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# Janmansh at Fruit Market CodeChef Solution

## Problem – Janmansh at Fruit Market CodeChef Solution

Janmansh is at the fruit market to buy fruits for Chingari. There is an infinite supply of three different kinds of fruits with prices AB and C.

He needs to buy a total of X fruits having at least 2 different kinds of fruits. What is the least amount of money he can spend to buy fruits?

### Input Format

• The first line of the input contains a single integer T – the number of test cases. The description of T test cases follows.
• The first and only line of each test case contains four space separated integers XABC – the number of fruits to buy and the prices of the three different types of fruits respectively.

### Output Format

For each test case, output the least amount of money he can spend to buy fruits.

### Constraints

• 1 \le T \le 10^51≤T≤10^5
• 2≤X≤1000
• 1≤A,B,C≤100

### Sample 1:

``````Input:
2
2 1 1 1
3 4 3 2
Output:
2
7``````

### Explanation:

Test case-1: He can buy any two fruits of different kinds for a total price of 2.

Test case-2: He can buy 1 fruit of price 3 and 2 fruits of price 2 for a total price of 7.

## Janmansh at Fruit Market CodeChef Solution in C++14

``````#include <iostream>
#include<bits/stdc++.h>
using namespace std;

int main()
{
int t;cin>>t;
while(t--)
{
int x,a,b,c;
cin>>x>>a>>b>>c;
int d[3]={a,b,c};
sort(d,d+3);
cout<<d[0]*(x-1)+d[1]<<endl;
}
return 0;
}``````

## Janmansh at Fruit Market CodeChef Solution in Java

``````/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner in=new Scanner(System.in);
int te=in.nextInt();
while(te-->0){
int n=in.nextInt();
int ar[]=new int[3];
for(int i=0;i<3;i++)
ar[i]=in.nextInt();
Arrays.sort(ar);

int res=(n-1)*ar[0];
res+=ar[1];
System.out.println(res);
}
}}``````

## Janmansh at Fruit Market CodeChef Solution in Pyth 3

``````# cook your dish here
t=int(input())
for i in range(t):
x,a,b,c=map(int,input().split())
m=min((a+b),(b+c),(c+a))
m1=min(a,b,c)
print(m+(x-2)*m1)``````
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