Minimum Consecutive Cards to Pick Up LeetCode Solution

Problem – Minimum Consecutive Cards to Pick Up LeetCode Solution

You are given an integer array cards where cards[i] represents the value of the ith card. A pair of cards are matching if the cards have the same value.

Return the minimum number of consecutive cards you have to pick up to have a pair of matching cards among the picked cards. If it is impossible to have matching cards, return -1.

Example 1:

Input: cards = [3,4,2,3,4,7]
Output: 4
Explanation: We can pick up the cards [3,4,2,3] which contain a matching pair of cards with value 3. Note that picking up the cards [4,2,3,4] is also optimal.

Example 2:

Input: cards = [1,0,5,3]
Output: -1
Explanation: There is no way to pick up a set of consecutive cards that contain a pair of matching cards.

Constraints:

• 1 <= cards.length <= 105
• 0 <= cards[i] <= 106

Minimum Consecutive Cards to Pick Up LeetCode Solution in C++

int minimumCardPickup(vector<int>& cards) {
    int last[1000001] = {}, res = INT_MAX;
    for (int i = 0; i < cards.size(); ++i) {
        if (last[cards[i]])
            res = min(res, i - last[cards[i]] + 2);
        last[cards[i]] = i + 1;
    }
    return res == INT_MAX ? -1 : res;
}

Minimum Consecutive Cards to Pick Up LeetCode Solution in Java

class Solution
{
    public int minimumCardPickup(int[] cards)
    {
        Map<Integer,Integer> map = new HashMap<>();
        int min = Integer.MAX_VALUE;
        for(int i = 0; i < cards.length; i++)
        {
            if(map.containsKey(cards[i]))
                min = Math.min(i-map.get(cards[i])+1,min); // Check if the difference in indices is smaller than minimum
            map.put(cards[i],i); // Update the last found index of the card
        }
        return min == Integer.MAX_VALUE?-1:min; // Repetition found or not
    }
}

Minimum Consecutive Cards to Pick Up LeetCode Solution in Python

class Solution:
    def minimumCardPickup(self, cards: List[int]) -> int:
        minPick = float('inf')
        seen = {}
        for i, n in enumerate(cards):
            if n in seen:
                if i - seen[n] + 1 < minPick:
                    minPick = i - seen[n] + 1
            seen[n] = i
        if minPick == float('inf'):
            return -1
        return minPick

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