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# Merge the Tools! Hacker Rank Solution – Queslers

## Problem: Merge the Tools! Hacker Rank Solution

Consider the following:

A string, s, of length n where s = c0c1. . . . cn-1.

An integer, k, where k is a factor of n.

We can split s into n/k substrings where each subtring, ti, consists of a contiguous block of k characters in s. Then, use each ti to create string ui such that:

The characters in ui are a subsequence of the characters in ti.

Any repeat occurrence of a character is removed from the string such that each character in ui occurs exactly once. In other words, if the character at some index j in ti occurs at a previous index < j in ti, then do not include the character in string ui.

Given s and k, print n/k lines where each line i denotes string ui.

Example

k = 3

There are three substrings of length 3 to consider: ‘AAA’, ‘BCA’ and ‘DDE’. The first substring is all ‘A’ characters, so u1 = ‘A’. The second substring has all distinct characters, so u2 = ‘BCA’. The third substring has 2 different characters, so u3 = ‘DE’. Note that a subsequence maintains the original order of characters encountered. The order of characters in each subsequence shown is important.

#### Function Description

Complete the merge_the_tools function in the editor below.

merge_the_tools has the following parameters:

• string s: the string to analyze
• int k: the size of substrings to analyze

#### Prints

Print each subsequence on a new line. There will be n/k of them. No return value is expected.

#### Input Format

The first line contains a single string, s.

The second line contains an integer, k, the length of each substring.

#### Constraints

• 1 <= n <= 10^4, where n is the length of s
• 1 <= k <= n
• It is guaranteed that n is a multiple of k.

Sample Input

``````STDIN       Function
-----       --------
3           k = 3``````

Sample Output

``````AB
CA

Explanation

Split s into n/k = 9/3 = 3 equal parts of length k = 3. Convert each ti to ui by removing any subsequent occurrences of non-distinct characters in ti:

1. t0 = “AAB” – u0 = “AB”
2. t1 = “CAA” – u1 = “CA”
3. t2 = “ADA” – u2 = “AD”

Print each ui on a new line.

### Merge the Tools! Hacker Rank Solution in Python 2

``````# Enter your code here. Read input from STDIN. Print output to STDOUT
s = raw_input().strip()
k = int(raw_input())
i = 0
while i < len(s):
a = s[i:i+k]
output = ""
for x in a:
if x not in output:
output += x
print output
i += k``````

### Merge the Tools! Hacker Rank Solution in Python 3

``````def merge_the_tools(string, k):
for part in zip(*[iter(string)] * k):
d = dict()
print(''.join([ d.setdefault(c, c) for c in part if c not in d ]))``````

### Merge the Tools! Hacker Rank Solution in pypy

``````def merge_the_tools(string, k):
# your code goes here
for x in xrange(0,len(string),k):
u_list=list(set(string[x:x+k]))
print ''.join(u_list)``````

### Merge the Tools! Hacker Rank Solution in pypy3

``````# Enter your code here. Read input from STDIN. Print output to STDOUT
s=input()
k=int(input())
ln=len(s)

for i in range(0,ln,k):
ss=s[i:i+k]
sss=[]
for x in ss:
if x not in sss:
sss.append(x)

print (''.join(sss))  ``````
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