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Largest 3-Same-Digit Number in String LeetCode Solution

Problem – Largest 3-Same-Digit Number in String LeetCode Solution

You are given a string `num` representing a large integer. An integer is good if it meets the following conditions:

• It is a substring of `num` with length `3`.
• It consists of only one unique digit.

Return the maximum good integer as a string or an empty string `""` if no such integer exists.

Note:

• substring is a contiguous sequence of characters within a string.
• There may be leading zeroes in `num` or a good integer.

Example 1:

``````Input: num = "6777133339"
Output: "777"
Explanation: There are two distinct good integers: "777" and "333".
"777" is the largest, so we return "777".
``````

Example 2:

``````Input: num = "2300019"
Output: "000"
Explanation: "000" is the only good integer.
``````

Example 3:

``````Input: num = "42352338"
Output: ""
Explanation: No substring of length 3 consists of only one unique digit. Therefore, there are no good integers.
``````

Constraints:

• `3 <= num.length <= 1000`
• `num` only consists of digits.

Largest 3-Same-Digit Number in String LeetCode Solution in Python

``````class Solution:
def largestGoodInteger(self, n: str) -> str:
return max(n[i-2:i+1] if n[i] == n[i - 1] == n[i - 2] else "" for i in range(2, len(n)))
``````

Largest 3-Same-Digit Number in String LeetCode Solution in C++

``````string largestGoodInteger(string num) {
char res = 0;
for(int i = 2; i < num.size(); ++i)
if (num[i] == num[i - 1] && num[i] == num[i - 2])
res = max(res, num[i]);
return res == 0 ? "" : string(3, res);
}
``````

Largest 3-Same-Digit Number in String LeetCode Solution in Java

``````class Solution
{
public String largestGoodInteger(String num)
{
String ans = "";
for(int i = 2; i < num.length(); i++)
if(num.charAt(i) == num.charAt(i-1) && num.charAt(i-1) == num.charAt(i-2))
if(num.substring(i-2,i+1).compareTo(ans) > 0) // Check if the new one is larger
ans = num.substring(i-2,i+1);
return ans;
}
}
``````
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