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# Jump Game LeetCode Solution

## Problem – Jump Game

You are given an integer array `nums`. You are initially positioned at the array’s first index, and each element in the array represents your maximum jump length at that position.

Return `true` if you can reach the last index, or `false` otherwise.

Example 1:

``````Input: nums = [2,3,1,1,4]
Output: true
Explanation: Jump 1 step from index 0 to 1, then 3 steps to the last index.``````

Example 2:

``````Input: nums = [3,2,1,0,4]
Output: false
Explanation: You will always arrive at index 3 no matter what. Its maximum jump length is 0, which makes it impossible to reach the last index.``````

Constraints:

• `1 <= nums.length <= 104`
• `0 <= nums[i] <= 105`

### Jump Game LeetCode Solution in C++

``````bool canJump(int A[], int n) {
int i = 0;
for (int reach = 0; i < n && i <= reach; ++i)
reach = max(i + A[i], reach);
return i == n;
}
``````

### Jump Game LeetCode Solution in Python

``````def canJump(self, nums):
m = 0
for i, n in enumerate(nums):
if i > m:
return False
m = max(m, i+n)
return True``````

### Jump Game LeetCode Solution in Java

``````public boolean canJump(int[] A) {
int max = 0;
for(int i=0;i<A.length;i++){
if(i>max) {return false;}
max = Math.max(A[i]+i,max);
}
return true;
}
``````
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