itertools.combinations_with_replacement() Hacker Rank Solution

Problem: itertools.combinations_with_replacement() Hacker Rank Solution

This tool returns r length subsequences of elements from the input iterable allowing individual elements to be repeated more than once.

Combinations are emitted in lexicographic sorted order. So, if the input iterable is sorted, the combination tuples will be produced in sorted order.

Sample Code :

>>> from itertools import combinations_with_replacement
>>> 
>>> print list(combinations_with_replacement('12345',2))
[('1', '1'), ('1', '2'), ('1', '3'), ('1', '4'), ('1', '5'), ('2', '2'), ('2', '3'), ('2', '4'), ('2', '5'), ('3', '3'), ('3', '4'), ('3', '5'), ('4', '4'), ('4', '5'), ('5', '5')]
>>> 
>>> A = [1,1,3,3,3]
>>> print list(combinations(A,2))
[(1, 1), (1, 3), (1, 3), (1, 3), (1, 3), (1, 3), (1, 3), (3, 3), (3, 3), (3, 3)]

Task :

You are given a string S.
Your task is to print all possible size k replacement combinations of the string in lexicographic sorted order.

Input Format :

A single line containing the string S and integer value k separated by a space.

Constraints :

  • 0 < k <= len(s)
  • The string contains only UPPERCASE characters.

Output Format :

Print the combinations with their replacements of string S on separate lines.

Sample Input :

HACK 2

Sample Output :

AA
AC
AH
AK
CC
CH
CK
HH
HK
KK

itertools.combinations_with_replacement() Hacker Rank Solution in python 2

from itertools import combinations_with_replacement

S,k = raw_input().split()
k = int(k)

print '\n'.join(sorted(''.join(sorted(c)) for c in combinations_with_replacement(S,k)))

itertools.combinations_with_replacement() Hacker Rank Solution in python 3

# Enter your code here. Read input from STDIN. Print output to STDOUT
from itertools import combinations_with_replacement
s, n = input().split()
print(*[''.join(i) for i in combinations_with_replacement(sorted(s), int(n))], sep="\n")

itertools.combinations_with_replacement() Hacker Rank Solution in pypy

from itertools import combinations_with_replacement
source, combos = raw_input().split()
sstr = sorted(source)
for combo in combinations_with_replacement(sstr,int(combos)):
    print ''.join(combo)

itertools.combinations_with_replacement() Hacker Rank Solution in pypy 3

# Enter your code here. Read input from STDIN. Print output to STDOUT
from itertools import combinations_with_replacement
s,k = input().split()
print('\n'.join(map(''.join,combinations_with_replacement(sorted(s),int(k)))))
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