Length of Last Word LeetCode Solution

Problem – Length of Last Word LeetCode Solution

Given a string s consisting of words and spaces, return the length of the last word in the string.

A word is a maximal substring consisting of non-space characters only.

Example 1:

Input: s = "Hello World"
Output: 5
Explanation: The last word is "World" with length 5.

Example 2:

Input: s = "   fly me   to   the moon  "
Output: 4
Explanation: The last word is "moon" with length 4.

Example 3:

Input: s = "luffy is still joyboy"
Output: 6
Explanation: The last word is "joyboy" with length 6.

Length of Last Word LeetCode Solution in C++

class Solution {
public:
    int lengthOfLastWord(string s) { 
        int len = 0, tail = s.length() - 1;
        while (tail >= 0 && s[tail] == ' ') tail--;
        while (tail >= 0 && s[tail] != ' ') {
            len++;
            tail--;
        }
        return len;
    }
};

Length of Last Word LeetCode Solution in Java

class Solution {
    public int lengthOfLastWord(String s) {
        int length = 0;
		
		// We are looking for the last word so let's go backward
        for (int i = s.length() - 1; i >= 0; i--) {
            if (s.charAt(i) != ' ') { // a letter is found so count
                length++;
            } else {  // it's a white space instead
				//  Did we already started to count a word ? Yes so we found the last word
                if (length > 0) return length;
            }
        }
        return length;
    }
}

Length of Last Word LeetCode Solution in Python

class Solution:
    def lengthOfLastWord(self, s):
        end = len(s) - 1
        while end > 0 and s[end] == " ": end -= 1
        beg = end
        while beg >= 0 and s[beg] != " ": beg -= 1
        return end - beg

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