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# Middle of the Linked List LeetCode Solution

## Problem – Middle of the Linked List LeetCode Solution

Given the `head` of a singly linked list, return the middle node of the linked list.

If there are two middle nodes, return the second middle node.

Example 1:

``````Input: head = [1,2,3,4,5]
Output: [3,4,5]
Explanation: The middle node of the list is node 3.``````

Example 2:

``````Input: head = [1,2,3,4,5,6]
Output: [4,5,6]
Explanation: Since the list has two middle nodes with values 3 and 4, we return the second one.
``````

Constraints:

• The number of nodes in the list is in the range `[1, 100]`.
• `1 <= Node.val <= 100`

### Middle of the Linked List LeetCode Solution in C++

``````    ListNode* middleNode(ListNode* head) {
ListNode *slow = head, *fast = head;
while (fast && fast->next)
slow = slow->next, fast = fast->next->next;
return slow;
}
``````

### Middle of the Linked List LeetCode Solution in Java

``````    public ListNode middleNode(ListNode head) {
ListNode slow = head, fast = head;
while (fast != null && fast.next != null) {
slow = slow.next;
fast = fast.next.next;
}
return slow;
}
``````

### Middle of the Linked List LeetCode Solution in Python

``````    def middleNode(self, head):
slow = fast = head
while fast and fast.next:
slow = slow.next
fast = fast.next.next
return slow
``````
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