Maze of Digits CodeChef Solution

Problem -Maze of Digits CodeChef Solution

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Maze of Digits CodeChef Solution in C++17

#include <iostream>
#include <cstdio>
#include <cstring>
#include <queue>
#include <string>
using namespace std;
 
const int MAXN = 105;
string map[MAXN];
int dir[5] = {1, 0, -1, 0, 1};
int f[MAXN][MAXN][MAXN];
int T, N, M, X, sx, sy;
 
int bfs(int y, int x, int v) {
	int nx, ny, nv;
	queue<int> Q;
	memset(f, 0x33, sizeof(f));
	f[y][x][v] = 0;
	Q.push(y), Q.push(x), Q.push(v);
 
	while(!Q.empty()) {
		y = Q.front(), Q.pop();
		x = Q.front(), Q.pop();
		v = Q.front(), Q.pop();
 
		for(int i = 0; i < 4; i++) {
			ny = y + dir[i];
			nx = x + dir[i + 1];
			if(ny >= 0 && ny <= N && nx >= 0 && nx <= M)
			if(map[ny][nx] != '#') {
				nv = v + map[ny][nx] - '0';
				if(nv == X) return f[y][x][v] + 1;
				if(nv > X) continue;
				if(f[ny][nx][nv] > f[y][x][v] + 1) {
					f[ny][nx][nv] = f[y][x][v] + 1;
					Q.push(ny), Q.push(nx), Q.push(nv);
				}
			}
		}
	}
	return -1;
}
 
int main() {
	cin >> T;
	while(T--) {
		cin >> N >> M;
		for(int i = 0; i <= N; i++) {
			cin >> map[i];
			for(int j = 0; j <= M; j++) {
				if(map[i][j] == '*') sy = i, sx = j, map[i][j] = '0';
				else if(map[i][j] == '.') map[i][j] = '0';
			}
		}
		cin >> X;
		cout << bfs(sy, sx, 0) << endl;
	}
	return 0;
}

Maze of Digits CodeChef Solution in C++14

#include <bits/stdc++.h>

#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")

using namespace std;

struct PairHash {inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }};

// speed
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);

// alias
using ll = long long;
using ld = long double;
using ull = unsigned long long;

// constants
const ld PI = 3.14159265358979323846;  /* pi */
const ll INF = 1e18;
const ld EPS = 1e-9;
const ll MAX_N = 3030303;
const ll mod = 1e9 + 7;

// typedef
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ld> vld;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef deque<ll> dqll;
typedef deque<pll> dqpll;
typedef pair<string, string> pss;
typedef vector<pss> vpss;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
typedef unordered_map<pll, ll, PairHash> umpll;

// macros
#define rep(i,m,n) for(ll i=m;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
#define INF(a) memset(a,0x3f3f3f3f3f3f3f3fLL,sizeof(a))
#define ASCEND(a) iota(all(a),0)
#define sz(x) ll((x).size())
#define BIT(a,i) (a & (1ll<<i))
#define BITSHIFT(a,i,n) (((a<<i) & ((1ll<<n) - 1)) | (a>>(n-i)))
#define pyes cout<<"YES\n";
#define pno cout<<"NO\n";
#define endl "\n"
#define pneg1 cout<<"-1\n";
#define ppossible cout<<"Possible\n";
#define pimpossible cout<<"Impossible\n";
#define TC(x) cout<<"Case #"<<x<<": ";
#define X first
#define Y second

// utility functions
template <typename T>
void print(T &&t)  { cout << t << "\n"; }
template<typename T>
void printv(vector<T>v){ll n=v.size();rep(i,0,n){cout<<v[i];if(i+1!=n)cout<<' ';}cout<<endl;}
template<typename T>
void printvln(vector<T>v){ll n=v.size();rep(i,0,n)cout<<v[i]<<endl;}
void fileIO(string in = "input.txt", string out = "output.txt") {freopen(in.c_str(),"r",stdin); freopen(out.c_str(),"w",stdout);}
void readf() {freopen("", "rt", stdin);}
template<typename T>
void readv(vector<T>& v){rep(i,0,sz(v)) cin>>v[i];}
template<typename T, typename U>
void readp(pair<T,U>& A) {cin>>A.first>>A.second;}
template<typename T, typename U>
void readvp(vector<pair<T,U>>& A) {rep(i,0,sz(A)) readp(A[i]); }
void readvall3(vall3& A) {rep(i,0,sz(A)) cin>>A[i][0]>>A[i][1]>>A[i][2];}
void readvall5(vall5& A) {rep(i,0,sz(A)) cin>>A[i][0]>>A[i][1]>>A[i][2]>>A[i][3]>>A[i][4];}
void readvvll(vvll& A) {rep(i,0,sz(A)) readv(A[i]);}

struct Combination {
    vll fac, inv;
    ll n, MOD;

    ll modpow(ll n, ll x, ll MOD = mod) { if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

