Nested Lists Hacker Rank Solution – Queslers

Problem: Nested Lists Hacker Rank Solution

Given the names and grades for each student in a Physics class of N students, store them in a nested list and print the name(s) of any student(s) having the second-lowest grade.

Note: If there are multiple students with the same grade, order their names alphabetically and print each name on a new line.

Input Format

The first line contains an integer, N , the number of students.
The 2N subsequent lines describe each student over 2 lines; the first line contains a student’s name, and the second line contains their grade.

Constraints

  • There will always be one or more students having the second lowest grade.

Output Format

Print the name(s) of any student(s) having the second lowest grade in Physics; if there are multiple students, order their names alphabetically and print each one on a new line.

Sample Input 0

5

Harry

37.21

Berry

37.21

Tina

37.2

Akriti

41

Harsh

39

Sample Output 0

Berry

Harry

Explanation 0

There are 5 students in this class whose names and grades are assembled to build the following list:

python students = [['Harry', 37.21], ['Berry', 37.21], ['Tina', 37.2], ['Akriti', 41], ['Harsh', 39]]

The lowest grade of 37.2 belongs to Tina. The second-lowest grade of 37.21 belongs to both Harry and Berry, so we order their names alphabetically and print each name on a new line.

Nested Lists Hacker Rank Solution Using Python 2

n = int(raw_input())
lst = []
for x in range(0, n):
    lst.append([raw_input(), float(raw_input())])
lst = sorted(lst, key=lambda x: x[1]);
for x in range(1, n):
    if(lst[x][1] != lst[x-1][1]):
        score = lst[x][1]
        break
lst = sorted(lst);
for x in range(n):
    if(lst[x][1] == score):
        print lst[x][0]

Nested Lists Hacker Rank Solution Using Python 3

if __name__ == '__main__':
    students = []
    for _ in range(int(input())):
        name = input()
        score = float(input())
        students.append([name,score]) 
    x = 99999
    for i in range(len(students)):
        if x > float(students[i][1]):
            x = float(students[i][1])
    y = 999999
    for i in range(len(students)):
        if float(students[i][1]) > float(x) and y > float(students[i][1]):
            y = float(students[i][1])
    runner = []
    for i in range(len(students)):
        if float(students[i][1]) == float(y):
            runner.append(students[i][0])
    runner = sorted(runner)

    for i in range(len(runner)):
        print(runner[i])

Nested Lists Hacker Rank Solution Using Pypy

if __name__ == '__main__':
    L=[]
    n=int(raw_input())
    for _ in range(n):
        name = raw_input()
        score = float(raw_input())
        L.append([name,score])
    k=[]
    for i in range(n):
        k.append(L[i][1])
    k.sort()
        
    i=1
    while i<n and k[0]==k[i]:
        i=i+1
    m=k[i]
    s=[]
    for j in range(n):
        if L[j][1]==m:
            s.append(L[j][0])
    s.sort()
    for z in range(len(s)):
     print(s[z])

Nested Lists Hacker Rank Solution Using Pypy3

if __name__ == '__main__':
   
    arr = []
    for _ in range(int(input())):
        name = input()
        score = float(input())       
        arr.append([score,name])
    arr.sort()
    for i in range(len(arr)):
         if arr[i][0]> arr[0][0]:
            print(arr[i][1])
            
            if i+1 >= len(arr) or arr[i+1][0] > arr[i][0]:
                #print(arr[i+1][1])
                break    
    #print (arr[1][1])
        #print (arr)
        #print (x)
Nested Lists Hacker Rank Solution Review:

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