Lucky Four CodeChef Solution

Problem – Lucky Four CodeChef Solution

Karan likes the number 4 very much.

Impressed by the power of this number, Karan has begun to look for occurrences of four anywhere. He has a list of T integers, for each of them he wants to calculate the number of occurrences of the digit 4 in the decimal representation. He is too busy now, so please help him.

Input

The first line of input consists of a single integer T, denoting the number of integers in Karan’s list.

Then, there are T lines, each of them contain a single integer from the list.

Output

Output T lines. Each of these lines should contain the number of occurrences of the digit 4 in the respective integer from Karan’s list.

Constraints

• 1 ≤ T ≤ 10^5
• (Subtask 1): 0 ≤ Numbers from the list ≤ 9 – 33 points.
• (Subtask 2): 0 ≤ Numbers from the list ≤ 10⁹ – 67 points.

Example

Input:
5
447474
228
6664
40
81
Output:
4
0
1
1
0

Lucky Four CodeChef Solution in Pyth 3

# cook your dish here
t = int(input())
for i in range(t):
    count = 0
    num = str(input())
    for x in num:
        if(x == "4"):
            count += 1
    print(count)

Lucky Four CodeChef Solution in C++14

#include <iostream>
using namespace std;

int main() {
	
	int t; cin>>t;
	while(t--)
	{
	    int cnt=0, n; cin>>n; 
	    while(n>0)
	    {
	        int r = n%10;
	        if(r==4) cnt++;
	        n/=10;
	    }
	    
	    cout<<cnt<<endl;
	}
	
	
	return 0;
}

Lucky Four CodeChef Solution in Java

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		// your code goes here
		 Scanner sc=new Scanner(System.in);
       int n=sc.nextInt();
       for(int i=1;i<=n;i++)
       {
           int sum=0;
         String s=sc.next();
         for(int j=0;j<s.length();j++)
         {
             if(s.charAt(j)=='4')
             sum++;
             else
             continue;
         }
         System.out.println(sum);
       }
	}
}

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