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# Make Array Zero by Subtracting Equal Amounts LeetCode Solution

## Problem – Make Array Zero by Subtracting Equal Amounts LeetCode Solution

You are given a non-negative integer array `nums`. In one operation, you must:

• Choose a positive integer `x` such that `x` is less than or equal to the smallest non-zero element in `nums`.
• Subtract `x` from every positive element in `nums`.

Return the minimum number of operations to make every element in `nums` equal to `0`.

Example 1:

``````Input: nums = [1,5,0,3,5]
Output: 3
Explanation:
In the first operation, choose x = 1. Now, nums = [0,4,0,2,4].
In the second operation, choose x = 2. Now, nums = [0,2,0,0,2].
In the third operation, choose x = 2. Now, nums = [0,0,0,0,0].``````

Example 2:

``````Input: nums = 
Output: 0
Explanation: Each element in nums is already 0 so no operations are needed.``````

Constraints:

• `1 <= nums.length <= 100`
• `0 <= nums[i] <= 100`

### Make Array Zero by Subtracting Equal Amounts LeetCode Solution in Java

``````    public int minimumOperations(int[] nums) {
Set<Integer> set = new HashSet<>();
for (int a: nums)
if (a > 0)
return set.size();
}
``````

### Make Array Zero by Subtracting Equal Amounts LeetCode Solution in C++

``````    int minimumOperations(vector<int>& A) {
unordered_set<int> s = unordered_set(A.begin(), A.end());
return s.size() - s.count(0);
}
``````

### Make Array Zero by Subtracting Equal Amounts LeetCode Solution in Python

``````    def minimumOperations(self, nums):
return len(set(x for x in nums if x > 0))
``````
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