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# Maximum Depth of Binary Tree LeetCode Solution

## Problem – Maximum Depth of Binary Tree LeetCode Solution

Given the `root` of a binary tree, return its maximum depth.

A binary tree’s maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

Example 1:

``````Input: root = [3,9,20,null,null,15,7]
Output: 3
``````

Example 2:

``````Input: root = [1,null,2]
Output: 2
``````

Constraints:

• The number of nodes in the tree is in the range `[0, 104]`.
• `-100 <= Node.val <= 100`

### Maximum Depth of Binary Tree LeetCode Solution in Java

``````class Solution {
public int maxDepth(TreeNode root) {
// Base Condition
if(root == null) return 0;
// Hypothesis
int left = maxDepth(root.left);
int right = maxDepth(root.right);
// Induction
return Math.max(left, right) + 1;
}
}
``````

### Maximum Depth of Binary Tree LeetCode Solution in C++

``````class Solution {
public:
int maxDepth(TreeNode* root) {
if(root == NULL) return 0;
int left = maxDepth(root->left);
int right = maxDepth(root->right);
return max(left, right) + 1;
}
};
``````

### Maximum Depth of Binary Tree LeetCode Solution in Python

``````class Solution(object):
def maxDepth(self, root):
"""
:type root: TreeNode
:rtype: int
"""
depth = 0
level = [root] if root else []
while level:
depth += 1
queue = []
for el in level:
if el.left:
queue.append(el.left)
if el.right:
queue.append(el.right)
level = queue

return depth
``````
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