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# Lucky Four CodeChef Solution

## Problem – Lucky Four CodeChef Solution

Karan likes the number 4 very much.

Impressed by the power of this number, Karan has begun to look for occurrences of four anywhere. He has a list of T integers, for each of them he wants to calculate the number of occurrences of the digit 4 in the decimal representation. He is too busy now, so please help him.

### Input

The first line of input consists of a single integer T, denoting the number of integers in Karan’s list.

Then, there are T lines, each of them contain a single integer from the list.

### Output

Output T lines. Each of these lines should contain the number of occurrences of the digit 4 in the respective integer from Karan’s list.

### Constraints

• 1 ≤ T ≤ 10^5
• (Subtask 1): 0 ≤ Numbers from the list ≤ 9 – 33 points.
• (Subtask 2): 0 ≤ Numbers from the list ≤ 109 – 67 points.

### Example

``````Input:
5
447474
228
6664
40
81
Output:
4
0
1
1
0
``````

## Lucky Four CodeChef Solution in Pyth 3

``````# cook your dish here
t = int(input())
for i in range(t):
count = 0
num = str(input())
for x in num:
if(x == "4"):
count += 1
print(count)``````

## Lucky Four CodeChef Solution in C++14

``````#include <iostream>
using namespace std;

int main() {

int t; cin>>t;
while(t--)
{
int cnt=0, n; cin>>n;
while(n>0)
{
int r = n%10;
if(r==4) cnt++;
n/=10;
}

cout<<cnt<<endl;
}

return 0;
}
``````

## Lucky Four CodeChef Solution in Java

``````/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
for(int i=1;i<=n;i++)
{
int sum=0;
String s=sc.next();
for(int j=0;j<s.length();j++)
{
if(s.charAt(j)=='4')
sum++;
else
continue;
}
System.out.println(sum);
}
}
}
``````
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