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# Little Elephant and Divisors CodeChef Solution

## CodeChef Solution CodeChef Solution in C++17

``````
#include<bits/stdc++.h>
using namespace std;
#define all(arr) arr.begin(),arr.end()
#define rep(i,s,e) for(int i=s;i<e;i++)
#define lli long long int
#define ll long long
const ll INF=1e18;
const int mod=1e9+7;

int main(){
ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
int t;cin>>t;
while(t--){
int n;cin>>n;vector<int>arr(n);for(int i=0;i<n;i++){cin>>arr[i];}
int gg=arr[0];
for(int i=1;i<n;i++){
gg=__gcd(gg,arr[i]);
}
if(gg==1){
cout<<-1<<"\n";continue;
}int ans=gg;
for(int i=2;i*i<=gg;i++){
if(gg%i==0){
ans=i;break;
}
}cout<<ans<<"\n";
}
return 0;
}
``````

## Little Elephant and Divisors CodeChef Solution in C++14

``````#include<bits/stdc++.h>
using namespace std;
#define all(arr) arr.begin(),arr.end()
#define rep(i,s,e) for(int i=s;i<e;i++)
#define lli long long int
#define ll long long
const ll INF=1e18;
const int mod=1e9+7;

int main(){
ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
int t;cin>>t;
while(t--){
int n;cin>>n;vector<int>arr(n);for(int i=0;i<n;i++){cin>>arr[i];}
int gg=arr[0];
for(int i=1;i<n;i++){
gg=__gcd(gg,arr[i]);
}
if(gg==1){
cout<<-1<<"\n";continue;
}int ans=gg;
for(int i=2;i*i<=gg;i++){
if(gg%i==0){
ans=i;break;
}
}cout<<ans<<"\n";
}
return 0;
}``````

## Little Elephant and Divisors CodeChef Solution in PYTH 3

``````# cook your dish here
from math import gcd
from math import sqrt
from functools import reduce
t = int(input())
for _ in range(t):
n = int(input())
a = list(map(int,input().split()))
l = reduce(gcd,a)
if l>1:
mind = l
for i in range(2,int(sqrt(l))+1):
if l%i==0:
mind = i
break
print(mind)
else: print(-1)``````

## Little Elephant and Divisors CodeChef Solution in C

``````#include <stdio.h>
int gcd(int a, int b)
{
if(a < b)
{
int temp = a;
a=b;
b=temp;
}
if(b == 0)
{
return a;
}
else
{
gcd(b, a%b);
}
}
int main()
{
int t;

scanf("%d", &t);

while(t--)
{
int n, p;

scanf("%d", &n);

int a[n];

for(int i=0; i<n; i++)
{
scanf("%d", &a[i]);
}

p=a[0];

for(int i=1; i<n; i++)
{
p = gcd(a[i], p);
}

if(p == 1)
{
printf("-1\n");
continue;
}
int r=0;
for(int i=2; i*i<=p; i++)
{
if(p%i == 0)
{
r++;
printf("%d\n", i);
break;
}
}

if(r == 0)
{
printf("%d\n", p);
}
}
}``````

## Little Elephant and Divisors CodeChef Solution in JAVA

``````/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
static int gcd(int a, int b)
{
if (a == 0)
return b;
return gcd(b % a, a);
}
static int lcm(int a, int b)
{
return (a / gcd(a, b)) * b;
}
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int T = sc.nextInt();

while(T-->0){
int n = sc.nextInt();
int[] arr = new int[n];
int max  = 0;
for(int i=0;i<n ;i++){
arr[i]= sc.nextInt();
max=Integer.max(max,arr[i]);
}
int res = arr[0];
for(int i=1;i<n;i++){
res = gcd(arr[i],res);
}
int result = -1;
boolean found =false;
for(int i=2;i*i<=res;i++){

if(res%i==0){
result =i;
found=true;
break;
}

}
if(found){

System.out.println(result);
}else{
if(res<=1){
System.out.println(-1);
}else{

System.out.println(res);
}
}

}
}
}``````

## Little Elephant and Divisors CodeChef Solution in PYPY 3

``````from math import gcd,sqrt
from functools import reduce
for _ in range(int(input())):
n=int(input())
l1=list(map(int,input().split()))
a=reduce(gcd,l1)
if a==1:
print(-1)
else:
for i in range(2,int(sqrt(a))+1):
if a%i==0:
print(i)
break
else:
print(a)``````

## Little Elephant and Divisors CodeChef Solution in PYTH

``````N = 10**3 # value of N required
def primesieve(N):
n = N+1
sieve = [True] * (n/2)
for i in xrange(3,int(n**0.5)+1,2):
if sieve[i/2]:
sieve[i*i/2::i] = [False] * ((n-i*i-1)/(2*i)+1)
# endif
# endfor i
return [2] + [2*i+1 for i in xrange(1,n/2) if sieve[i]]
# end fun
primes = primesieve(N)
def gcd(n, m):
r = n % m
while r > 0:
n = m
m = r
r = n % m
#endwhile
return m
#end fun
t = int(raw_input())
for i in range(t):
N = int(raw_input())
st = raw_input().split()
g = int(st[0])
k = 1
while (k < N) and (g > 1):
n = int(st[k])
g = gcd(g,n)
k += 1
# endwhile
r = -1
if g > 1:
sq = int(g**0.5)
q = 0
p = primes[q]
while (p <= sq) and (g%p > 0):
q += 1
p = primes[q]
# endwhile
if g%p == 0:
r = p
else:
r = g
# endif
# endif
print r
# endfor i

``````

## Little Elephant and Divisors CodeChef Solution in C#

``````using System;

namespace CC_E_LittleElephantDivisors
{
class MainClass
{
public static void Main(string[] args)
{
int[] result = new int[terms];

for (int i = 0; i < terms; i++)
{
result[i] = array[0];

for (int j = 1; j < lenght; j++)
{
result[i] = GCD(result[i], array[j]);
}

if (result[i] == 1)
result[i] = -1;
else
{
for (int j = 2; j <= Math.Sqrt(result[i]); j++)
{
if (result[i] % j == 0)
{
result[i] = j;
break;
}
}
}
}

foreach (int divisor in result)
Console.WriteLine(divisor);

}

public static int GCD(int a, int b)
{
if (b == 0)
return a;
return GCD(b, a % b);
}
}
}``````

## Little Elephant and Divisors CodeChef Solution in NODEJS

``````var input = '';

function cacheInput(data) {
input += data;
}

function callMain() {
input = input.split(/\s+/).map(Number);
main();
}

var i = -1;
return function() {
return input[++i];
};
}();

function GCD(a, b) {
var r = a % b;
while (r != 0) {
a = b;
b = r;
r = a % b;
}
return b;
}

function smallestPrimeFactor(number) {
for (var s = 2; s * s <= number; ++s) {
if (number % s == 0) {
return s;
}
}
return number;
}

function main() {
var output = '';
var smallestPrimes = new Array(100001);
for (var i = 0; i < 100001; ++i) {
smallestPrimes[i] = smallestPrimeFactor(i);
}
for (var t = 0; t < T; ++t) {
for (var i = 1; i < N; ++i) {
}
if (gcd == 1) {
output += '-1\n';
}
else {
output += smallestPrimes[gcd] + '\n';
}
}
process.stdout.write(output);
process.exit();
}

process.stdin.resume();
process.stdin.setEncoding('utf8');
process.stdin.on('data', cacheInput).on('end', callMain);``````
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