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Let’s learn some new Python concepts! You have to generate a list of the first N fibonacci numbers, 0 being the first number. Then, apply the map function and a lambda expression to cube each fibonacci number and print the list.

**Concept**The map() function applies a function to every member of an iterable and returns the result. It takes two parameters: first, the function that is to be applied and secondly, the iterables.

Let’s say you are given a list of names, and you have to print a list that contains the length of each name.

`>> `**print** (list(map(len, ['Tina', 'Raj', 'Tom'])))
[**4**, **3**, **3**]

Lambda is a single expression anonymous function often used as an inline function. In simple words, it is a function that has only one line in its body. It proves very handy in functional and GUI programming.

`>> sum = `**lambda** a, b, c: a + b + c
>> sum(**1**, **2**, **3**)
**6**

**Note :**Lambda functions cannot use the return statement and can only have a single expression. Unlike def, which creates a function and assigns it a name, lambda creates a function and returns the function itself. Lambda can be used inside lists and dictionaries.

One line of input: an integer N.

- 0 <= N <= 15

A list on a single line containing the cubes of the first N fibonacci numbers.

**5**

`[`**0**, **1**, **1**, **8**, **27**]

The first 5 fibonacci numbers are [0, 1, 1, 2, 3] , and their cubes are [0, 1, 1, 8, 27].

```
# Enter your code here. Read input from STDIN. Print output to STDOUT
def fib(n):
if n == 0:
return 0
if n == 1:
return 1
return fib(n-2) + fib(n-1)
n = int(raw_input())
cube = lambda x: x*x*x
print list(map(cube,[fib(a) for a in xrange(n)]))
```

```
cube = lambda x: pow(x,3)# complete the lambda function
def fibonacci(n):
# return a list of fibonacci numbers
lis = [0,1]
for i in range(2,n):
lis.append(lis[i-2] + lis[i-1])
return(lis[0:n])
```

```
cube = lambda x: x**3
def fibonacci(n):
# return a list of fibonacci numbers
result = [0,1]
for i in range(2,n):
result.append(result[i-1]+result[i-2])
return result[:n]
```

```
cube = lambda x: pow(x,3)# complete the lambda function
def fibonacci(n):
# return a list of fibonacci numbers
lis = [0,1]
for i in range(2,n):
lis.append(lis[i-2] + lis[i-1])
return(lis[0:n])
```

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