### Problem : Mod Divmod Hacker Rank Solution

One of the built-in functions of Python is divmod, which takes two arguments a and b and returns a tuple containing the quotient of a/b first and then the remainder a.

**For example:**

`>>> print divmod(`**177**,**10**)
(**17**, **7**)

Here, the integer division is 177/10 => 17 and the modulo operator is 177%10 => 7.

#### Task :

Read in two integers, a and b, and print three lines.

The first line is the integer division a//b (While using Python2 remember to import division from __future__).

The second line is the result of the modulo operator: a%b.

The third line prints the divmod of a and b.

#### Input Format :

The first line contains the first integer, a, and the second line contains the second integer, b.

#### Output Format :

Print the result as described above.

#### Sample Input :

**177**
**10**

#### Sample Output :

**17**
**7**
(**17**, **7**)

### Mod Divmod Hacker Rank Solution in Python

```
a = int(raw_input())
b = int(raw_input())
print a/b
print a%b
print divmod(a,b)
```

### Mod Divmod Hacker Rank Solution in Pythonn 3

```
# Enter your code here. Read input from STDIN. Print output to STDOUT
print('{0}\n{1}\n({0}, {1})'.format(*divmod(int(input()), int(input()))))
```

### Mod Divmod Hacker Rank Solution in pypy

```
# Enter your code here. Read input from STDIN. Print output to STDOUT
from __future__ import division
a = input()
b = input()
print a//b
print a%b
print divmod(a,b)
```

### Mod Divmod Hacker Rank Solution in pypy3

```
# Enter your code here. Read input from STDIN. Print output to STDOUT
a = int(input())
b = int(input())
print(a//b)
print(a%b)
print(divmod(a,b))
```

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