    Combination(ll _n, ll MOD = mod): n(_n + 1), MOD(MOD) {
        inv = fac = vll(n,1);
        rep(i,1,n) fac[i] = fac[i-1] * i % MOD;
        inv[n - 1] = modpow(fac[n - 1], MOD - 2, MOD);
        rrep(i,1,n - 2) inv[i] = inv[i + 1] * (i + 1) % MOD;
    }

    ll fact(ll n) {return fac[n];}
    ll nCr(ll n, ll r) {
        if(n < r or n < 0 or r < 0) return 0;
        return fac[n] * inv[r] % MOD * inv[n-r] % MOD;
    }
};

struct Matrix {
    ll r,c;
    vvll matrix;
    Matrix(ll r, ll c, ll v = 0): r(r), c(c), matrix(vvll(r,vll(c,v))) {}

    Matrix operator*(const Matrix& B) const {
        Matrix res(r, B.c);
        rep(i,0,r) rep(j,0,B.c) rep(k,0,B.r) {
                    res.matrix[i][j] = (res.matrix[i][j] + matrix[i][k] * B.matrix[k][j] % mod) % mod;
                }
        return res;
    }

    Matrix copy() {
        Matrix copy(r,c);
        copy.matrix = matrix;
        return copy;
    }

    Matrix pow(ll n) {
        assert(r == c);
        Matrix res(r,r);
        Matrix now = copy();
        rep(i,0,r) res.matrix[i][i] = 1;
        while(n) {
            if(n & 1) res = res * now;
            now = now * now;
            n /= 2;
        }
        return res;
    }
};

// geometry data structures
template <typename T>
struct Point {
    T y,x;
    Point(T y, T x) : y(y), x(x) {}
    Point(pair<T,T> p) : y(p.first), x(p.second) {}
    Point() {}
    void input() {cin>>y>>x;}
    friend ostream& operator<<(ostream& os, const Point<T>& p) { os<<p.y<<' '<<p.x<<'\n'; return os;}
    Point<T> operator+(Point<T>& p) {return Point<T>(y + p.y, x + p.x);}
    Point<T> operator-(Point<T>& p) {return Point<T>(y - p.y, x - p.x);}
    Point<T> operator*(ll n) {return Point<T>(y*n,x*n); }
    Point<T> operator/(ll n) {return Point<T>(y/n,x/n); }
    bool operator<(const Point &other) const {if (x == other.x) return y < other.y;return x < other.x;}
    Point<T> rotate(Point<T> center, ld angle) {
        ld si = sin(angle * PI / 180.), co = cos(angle * PI / 180.);
        ld y = this->y - center.y;
        ld x = this->x - center.x;

        return Point<T>(y * co - x * si + center.y, y * si + x * co + center.x);
    }
    ld distance(Point<T> other) {
        T dy = abs(this->y - other.y);
        T dx = abs(this->x - other.x);
        return sqrt(dy * dy + dx * dx);
    }

    T norm() { return x * x + y * y; }
};

template<typename T>
struct Line {
    Point<T> A, B;
    Line(Point<T> A, Point<T> B) : A(A), B(B) {}
    Line() {}

    void input() {
        A = Point<T>();
        B = Point<T>();
        A.input();
        B.input();
    }

    T ccw(Point<T> &a, Point<T> &b, Point<T> &c) {
        T res = a.x * b.y + b.x * c.y + c.x * a.y;
        res -= (a.x * c.y + b.x * a.y + c.x * b.y);
        return res;
    }

    bool isIntersect(Line<T> o) {
        T p1p2 = ccw(A,B,o.A) * ccw(A,B,o.B);
        T p3p4 = ccw(o.A,o.B,A) * ccw(o.A,o.B,B);
        if (p1p2 == 0 && p3p4 == 0) {
            pair<T,T> p1(A.y, A.x), p2(B.y,B.x), p3(o.A.y, o.A.x), p4(o.B.y, o.B.x);
            if (p1 > p2) swap(p2, p1);
            if (p3 > p4) swap(p3, p4);
            return p3 <= p2 && p1 <= p4;
        }
        return p1p2 <= 0 && p3p4 <= 0;
    }

