Minimum Distance Between BST Nodes LeetCode Solution

Problem – Minimum Distance Between BST Nodes

Given the root of a Binary Search Tree (BST), return the minimum difference between the values of any two different nodes in the tree.

Example 1:

Input: root = [4,2,6,1,3]
Output: 1

Example 2:

Input: root = [1,0,48,null,null,12,49]
Output: 1

Constraints:

• The number of nodes in the tree is in the range [2, 100].
• 0 <= Node.val <= 105

Minimum Distance Between BST Nodes LeetCode Solution in C++

class Solution {
  public:
    int res = INT_MAX, pre = -1;
    int minDiffInBST(TreeNode* root) {
        if (root->left != NULL) minDiffInBST(root->left);
        if (pre >= 0) res = min(res, root->val - pre);
        pre = root->val;
        if (root->right != NULL) minDiffInBST(root->right);
        return res;
    }
};

Minimum Distance Between BST Nodes LeetCode Solution in Java

class Solution {
    Integer res = Integer.MAX_VALUE, pre = null;
    public int minDiffInBST(TreeNode root) {
        if (root.left != null) minDiffInBST(root.left);
        if (pre != null) res = Math.min(res, root.val - pre);
        pre = root.val;
        if (root.right != null) minDiffInBST(root.right);
        return res;
    }
}

Minimum Distance Between BST Nodes LeetCode Solution in Python

class Solution(object):
    pre = -float('inf')
    res = float('inf')

    def minDiffInBST(self, root):
        if root.left:
            self.minDiffInBST(root.left)
        self.res = min(self.res, root.val - self.pre)
        self.pre = root.val
        if root.right:
            self.minDiffInBST(root.right)
        return self.res

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