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You are given an integer array `nums`

of length `n`

, and an integer array `queries`

of length `m`

.

Return *an array *`answer`

* of length *`m`

* where *`answer[i]`

* is the maximum size of a subsequence that you can take from *

`nums`

`queries[i]`

.A **subsequence** is an array that can be derived from another array by deleting some or no elements without changing the order of the remaining elements.

**Example 1:**

**Input**: nums = [4,5,2,1], queries = [3,10,21]
**Output**: [2,3,4]
**Explanation**: We answer the queries as follows:
- The subsequence [2,1] has a sum less than or equal to 3. It can be proven that 2 is the maximum size of such a subsequence, so answer[0] = 2.
- The subsequence [4,5,1] has a sum less than or equal to 10. It can be proven that 3 is the maximum size of such a subsequence, so answer[1] = 3.
- The subsequence [4,5,2,1] has a sum less than or equal to 21. It can be proven that 4 is the maximum size of such a subsequence, so answer[2] = 4.

**Example 2:**

**Input**: nums = [2,3,4,5], queries = [1]
**Output**: [0]
**Explanation**: The empty subsequence is the only subsequence that has a sum less than or equal to 1, so answer[0] = 0.

**Constraints:**

`n == nums.length`

`m == queries.length`

`1 <= n, m <= 1000`

`1 <= nums[i], queries[i] <= 10`

^{6}

```
public int[] answerQueries(int[] nums, int[] queries) {
Arrays.sort(nums);
Arrays.parallelPrefix(nums, Integer::sum);
for (int i = 0; i < queries.length; ++i) {
int pos = Arrays.binarySearch(nums, queries[i] + 1);
queries[i] = pos < 0 ? ~pos : pos;
}
return queries;
}
```

```
vector<int> answerQueries(vector<int>& nums, vector<int>& queries) {
sort(begin(nums), end(nums));
partial_sum(begin(nums), end(nums), begin(nums));
transform(begin(queries), end(queries), begin(queries), [&](int q){
return upper_bound(begin(nums), end(nums), q) - begin(nums);
});
return queries;
}
```

```
class Solution:
def answerQueries(self, nums: List[int], queries: List[int]) -> List[int]:
numsSorted = sorted(nums)
res = []
for q in queries:
total = 0
count = 0
for num in numsSorted:
total += num
count += 1
if total > q:
count -= 1
break
res.append(count)
return res
```

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