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# Make all equal using Pairs CodeChef Solution

## Problem – Make all equal using Pairs CodeChef Solution

Chef has an array A of length N.

In one operation, Chef can choose any two distinct indices i,j (1≤i,jN,i=j) and either change Ai​ to Aj​ or change Aj​ to Ai​.

Find the minimum number of operations required to make all the elements of the array equal.

### Input Format

• First line will contain T, number of test cases. Then the test cases follow.
• First line of each test case consists of an integer N – denoting the size of array A.
• Second line of each test case consists of N space-separated integers A1​,A2​,…,AN​ – denoting the array A.

### Output Format

For each test case, output the minimum number of operations required to make all the elements equal.

• 1≤T≤100
• 2≤N≤1000
• 1≤Ai​≤1000

Input:
4
3
1 2 3
4
5 5 5 5
4
2 2 1 1
3
1 1 2
Output:
2
0
2
1

### Explanation:

Test Case 1: You can make all the elements equal in 2 operations. In the first operation, you can choose indices 1,2 and convert A1​ to A2​. So the array becomes [2,2,3]. Now you can choose indices 1,3 and convert A3​ to A1​, so the final array becomes [2,2,2].

Test Case 2: Since all the elements are already equal there is no need to perform any operation.

Test Case 3: You can make all the elements equal in 2 operations. In the first operation, you can choose indices 1,3 and convert A1​ to A3​. So the array becomes [1,2,1,1]. Now you can choose indices 1,2 and convert A2​ to A1​, so the final array becomes [1,1,1,1].

Test Case 4: You can make all the elements equal in 1 operation. You can pick indices 2,3 and convert A3​ to A2​ after which the array becomes [1,1,1].

## Make all equal using Pairs CodeChef Solution in Java

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc=new  Scanner(System.in);
int t=sc.nextInt();
while(t-->0){
int n =sc.nextInt();
int arr[]=new int[n];
for(int i=0;i<n;i++){
arr[i]=sc.nextInt();
}
int count=0;
for(int i=0;i<n;i++){
int a=0;
for(int j=0;j<n;j++){
if(arr[i]==arr[j])
a++;

}
count=Math.max(a,count);
}
System.out.println(n-count);

}
}
}

## Make all equal using Pairs CodeChef Solution in C++17

#include <iostream>
using namespace std;

int main() {
int T;
std::cin >> T;
while(T--){
int N;
cin>>N;
int A[N];
for( int i=0; i<N; i++){
cin>>A[i];
}
int min=0,count=0;
for(int i=0; i<N; i++){
int count=0;
for(int j=i; j<N; j++){
if(A[i]==A[j]){
count++;
}
if(min<count){
min=count;
}
}
}
std::cout << (N-min) << std::endl;
}
return 0;
}

## Make all equal using Pairs CodeChef Solution in Pyth 3

for _ in range(int(input())):
n=int(input());
arr = list(map(int,input().split()));
count=0;
for i in arr:
if arr.count(i)>count:
count = arr.count(i)
print(n-count)
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