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# Longest Nice Subarray LeetCode Solution

## Problem – Longest Nice Subarray LeetCode Solution

You are given an array `nums` consisting of positive integers.

We call a subarray of `nums` nice if the bitwise AND of every pair of elements that are in different positions in the subarray is equal to `0`.

Return the length of the longest nice subarray.

subarray is a contiguous part of an array.

Note that subarrays of length `1` are always considered nice.

Example 1:

``````Input: nums = [1,3,8,48,10]
Output: 3
Explanation: The longest nice subarray is [3,8,48]. This subarray satisfies the conditions:
- 3 AND 8 = 0.
- 3 AND 48 = 0.
- 8 AND 48 = 0.
It can be proven that no longer nice subarray can be obtained, so we return 3.``````

Example 2:

``````Input: nums = [3,1,5,11,13]
Output: 1
Explanation: The length of the longest nice subarray is 1. Any subarray of length 1 can be chosen.
``````

Constraints:

• `1 <= nums.length <= 105`
• `1 <= nums[i] <= 109`

## Longest Nice Subarray LeetCode Solution in Java

``````    public int longestNiceSubarray(int[] A) {
int AND = 0, i = 0, res = 0, n = A.length;
for (int j = 0; j < n; ++j) {
while ((AND & A[j]) > 0)
AND ^= A[i++];
AND |= A[j];
res = Math.max(res, j - i + 1);
}
return res;
}
``````

## Longest Nice Subarray LeetCode Solution in C++

``````    int longestNiceSubarray(vector<int>& A) {
int AND = 0, i = 0, res = 0, n = A.size();
for (int j = 0; j < n; ++j) {
while ((AND & A[j]) > 0)
AND ^= A[i++];
AND |= A[j];
res = max(res, j - i + 1);
}
return res;
}``````

## Longest Nice Subarray LeetCode Solution in Python

``````    def longestNiceSubarray(self, A):
res = AND = i = 0
for j in range(len(A)):
while AND & A[j]:
AND ^= A[i]
i += 1
AND |= A[j]
res = max(res, j - i + 1)
return res``````
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