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# Max Points on a Line LeetCode Solution

## Problem – Max Points on a Line

Given an array of `points` where `points[i] = [xi, yi]` represents a point on the X-Y plane, return the maximum number of points that lie on the same straight line.

Example 1:

``````Input: points = [[1,1],[2,2],[3,3]]
Output: 3``````

Example 2:

``````Input: points = [[1,1],[3,2],[5,3],[4,1],[2,3],[1,4]]
Output: 4``````

Constraints:

• `1 <= points.length <= 300`
• `points[i].length == 2`
• `-104 <= xi, yi <= 104`
• All the `points` are unique.

### Max Points on a Line LeetCode Solution in Java

``````    public class Solution{
public int maxPoints(Point[] points) {
if (points==null) return 0;
if (points.length<=2) return points.length;

Map<Integer,Map<Integer,Integer>> map = new HashMap<Integer,Map<Integer,Integer>>();
int result=0;
for (int i=0;i<points.length;i++){
map.clear();
int overlap=0,max=0;
for (int j=i+1;j<points.length;j++){
int x=points[j].x-points[i].x;
int y=points[j].y-points[i].y;
if (x==0&&y==0){
overlap++;
continue;
}
int gcd=generateGCD(x,y);
if (gcd!=0){
x/=gcd;
y/=gcd;
}

if (map.containsKey(x)){
if (map.get(x).containsKey(y)){
map.get(x).put(y, map.get(x).get(y)+1);
}else{
map.get(x).put(y, 1);
}
}else{
Map<Integer,Integer> m = new HashMap<Integer,Integer>();
m.put(y, 1);
map.put(x, m);
}
max=Math.max(max, map.get(x).get(y));
}
result=Math.max(result, max+overlap+1);
}
return result;

}
private int generateGCD(int a,int b){

if (b==0) return a;
else return generateGCD(b,a%b);

}
}
``````

### Max Points on a Line LeetCode Solution in C++

``````int maxPoints(vector<Point> &points) {
int result = 0;
for(int i = 0; i < points.size(); i++){
int samePoint = 1;
unordered_map<double, int> map;
for(int j = i + 1; j < points.size(); j++){
if(points[i].x == points[j].x && points[i].y == points[j].y){
samePoint++;
}
else if(points[i].x == points[j].x){
map[INT_MAX]++;
}
else{
double slope = double(points[i].y - points[j].y) / double(points[i].x - points[j].x);
map[slope]++;
}
}
int localMax = 0;
for(auto it = map.begin(); it != map.end(); it++){
localMax = max(localMax, it->second);
}
localMax += samePoint;
result = max(result, localMax);
}
return result;
}
``````

### Max Points on a Line LeetCode Solution in Python

``````    def maxPoints(self, points):
l = len(points)
m = 0
for i in range(l):
dic = {'i': 1}
same = 0
for j in range(i+1, l):
tx, ty = points[j].x, points[j].y
if tx == points[i].x and ty == points[i].y:
same += 1
continue
if points[i].x == tx: slope = 'i'
else:slope = (points[i].y-ty) * 1.0 /(points[i].x-tx)
if slope not in dic: dic[slope] = 1
dic[slope] += 1
m = max(m, max(dic.values()) + same)
return m
``````
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