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# Maximum Consecutive Floors Without Special Floors LeetCode Solution

## Problem – Maximum Consecutive Floors Without Special Floors leetCode Solution

Alice manages a company and has rented some floors of a building as office space. Alice has decided some of these floors should be special floors, used for relaxation only.

You are given two integers `bottom` and `top`, which denote that Alice has rented all the floors from `bottom` to `top` (inclusive). You are also given the integer array `special`, where `special[i]` denotes a special floor that Alice has designated for relaxation.

Return the maximum number of consecutive floors without a special floor.

Example 1:

``````Input: bottom = 2, top = 9, special = [4,6]
Output: 3
Explanation: The following are the ranges (inclusive) of consecutive floors without a special floor:
- (2, 3) with a total amount of 2 floors.
- (5, 5) with a total amount of 1 floor.
- (7, 9) with a total amount of 3 floors.
Therefore, we return the maximum number which is 3 floors.``````

Example 2:

``````Input: bottom = 6, top = 8, special = [7,6,8]
Output: 0
Explanation: Every floor rented is a special floor, so we return 0.
``````

Constraints:

• `1 <= special.length <= 105`
• `1 <= bottom <= special[i] <= top <= 109`
• All the values of `special` are unique.

### Maximum Consecutive Floors Without Special Floors LeetCode Solution in Java

``````    public int maxConsecutive(int bottom, int top, int[] A) {
Arrays.sort(A);
int n = A.length, res = Math.max(A[0] - bottom, top - A[n - 1]);
for (int i = 1; i < n; ++i)
res = Math.max(res, A[i] - A[i - 1] - 1);
return res;
}
``````

### Maximum Consecutive Floors Without Special Floors LeetCode Solution in C++

``````    int maxConsecutive(int bottom, int top, vector<int>& A) {
sort(begin(A), end(A));
int n = A.size(), res = max(A[0] - bottom, top - A[n - 1]);
for (int i = 1; i < n; ++i)
res = max(res, A[i] - A[i - 1] - 1);
return res;
}
``````

### Maximum Consecutive Floors Without Special Floors LeetCode Solution in python

``````    def maxConsecutive(self, bottom, top, A):
A.sort()
res = max(top - A[-1], A[0] - bottom)
for i in range(1, len(A)):
res = max(res, A[i] - A[i - 1] - 1)
return res
``````
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