: nums1 = [1,2,2,1], nums2 = [2,2]
Output: ``````

Example 2:

``````Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4]
Output: [9,4]
Explanation: [4,9] is also accepted.``````

Constraints:

• `1 <= nums1.length, nums2.length <= 1000`
• `0 <= nums1[i], nums2[i] <= 1000`

### Intersection of Two Arrays LeetCode Solution in Java

``````public class Solution {
public int[] intersection(int[] nums1, int[] nums2) {
Set<Integer> set = new HashSet<>();
Set<Integer> intersect = new HashSet<>();
for (int i = 0; i < nums1.length; i++) {
}
for (int i = 0; i < nums2.length; i++) {
if (set.contains(nums2[i])) {
}
}
int[] result = new int[intersect.size()];
int i = 0;
for (Integer num : intersect) {
result[i++] = num;
}
return result;
}
}
``````

### Intersection of Two Arrays LeetCode Solution in C++

``````class Solution {
public:
vector<int> intersection(vector<int>& nums1, vector<int>& nums2) {
unordered_set<int> m(nums1.begin(), nums1.end());
vector<int> res;
for (auto a : nums2)
if (m.count(a)) {
res.push_back(a);
m.erase(a);
}
return res;
}
};
``````

### Intersection of Two Arrays LeetCode Solution in Python

``````class Solution(object):
def intersection(self, nums1, nums2):
"""
:type nums1: List[int]
:type nums2: List[int]
:rtype: List[int]
"""
return list(set(nums1) & set(nums2))
``````
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