Largest Number LeetCode Solution

Problem – Largest Number

Given a list of non-negative integers nums, arrange them such that they form the largest number and return it.

Since the result may be very large, so you need to return a string instead of an integer.

Example 1:

Input: nums = [10,2]
Output: "210"

Example 2:

Input: nums = [3,30,34,5,9]
Output: "9534330"


  • 1 <= nums.length <= 100
  • 0 <= nums[i] <= 109

Largest Number LeetCode Solution in Java

public class Solution {
     public String largestNumber(int[] num) {
		if(num == null || num.length == 0)
		    return "";
		// Convert int array to String array, so we can sort later on
		String[] s_num = new String[num.length];
		for(int i = 0; i < num.length; i++)
		    s_num[i] = String.valueOf(num[i]);
		// Comparator to decide which string should come first in concatenation
		Comparator<String> comp = new Comparator<String>(){
		    public int compare(String str1, String str2){
		        String s1 = str1 + str2;
				String s2 = str2 + str1;
				return s2.compareTo(s1); // reverse order here, so we can do append() later
		Arrays.sort(s_num, comp);
		// An extreme edge case by lc, say you have only a bunch of 0 in your int array
		if(s_num[0].charAt(0) == '0')
			return "0";
		StringBuilder sb = new StringBuilder();
		for(String s: s_num)
		return sb.toString();

Largest Number LeetCode Solution in C++

class Solution {
    string largestNumber(vector<int> &num) {
        vector<string> arr;
        for(auto i:num)
        sort(begin(arr), end(arr), [](string &s1, string &s2){ return s1+s2>s2+s1; });
        string res;
        for(auto s:arr)
        while(res[0]=='0' && res.length()>1)
        return  res;

Largest Number LeetCode Solution in Python

class Solution:
    # @param num, a list of integers
    # @return a string
    def largestNumber(self, num):
        num = [str(x) for x in num]
        num.sort(cmp=lambda x, y: cmp(y+x, x+y))
        return ''.join(num).lstrip('0') or '0'
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