**Physical Address**

304 North Cardinal St.

Dorchester Center, MA 02124

Alice manages a company and has rented some floors of a building as office space. Alice has decided some of these floors should be **special floors**, used for relaxation only.

You are given two integers `bottom`

and `top`

, which denote that Alice has rented all the floors from `bottom`

to `top`

(**inclusive**). You are also given the integer array `special`

, where `special[i]`

denotes a special floor that Alice has designated for relaxation.

Return *the maximum number of consecutive floors without a special floor*.

**Example 1:**

```
Input: bottom = 2, top = 9, special = [4,6]
Output: 3
Explanation: The following are the ranges (inclusive) of consecutive floors without a special floor:
- (2, 3) with a total amount of 2 floors.
- (5, 5) with a total amount of 1 floor.
- (7, 9) with a total amount of 3 floors.
Therefore, we return the maximum number which is 3 floors.
```

**Example 2:**

```
Input: bottom = 6, top = 8, special = [7,6,8]
Output: 0
Explanation: Every floor rented is a special floor, so we return 0.
```

**Constraints:**

`1 <= special.length <= 10`

^{5}`1 <= bottom <= special[i] <= top <= 10`

^{9}- All the values of
`special`

are**unique**.

```
public int maxConsecutive(int bottom, int top, int[] A) {
Arrays.sort(A);
int n = A.length, res = Math.max(A[0] - bottom, top - A[n - 1]);
for (int i = 1; i < n; ++i)
res = Math.max(res, A[i] - A[i - 1] - 1);
return res;
}
```

```
int maxConsecutive(int bottom, int top, vector<int>& A) {
sort(begin(A), end(A));
int n = A.size(), res = max(A[0] - bottom, top - A[n - 1]);
for (int i = 1; i < n; ++i)
res = max(res, A[i] - A[i - 1] - 1);
return res;
}
```

```
def maxConsecutive(self, bottom, top, A):
A.sort()
res = max(top - A[-1], A[0] - bottom)
for i in range(1, len(A)):
res = max(res, A[i] - A[i - 1] - 1)
return res
```

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