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# Minimum Cars required CodeChef Solution

## Problem – Minimum Cars required CodeChef Solution

A single car can accommodate at most 4 people.

N friends want to go to a restaurant for a party. Find the minimum number of cars required to accommodate all the friends.

### Input Format

• The first line contains a single integer T – the number of test cases. Then the test cases follow.
• The first and only line of each test case contains an integer N – denoting the number of friends.

### Output Format

For each test case, output the minimum number of cars required to accommodate all the friends.

• 1≤T≤1000
• 2≤N≤1000

### Sample 1:

``````Input: 4
4
2
7
98
Output: 1
1
2
25
``````

### Explanation:

Test Case 1: There are only 4 friends and a single car can accommodate 4 people. Thus, only 1 car is required.

Test Case 2: There are only 2 friends and a single car can accommodate 4 people. Thus, only 1 car is required

Test Case 3: There are 7 friends and 2 cars can accommodate 8 people. Thus, 2 cars are required.

## Minimum Cars required CodeChef Solution in Java

``````/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{

Scanner sc=new Scanner(System.in);
int T=sc.nextInt();
for(int i=0;i<T;i++)
{
int x=sc.nextInt();
int a=x%4;
int b=x/4;
if(a==0)
System.out.println(b);
else
System.out.println(b+1);
}
}
}
``````

## Minimum Cars required CodeChef Solution in Pyth 3

``````# cook your dish here
n=int(input())
for i in range(0,n):
e=int(input())
d=e%4
if(d<4 and d!=0):
print((e//4)+1)
elif(d==0):
print(e//4)
``````

## Minimum Cars required CodeChef Solution in C++17

``````#include <iostream>
using namespace std;

int main() {
int t;
cin>>t;
while(t--){
int n;
cin>>n;
// cout<<n*2<<endl;
if(n%4==0)
{
cout<<(n/4)<<endl;
}
else{
cout<<(n/4)+1<<endl;
}
}

return 0;
}
``````
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