Make Array Zero by Subtracting Equal Amounts LeetCode Solution

Problem – Make Array Zero by Subtracting Equal Amounts LeetCode Solution

You are given a non-negative integer array nums. In one operation, you must:

  • Choose a positive integer x such that x is less than or equal to the smallest non-zero element in nums.
  • Subtract x from every positive element in nums.

Return the minimum number of operations to make every element in nums equal to 0.

Example 1:

Input: nums = [1,5,0,3,5]
Output: 3
Explanation:
In the first operation, choose x = 1. Now, nums = [0,4,0,2,4].
In the second operation, choose x = 2. Now, nums = [0,2,0,0,2].
In the third operation, choose x = 2. Now, nums = [0,0,0,0,0].

Example 2:

Input: nums = [0]
Output: 0
Explanation: Each element in nums is already 0 so no operations are needed.

Constraints:

  • 1 <= nums.length <= 100
  • 0 <= nums[i] <= 100

Make Array Zero by Subtracting Equal Amounts LeetCode Solution in Java

    public int minimumOperations(int[] nums) {
        Set<Integer> set = new HashSet<>();
        for (int a: nums)
            if (a > 0)
                set.add(a);
        return set.size();
    }

Make Array Zero by Subtracting Equal Amounts LeetCode Solution in C++

    int minimumOperations(vector<int>& A) {
        unordered_set<int> s = unordered_set(A.begin(), A.end());
        return s.size() - s.count(0);
    }

Make Array Zero by Subtracting Equal Amounts LeetCode Solution in Python

    def minimumOperations(self, nums):
        return len(set(x for x in nums if x > 0))
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