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# Maximum Number of Pairs in Array LeetCode Solution

## Problem – Maximum Number of Pairs in Array LeetCode Solution

You are given a 0-indexed integer array `nums`. In one operation, you may do the following:

• Choose two integers in `nums` that are equal.
• Remove both integers from `nums`, forming a pair.

The operation is done on `nums` as many times as possible.

Return 0-indexed integer array `answer` of size `2` where `answer` is the number of pairs that are formed and `answer` is the number of leftover integers in `nums` after doing the operation as many times as possible.

Example 1:

``````Input: nums = [1,3,2,1,3,2,2]
Output: [3,1]
Explanation:
Form a pair with nums and nums and remove them from nums. Now, nums = [3,2,3,2,2].
Form a pair with nums and nums and remove them from nums. Now, nums = [2,2,2].
Form a pair with nums and nums and remove them from nums. Now, nums = .
No more pairs can be formed. A total of 3 pairs have been formed, and there is 1 number leftover in nums.``````

Example 2:

``````Input: nums = [1,1]
Output: [1,0]
Explanation: Form a pair with nums and nums and remove them from nums. Now, nums = [].
No more pairs can be formed. A total of 1 pair has been formed, and there are 0 numbers leftover in nums.
``````

Example 3:

``````Input: nums = 
Output: [0,1]
Explanation: No pairs can be formed, and there is 1 number leftover in nums.``````

Constraints:

• `1 <= nums.length <= 100`
• `0 <= nums[i] <= 100`

### Maximum Number of Pairs in Array LeetCode Solution in C++

``````vector<int> numberOfPairs(vector<int>& nums) {
int cnt{};
for(auto i:nums) cnt[i]++;
int pairs=0, leftover=0;
for(int i:cnt){
pairs+= i/2;
leftover+= i%2;
}
return {pairs,leftover};
}
``````

### Maximum Number of Pairs in Array LeetCode Solution in Java

`````` public int[] numberOfPairs(int[] nums) {
int cnt[]= new int;
for(int i:nums) cnt[i]++;
int pairs=0, leftover=0;
for(int i:cnt){
pairs+= i/2;
leftover+= i%2;
}
return new int[]{pairs,leftover};
}
``````

### Maximum Number of Pairs in Array LeetCode Solution in Python

``````class Solution:
def numberOfPairs(self, nums: List[int]) -> List[int]:
ans =  * 2
c = Counter(nums)

for v in c.values():
ans += (v // 2)
ans += (v % 2)

return ans
``````
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