Largest Palindromic Number LeetCode Solution

Problem – Largest Palindromic Number

You are given a string num consisting of digits only.

Return the largest palindromic integer (in the form of a string) that can be formed using digits taken from num. It should not contain leading zeroes.

Notes:

• You do not need to use all the digits of num, but you must use at least one digit.
• The digits can be reordered.

Example 1:

Input: num = "444947137"
Output: "7449447"
Explanation: 
Use the digits "4449477" from "444947137" to form the palindromic integer "7449447".
It can be shown that "7449447" is the largest palindromic integer that can be formed.

Example 2:

Input: num = "00009"
Output: "9"
Explanation: 
It can be shown that "9" is the largest palindromic integer that can be formed.
Note that the integer returned should not contain leading zeroes.

Constraints:

• 1 <= num.length <= 105
• num consists of digits.

Largest Palindromic Number LeetCode Solution in Python

    def largestPalindromic(self, num: str) -> str:
        count = Counter(num)
        res = ''.join(count[i] // 2 * i for i in '9876543210').lstrip('0')
        mid = max(count[i] % 2 * i for i in count)
        return (res + mid + res[::-1]) or '0'

Largest Palindromic Number LeetCode Solution in C++

class Solution {
public:
    string largestPalindromic(string num) {
        vector<int> cnt(10);
        for (char c: num) {
            cnt[c - '0']++;
        }
        
        string lp, rp; // left and right partition
        for (int i: num) {
            for (int j = 9; j >= 0; j--)  {
                if (cnt[j] > 1 && (j > 0 || lp.size())) {
                    lp += '0' + j;
                    rp += '0' + j;
                    cnt[j] -= 2;
                    break;
                }
            }
        }
        for (int i = 9; i >= 0; i--) {
            if (cnt[i]) {
                lp += '0' + i; break;
            }
        }
        reverse(begin(rp), end(rp));
        return lp + rp;
    }
};

Largest Palindromic Number LeetCode Solution in Java

class Solution {
    public String largestPalindromic(String num) {
        int[] n = new int[10];
        for (char c : num.toCharArray()) {
            n[c - '0']++;
        }
        boolean only = false;
		//seperate the result into 3 parts, the first half and second half, also the center (if exist)
        StringBuilder sbPre = new StringBuilder();
        StringBuilder sbPost = new StringBuilder();
        StringBuilder sbOnly = new StringBuilder();
		//check from 9 to 1, to make it the largest
        for (int i = 9; i >= 0; i--) {
		    //check for center
            if (n[i] % 2 != 0 && !only) {
                only = true;
                sbOnly.append(Integer.toString(i));
            }
			//handle special case of all '0' or '0' is the first digit(invalid) 
            if (i == 0 && sbPre.length() == 0) {
                if (n[i] > 0 && sbOnly.length() == 0) sbOnly.append(Integer.toString(i));
                return sbOnly.toString();
            }
            for (int j = 0; j < n[i] / 2; j++) {
                sbPre.append(Integer.toString(i));
                sbPost.insert(0, Integer.toString(i));
            }
        }
        sbPre.append(sbOnly);
        sbPre.append(sbPost);
        return sbPre.toString();
    }
}

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