Max Consecutive Ones LeetCode Solution

Problem – Max Consecutive Ones LeetCode Solution

Given a binary array nums, return the maximum number of consecutive 1‘s in the array.

Example 1:

Input: nums = [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.

Example 2:

Input: nums = [1,0,1,1,0,1]
Output: 2

Constraints:

• 1 <= nums.length <= 105
• nums[i] is either 0 or 1.

Max Consecutive Ones LeetCode Solution in Java

    public int findMaxConsecutiveOnes(int[] nums) {
        int maxHere = 0, max = 0;
        for (int n : nums)
            max = Math.max(max, maxHere = n == 0 ? 0 : maxHere + 1);
        return max; 
    } 

Max Consecutive Ones LeetCode Solution in Python

class Solution(object):
    def findMaxConsecutiveOnes(self, nums):
        cnt = 0
        ans = 0
        for num in nums:
            if num == 1:
                cnt += 1
                ans = max(ans, cnt)
            else:
                cnt = 0
        return ans

Max Consecutive Ones LeetCode Solution in C++

    int findMaxConsecutiveOnes(vector<int>& nums) {
        int max_cnt = 0, cnt = 0;
        for (auto n : nums) {
            if (n == 1) max_cnt = max(++cnt, max_cnt);
            else cnt = 0;
        }
        return max_cnt;
    }

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