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# Mod Divmod Hacker Rank Solution – Queslers

### Problem : Mod Divmod Hacker Rank Solution

One of the built-in functions of Python is divmod, which takes two arguments a and b and returns a tuple containing the quotient of a/b first and then the remainder a.

For example:

``````>>> print divmod(177,10)
(17, 7)
``````

Here, the integer division is 177/10 => 17 and the modulo operator is 177%10 => 7.

Read in two integers, a and b, and print three lines.
The first line is the integer division a//b (While using Python2 remember to import division from __future__).
The second line is the result of the modulo operator: a%b.
The third line prints the divmod of a and b.

#### Input Format :

The first line contains the first integer, a, and the second line contains the second integer, b.

#### Output Format :

Print the result as described above.

#### Sample Input :

``````177
10
``````

#### Sample Output :

``````17
7
(17, 7)
``````

### Mod Divmod Hacker Rank Solution in Python

``````a = int(raw_input())
b = int(raw_input())
print a/b
print a%b
print divmod(a,b)``````

### Mod Divmod Hacker Rank Solution in Pythonn 3

``````# Enter your code here. Read input from STDIN. Print output to STDOUT
print('{0}\n{1}\n({0}, {1})'.format(*divmod(int(input()), int(input()))))
``````

### Mod Divmod Hacker Rank Solution in pypy

``````# Enter your code here. Read input from STDIN. Print output to STDOUT
from __future__ import division

a = input()
b = input()
print a//b
print a%b
print divmod(a,b)``````

### Mod Divmod Hacker Rank Solution in pypy3

``````# Enter your code here. Read input from STDIN. Print output to STDOUT
a = int(input())
b = int(input())

print(a//b)
print(a%b)
print(divmod(a,b))``````
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