Max Sum of a Pair With Equal Sum of Digits LeetCode Solution

Problem – Max Sum of a Pair With Equal Sum of Digits LeetCode Solution

You are given a 0-indexed array nums consisting of positive integers. You can choose two indices i and j, such that i != j, and the sum of digits of the number nums[i] is equal to that of nums[j].

Return the maximum value of nums[i] + nums[j] that you can obtain over all possible indices i and j that satisfy the conditions.

Example 1:

Input: nums = [18,43,36,13,7]
Output: 54
Explanation: The pairs (i, j) that satisfy the conditions are:
- (0, 2), both numbers have a sum of digits equal to 9, and their sum is 18 + 36 = 54.
- (1, 4), both numbers have a sum of digits equal to 7, and their sum is 43 + 7 = 50.
So the maximum sum that we can obtain is 54.

Example 2:

Input: nums = [10,12,19,14]
Output: -1
Explanation: There are no two numbers that satisfy the conditions, so we return -1.

Constraints:

  • 1 <= nums.length <= 105
  • 1 <= nums[i] <= 109

Max Sum of a Pair With Equal Sum of Digits LeetCode Solution in C++

int maximumSum(vector<int>& nums) {
    int res = -1, d_n[82] = {}; // 9 * 9
    for (int n : nums) {
        int d = 0;
        for (int nn = n; nn; nn /= 10)
            d += nn % 10;
        if (d_n[d])
            res = max(res, d_n[d] + n);
        d_n[d] = max(d_n[d], n);
    }
    return res;
}

Max Sum of a Pair With Equal Sum of Digits LeetCode Solution in Java

class Solution {
    public int maximumSum(int[] nums) {
        HashMap<Integer, Integer> map = new HashMap<>();
        int result = -1;

        for (int item : nums) {
            int key = getNumberTotal(item);

            if (!map.containsKey(key))
                map.put(key, item);
            else {
                result = Math.max(result, map.get(key) + item);
                map.put(key, Math.max(map.get(key), item));
            }
        }

        return result;
    }

    int getNumberTotal(int num) {
        int result = 0;
        while (num > 0) {
            result += num % 10;
            num /= 10;
        }

        return result;
    }
}

Max Sum of a Pair With Equal Sum of Digits LeetCode Solution in Python

from heapq import heappush, heappop
class SizedHeap:
    def __init__(self, size: int):
        self.heap = []
        self.size = size
    
    def push(self, element: int):
        if len(self.heap) < self.size:
            heappush(self.heap, element)
        elif element > self.heap[0]:
            heappop(self.heap)
            heappush(self.heap, element)
            
    def len(self) -> int:
        return len(self.heap)
            
    def sum(self) -> int:
        return sum(self.heap)

class Solution:
    def maximumSum(self, nums: List[int]) -> int:
        n = len(nums)
        sum_of_digits_max = defaultdict(lambda: SizedHeap(2))
        ans = -1
        
        for i, num in enumerate(nums):
            tmp = num
            s = 0
            while num:
                s += num % 10
                num = num // 10
            sum_of_digits_max[s].push(tmp)
        
        for sum_digit in sum_of_digits_max:
            if sum_of_digits_max[sum_digit].len() < 2: continue
            ans = max(ans, sum_of_digits_max[sum_digit].sum())
        return ans
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