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# Map and Lambda Function Hacker Rank Solution – Queslers

## Problem : Map and Lambda Function Hacker Rank Solution

Let’s learn some new Python concepts! You have to generate a list of the first N fibonacci numbers, 0 being the first number. Then, apply the map function and a lambda expression to cube each fibonacci number and print the list.

ConceptThe map() function applies a function to every member of an iterable and returns the result. It takes two parameters: first, the function that is to be applied and secondly, the iterables.
Let’s say you are given a list of names, and you have to print a list that contains the length of each name.

``````>> print (list(map(len, ['Tina', 'Raj', 'Tom'])))
[4, 3, 3]
``````

Lambda is a single expression anonymous function often used as an inline function. In simple words, it is a function that has only one line in its body. It proves very handy in functional and GUI programming.

``````>> sum = lambda a, b, c: a + b + c
>> sum(1, 2, 3)
6
``````

Note :Lambda functions cannot use the return statement and can only have a single expression. Unlike def, which creates a function and assigns it a name, lambda creates a function and returns the function itself. Lambda can be used inside lists and dictionaries.

#### Input Format :

One line of input: an integer N.

• 0 <= N <= 15

#### Output Format :

A list on a single line containing the cubes of the first N fibonacci numbers.

#### Sample Input :

``````5
``````

#### Sample Output :

``````[0, 1, 1, 8, 27]
``````

#### Explanation :

The first 5 fibonacci numbers are [0, 1, 1, 2, 3] , and their cubes are [0, 1, 1, 8, 27].

### Map and Lambda Function Hacker Rank Solution in python 2

``````# Enter your code here. Read input from STDIN. Print output to STDOUT
def fib(n):
if n == 0:
return 0
if n == 1:
return 1
return fib(n-2) + fib(n-1)
n = int(raw_input())
cube = lambda x: x*x*x
print list(map(cube,[fib(a) for a in xrange(n)]))``````

### Map and Lambda Function Hacker Rank Solution in python 3

``````cube = lambda x: pow(x,3)# complete the lambda function
def fibonacci(n):
# return a list of fibonacci numbers
lis = [0,1]
for i in range(2,n):
lis.append(lis[i-2] + lis[i-1])
return(lis[0:n])``````

### Map and Lambda Function Hacker Rank Solution in pypy

``````cube = lambda x: x**3

def fibonacci(n):
# return a list of fibonacci numbers
result = [0,1]
for i in range(2,n):
result.append(result[i-1]+result[i-2])

return result[:n]
``````

### Map and Lambda Function Hacker Rank Solution in pypy 3

``````cube = lambda x: pow(x,3)# complete the lambda function

def fibonacci(n):
# return a list of fibonacci numbers
lis = [0,1]

for i in range(2,n):
lis.append(lis[i-2] + lis[i-1])

return(lis[0:n])
``````
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