    pair<bool,Point<ld>> intersection(Line<T> o) {
        if(!this->intersection(o)) return {false, {}};
        ld det = 1. * (o.B.y-o.A.y)*(B.x-A.x) - 1.*(o.B.x-o.A.x)*(B.y-A.y);
        ld t = ((o.B.x-o.A.x)*(A.y-o.A.y) - (o.B.y-o.A.y)*(A.x-o.A.x)) / det;
        return {true, {A.y + 1. * t * (B.y - A.y), B.x + 1. * t * (B.x - A.x)}};
    }

    //@formula for : y = ax + b
    //@return {a,b};
    pair<ld, ld> formula() {
        T y1 = A.y, y2 = B.y;
        T x1 = A.x, x2 = B.x;
        if(y1 == y2) return {1e9, 0};
        if(x1 == x2) return {0, 1e9};
        ld a = 1. * (y2 - y1) / (x2 - x1);
        ld b = -x1 * a + y1;
        return {a, b};
    }
};

template<typename T>
struct Circle {
    Point<T> center;
    T radius;
    Circle(T y, T x, T radius) : center(Point<T>(y,x)), radius(radius) {}
    Circle(Point<T> center, T radius) : center(center), radius(radius) {}
    Circle() {}

    void input() {
        center = Point<T>();
        center.input();
        cin>>radius;
    }

    bool circumference(Point<T> p) {
        return (center.x - p.x) * (center.x - p.x) + (center.y - p.y) * (center.y - p.y) == radius * radius;
    }

    bool intersect(Circle<T> c) {
        T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
        return (radius - c.radius) * (radius - c.radius) <= d and d <= (radius + c.radius) * (radius + c.radius);
    }

    bool include(Circle<T> c) {
        T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
        return d <= radius * radius;
    }
};

ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
all3 __exgcd(ll x, ll y) { if(!y) return {x,1,0}; auto [g,x1,y1] = __exgcd(y, x % y); return {g, y1, x1 - (x/y) * y1}; }
ll __lcm(ll x, ll y) { return x / __gcd(x,y) * y; }
ll modpow(ll n, ll x, ll MOD = mod) { n%=MOD; if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

ll vis[101][101][101];

ll bfs(vs& A, ll sy, ll sx, ll k) {
    if(k == 1) return 0;
    queue<all3> q;
    q.push({0,sy,sx});
    vis[0][sy][sx] = 0;
    ll dy[4]{-1,0,1,0},dx[4]{0,1,0,-1};
    ll n = sz(A), m = sz(A[0]);
    while(sz(q)) {
        auto [val, y, x] = q.front(); q.pop();
        rep(i,0,4) {
            ll ny = y + dy[i], nx = x + dx[i];
            if(0 <= ny and ny < n and 0 <= nx and nx < m and A[ny][nx] != '#') {
                ll cost = 1 + vis[val][y][x];
                ll v = val + (isdigit(A[ny][nx]) ? A[ny][nx] - '0' : 0);
                if(v > k) continue;
                if(vis[v][ny][nx] <= cost) continue;
                vis[v][ny][nx] = cost;
                if(v == k)
                    return cost;
                q.push({v,ny,nx});
            }
        }
    }
    return -1;
}

ll solve(vs A, ll x) {
    INF(vis);
    rep(i,0,sz(A)) rep(j,0,sz(A[i])) {
        if(A[i][j] == '*') return bfs(A,i,j,x);
    }
    return -1;
}
int main() {
    Code By Sumfi
    cout.precision(12);
    ll tc = 1;
    cin>>tc;
    rep(i,1,tc+1) {
        ll n,m,x;
        cin>>n>>m;
        vs A(n + 1);
        readv(A);
        cin>>x;
        print(solve(A,x));
    }
    return 0;
}

