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# Nim Game LeetCode Solution

## Problem – Nim Game LeetCode Solution

You are playing the following Nim Game with your friend:

• Initially, there is a heap of stones on the table.
• You and your friend will alternate taking turns, and you go first.
• On each turn, the person whose turn it is will remove 1 to 3 stones from the heap.
• The one who removes the last stone is the winner.

Given `n`, the number of stones in the heap, return `true` if you can win the game assuming both you and your friend play optimally, otherwise return `false`.

Example 1:

``````Input: n = 4
Output: false
Explanation: These are the possible outcomes:
1. You remove 1 stone. Your friend removes 3 stones, including the last stone. Your friend wins.
2. You remove 2 stones. Your friend removes 2 stones, including the last stone. Your friend wins.
3. You remove 3 stones. Your friend removes the last stone. Your friend wins.
In all outcomes, your friend wins.
``````

Example 2:

``````Input: n = 1
Output: true
``````

Example 3:

``````Input: n = 2
Output: true
``````

Constraints:

• `1 <= n <= 231 - 1`

## Nim Game LeetCode Solution in C++

``````class Solution {
public:
bool canWinNim(int n) {
return n%4 ;
}
};
``````

## Nim Game LeetCode Solution in Python

``````class Solution(object):
def canWinNim(self, n):
"""
:type n: int
:rtype: bool
"""
return bool(n % 4)
``````

## Nim Game LeetCode Solution in Java

``````public boolean canWinNim(int n) {
if (n <= 0) {return false;}
return n % 4 != 0;
}
``````
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