Max Points on a Line LeetCode Solution

Problem – Max Points on a Line

Given an array of points where points[i] = [xi, yi] represents a point on the X-Y plane, return the maximum number of points that lie on the same straight line.

Example 1:

Input: points = [[1,1],[2,2],[3,3]]
Output: 3

Example 2:

Input: points = [[1,1],[3,2],[5,3],[4,1],[2,3],[1,4]]
Output: 4


  • 1 <= points.length <= 300
  • points[i].length == 2
  • -104 <= xi, yi <= 104
  • All the points are unique.

Max Points on a Line LeetCode Solution in Java

    public class Solution{
        public int maxPoints(Point[] points) {
        	if (points==null) return 0;
        	if (points.length<=2) return points.length;
        	Map<Integer,Map<Integer,Integer>> map = new HashMap<Integer,Map<Integer,Integer>>();
        	int result=0;
        	for (int i=0;i<points.length;i++){ 
        		int overlap=0,max=0;
        		for (int j=i+1;j<points.length;j++){
        			int x=points[j].x-points[i].x;
        			int y=points[j].y-points[i].y;
        			if (x==0&&y==0){
        			int gcd=generateGCD(x,y);
        			if (gcd!=0){
        			if (map.containsKey(x)){
        				if (map.get(x).containsKey(y)){
        					map.get(x).put(y, map.get(x).get(y)+1);
        					map.get(x).put(y, 1);
        				Map<Integer,Integer> m = new HashMap<Integer,Integer>();
        				m.put(y, 1);
        				map.put(x, m);
        			max=Math.max(max, map.get(x).get(y));
        		result=Math.max(result, max+overlap+1);
        	return result;
        private int generateGCD(int a,int b){
        	if (b==0) return a;
        	else return generateGCD(b,a%b);

Max Points on a Line LeetCode Solution in C++

int maxPoints(vector<Point> &points) {
    int result = 0;
    for(int i = 0; i < points.size(); i++){
        int samePoint = 1;
        unordered_map<double, int> map;
        for(int j = i + 1; j < points.size(); j++){
            if(points[i].x == points[j].x && points[i].y == points[j].y){
            else if(points[i].x == points[j].x){
                double slope = double(points[i].y - points[j].y) / double(points[i].x - points[j].x);
        int localMax = 0;
        for(auto it = map.begin(); it != map.end(); it++){
            localMax = max(localMax, it->second);
        localMax += samePoint;
        result = max(result, localMax);
    return result;

Max Points on a Line LeetCode Solution in Python

    def maxPoints(self, points):
        l = len(points)
        m = 0
        for i in range(l):
            dic = {'i': 1}
            same = 0
            for j in range(i+1, l):
                tx, ty = points[j].x, points[j].y
                if tx == points[i].x and ty == points[i].y: 
                    same += 1
                if points[i].x == tx: slope = 'i'
                else:slope = (points[i].y-ty) * 1.0 /(points[i].x-tx)
                if slope not in dic: dic[slope] = 1
                dic[slope] += 1
            m = max(m, max(dic.values()) + same)
    return m
Max Points on a Line LeetCode Solution Review:

In our experience, we suggest you solve this Max Points on a Line LeetCode Solution and gain some new skills from Professionals completely free and we assure you will be worth it.

If you are stuck anywhere between any coding problem, just visit Queslers to get the Max Points on a Line LeetCode Solution

Find on LeetCode


I hope this Max Points on a Line LeetCode Solution would be useful for you to learn something new from this problem. If it helped you then don’t forget to bookmark our site for more Coding Solutions.

This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.

Keep Learning!

More Coding Solutions >>

LeetCode Solutions

Hacker Rank Solutions

CodeChef Solutions

Leave a Reply

Your email address will not be published.