Maze of Digits CodeChef Solution in C

#include <stdio.h>
#define MIN(x,y) ((x)<(y)?(x):(y))
#define MX 102
#define true 1
#define false 0
#define MXQ 10005

const int INF = 100000005;
int R,C,D,dx[]={0,0,1,-1},dy[]={1,-1,0,0};
int G[MX][MX];
int vis[MX][MX];
int DigInd[MX][MX];
int DigsX[MX], DigsY[MX], DigsN[MX];
int Dis[MX][MX];
int dp[MX][MX];
int Q[MXQ];


void bfsStart(int sx,int sy)
{
	DigInd[sx][sy]=0; 
	DigsX[0]=sx; DigsY[0]=sy; DigsN[0]=0;
	int i,j,k,cx,cy,cs,nx,ny,ns,x;

	for(i=0;i<=R;i++) for(j=0;j<=C;j++) vis[i][j]=false;

	D=1;
	int H=0,T=0;
	Q[T++]=sx+1000*sy;
	vis[sx][sy]=true;

	while(H!=T)
	{
		x=Q[H++];
		if(H==MXQ) H=0;
		cx=x%1000; x/=1000;
		cy=x%1000; x/=1000;
		cs=x;

		for(i=0;i<4;i++)
		{
			nx=cx+dx[i]; ny=cy+dy[i]; ns=cs+1;
			if(nx<0||nx>R||ny<0||ny>C||G[nx][ny]==-1||vis[nx][ny])
				continue;
			if(G[nx][ny]>0) // Got a new number, Update !
			{
				DigInd[nx][ny]=D;
				DigsX[D]=nx; DigsY[D]=ny; DigsN[D]=G[nx][ny];
				Dis[0][D]=ns; 
				Dis[D][0]=ns;
				D++;
			}
			vis[nx][ny]=true;
			Q[T++]=nx+1000*(ny+1000*ns);
			if(T==MXQ) T=0;
		}
	}

	// Distance to itself is 2 .. haha :)
	for(i=0;i<D;i++) Dis[i][i]=2;
}



void bfsOnDig(int ci)
{
	int sx=DigsX[ci], sy=DigsY[ci];
	int i,j,k,cx,cy,cs,nx,ny,ns,x;

	for(i=0;i<=R;i++) for(j=0;j<=C;j++) vis[i][j]=false;
	int H=0,T=0;
	Q[T++]=(sx+sy*1000);
	vis[sx][sy]=true;

	while(H!=T)
	{
		x=Q[H++];
		if(H==MXQ) H=0;
		cx=x%1000; x/=1000;
		cy=x%1000; x/=1000;
		cs=x;
		for(i=0;i<4;i++)
		{
			nx=cx+dx[i]; ny=cy+dy[i]; ns=cs+1;
			if(nx<0||nx>R||ny<0||ny>C||G[nx][ny]==-1||vis[nx][ny])
				continue;
			if(G[nx][ny]>0) Dis[ci][DigInd[nx][ny]]=ns;
			vis[nx][ny]=true;
			Q[T++]=(nx+1000*(ny+1000*ns));
			if(T==MXQ) T=0;
		}
	}
}



int getMinSteps(int X)
{
	int i,j,k,pn,cn,pi,ci,r=INF,mn;
	for(i=0;i<D;i++) for(j=0;j<=X;j++) dp[i][j]=INF;
	dp[0][0]=0;
	
	for(i=1;i<=X;i++)
		for(ci=1;ci<D;ci++)
		{
			pn=i-DigsN[ci];
			if(pn<0) continue;
			mn=INF;
			for(pi=0;pi<D;pi++)
				mn = MIN( mn , dp[pi][pn]+Dis[ci][pi]);
			dp[ci][i]=mn;
		}

	for(i=0;i<D;i++) r = MIN( r , dp[i][X] );
	return r;
}



int main()
{
	int cases,i,j,k,x,sx,sy,s,res;
	char ch,in[105];
	scanf("%d",&cases);
	while(cases--)
	{
		scanf("%d %d ",&R,&C);
		for(i=0;i<=R;i++)
		{
			gets(in);
			for(j=0;j<=C;j++)
			{
				ch = in[j];
				if(ch=='*') sx=i,sy=j;
				if(ch=='#') G[i][j]=-1;
				else
				{ 
					if(ch>'0' && ch<='9') G[i][j]=ch-'0';
					else G[i][j]=0;
				}
			}
		}
		scanf("%d",&x);

		// find APSP ( = Every SSSP )
		bfsStart(sx,sy);
		for(i=1;i<D;i++) bfsOnDig(i);

		res = getMinSteps(x);
		if(res==INF) printf("-1\n");
		else printf("%d\n",res);
	}
	return 0;
}


