Largest 3-Same-Digit Number in String LeetCode Solution

Problem – Largest 3-Same-Digit Number in String LeetCode Solution

You are given a string num representing a large integer. An integer is good if it meets the following conditions:

• It is a substring of num with length 3.
• It consists of only one unique digit.

Return the maximum good integer as a string or an empty string "" if no such integer exists.

Note:

• A substring is a contiguous sequence of characters within a string.
• There may be leading zeroes in num or a good integer.

Example 1:

Input: num = "6777133339"
Output: "777"
Explanation: There are two distinct good integers: "777" and "333".
"777" is the largest, so we return "777".

Example 2:

Input: num = "2300019"
Output: "000"
Explanation: "000" is the only good integer.

Example 3:

Input: num = "42352338"
Output: ""
Explanation: No substring of length 3 consists of only one unique digit. Therefore, there are no good integers.

Constraints:

• 3 <= num.length <= 1000
• num only consists of digits.

Largest 3-Same-Digit Number in String LeetCode Solution in Python

class Solution:
    def largestGoodInteger(self, n: str) -> str:
        return max(n[i-2:i+1] if n[i] == n[i - 1] == n[i - 2] else "" for i in range(2, len(n)))

Largest 3-Same-Digit Number in String LeetCode Solution in C++

string largestGoodInteger(string num) {
    char res = 0;
    for(int i = 2; i < num.size(); ++i)
        if (num[i] == num[i - 1] && num[i] == num[i - 2])
            res = max(res, num[i]);
    return res == 0 ? "" : string(3, res);
}

Largest 3-Same-Digit Number in String LeetCode Solution in Java

class Solution
{
    public String largestGoodInteger(String num)
    {
        String ans = "";
        for(int i = 2; i < num.length(); i++)
            if(num.charAt(i) == num.charAt(i-1) && num.charAt(i-1) == num.charAt(i-2))
                if(num.substring(i-2,i+1).compareTo(ans) > 0) // Check if the new one is larger
                    ans = num.substring(i-2,i+1);
        return ans;
    }
}

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