## Problem – Nim Game LeetCode Solution

You are playing the following Nim Game with your friend:

- Initially, there is a heap of stones on the table.
- You and your friend will alternate taking turns, and
**you go first**. - On each turn, the person whose turn it is will remove 1 to 3 stones from the heap.
- The one who removes the last stone is the winner.

Given `n`

, the number of stones in the heap, return `true`

* if you can win the game assuming both you and your friend play optimally, otherwise return *`false`

.

**Example 1:**

**Input:** n = 4
**Output:** false
**Explanation:** These are the possible outcomes:
1. You remove 1 stone. Your friend removes 3 stones, including the last stone. Your friend wins.
2. You remove 2 stones. Your friend removes 2 stones, including the last stone. Your friend wins.
3. You remove 3 stones. Your friend removes the last stone. Your friend wins.
In all outcomes, your friend wins.

**Example 2:**

**Input:** n = 1
**Output:** true

**Example 3:**

**Input:** n = 2
**Output:** true

**Constraints:**

## Nim Game LeetCode Solution in C++

```
class Solution {
public:
bool canWinNim(int n) {
return n%4 ;
}
};
```

## Nim Game LeetCode Solution in Python

```
class Solution(object):
def canWinNim(self, n):
"""
:type n: int
:rtype: bool
"""
return bool(n % 4)
```

## Nim Game LeetCode Solution in Java

```
public boolean canWinNim(int n) {
if (n <= 0) {return false;}
return n % 4 != 0;
}
```

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