/* Code and Let Code ~ */

Maze of Digits CodeChef Solution in JAVA

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;

public class Main {

	public static void main(String[] args) throws IOException {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		PrintWriter out = new PrintWriter(System.out);

		for (int t = Integer.valueOf(in.readLine()); t > 0; t--) {
			in.readLine();
			String[] T = in.readLine().split(" ");
			int n = Integer.valueOf(T[0]) + 1;
			int m = Integer.valueOf(T[1]) + 1;
			
			int[][] map = new int[n][m];
			int sx = -1, sy = -1;
			
			for (int i = 0; i < n; i++) {
				String s = in.readLine();
				for (int j = 0; j < m; j++) {
					map[i][j] = s.charAt(j) == '#' ? -1 : s.charAt(j) >= '0' && s.charAt(j) <= '9' ? s.charAt(j) - '0' : 0;
					if (s.charAt(j) == '*') {
						sx = i;
						sy = j;
					}
				}
			}
			
			int q = Integer.valueOf(in.readLine());
			int res = -1;
			
			int[][][] dp = new int[n][m][q+1];
			start = finish = 0;
			dp[qx[finish] = sx][qy[finish] = sy][qq[finish] = 0] = 1;
			finish++;
			
			while (finish - start > 0) {
				int x = qx[start], y = qy[start], Q = qq[start], D = dp[x][y][Q];
				start++;
				
				if (Q == q) {
					res = D - 1;
					break;
				}
				
				for (int i = 0; i < dx.length; i++) {
					int tox = x + dx[i], toy = y + dy[i];
					if (tox >= 0 && tox < n && toy >= 0 && toy < m && map[tox][toy] != -1) {
						int toq = Q + map[tox][toy];
						if (toq <= q && dp[tox][toy][toq] == 0) {
							dp[qx[finish] = tox][qy[finish] = toy][qq[finish] = toq] = D + 1;
							finish++;
						}
					}
				}
			}
			
			out.println(res);
		}
		
		out.flush();
	}

	static int[] qx = new int[101*101*101];
	static int[] qy = new int[101*101*101];
	static int[] qq = new int[101*101*101];
	static int start, finish;
	
	static int[] dx = new int[]{1, 0, -1, 0};
	static int[] dy = new int[]{0, 1, 0, -1};
}

Maze of Digits CodeChef Solution in C#

using System;
using System.Collections;

public class K3
{
    static int[] dr = { 0, 1, 0, -1 };
    static int[] dc = { 1, 0, -1, 0 };

    public static void Main(string[] args)
    {
        int t = int.Parse(Console.ReadLine());
        while (t-- > 0) TestCase();
    }

    public static void TestCase()
    {
        Console.ReadLine();
        string[] parts = Console.ReadLine().Split();
        int M = 1 + int.Parse(parts[0]);
        int N = 1 + int.Parse(parts[1]);
        char[][] maze = new char[M][];
        int sr = -1, sc = -1;
        for (int i = 0; i < M; i++)
        {
            maze[i] = Console.ReadLine().ToCharArray();
            for (int j = 0; j < N; j++)
            {
                if (maze[i][j] == '*')
                {
                    sr = i;
                    sc = j;
                    maze[i][j] = '.';
                }
            }
        }
        int X = int.Parse(Console.ReadLine());

        Queue Q = new Queue();
        Q.Enqueue(new State(sr, sc, 0, X));
        bool[, ,] done = new bool[M, N, X + 1];
        while (Q.Count > 0)
        {
            State top = Q.Dequeue() as State;
            if (done[top.r, top.c, top.x])
                continue;
            done[top.r, top.c, top.x] = true;
            if (maze[top.r][top.c] == '#')
                continue;
            int nx = top.x;
            if(maze[top.r][top.c] != '.') nx -= maze[top.r][top.c] - '0';
            if (nx == 0)
            {
                Console.WriteLine(top.steps);
                return;
            }
            for (int i = 0; i < 4; i++)
            {
                int nr = top.r + dr[i];
                int nc = top.c + dc[i];
                if (nr < 0 || nr >= M || nc < 0 || nc >= N || nx < 0 || done[nr, nc, nx]) continue;
                Q.Enqueue(new State(nr, nc, top.steps + 1, nx));
            }
        }

        Console.WriteLine("-1");
    }

    public class State
    {
        public int r, c, steps, x;

        public State(int r, int c, int s, int x)
        {
            this.r = r;
            this.c = c;
            this.steps = s;
            this.x = x;
        }
    }
}

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