No Idea Hacker Rank Solution – Queslers

Problem : No Idea Hacker Rank Solution

There is an array of n integers. There are also 2 disjoint sets, A and B, each containing m integers. You like all the integers in set A and dislike all the integers in set B. Your initial happiness is 0. For each i integer in the array, if i (- A , you add 1 to your happiness. If i (- B, you add -1 to your happiness. Otherwise, your happiness does not change. Output your final happiness at the end.

Note: Since A and B are sets, they have no repeated elements. However, the array might contain duplicate elements.

Constraints :

• 1 <= n <= 10^5
• 1 <= m <= 10^5
• 1 <= any integer in the input <= 10^9

Input Format :

The first line contains integers n and m separated by a space.
The second line contains n integers, the elements of the array.
The third and fourth lines contain m integers, A and B, respectively.

Output Format :

Output a single integer, your total happiness.

Sample Input :

3 2
1 5 3
3 1
5 7

Sample Output :

1

Explanation :

You gain 1 unit of happiness for elements 3 and 1 in set A. You lose 1 unit for 5 in set B. The element 7 in set B does not exist in the array so it is not included in the calculation.
Hence, the total happiness is 2 – 1 = 1.

No Idea Hacker Rank Solution in python 2

import sys

def main():
    h = Happiness()
    input = get_input()
    m = input["m"]
    n = input["n"]
    n_array = input["n_array"]
    A_set = input["A_set"]
    B_set = input["B_set"]
    for num in n_array:
        if num in A_set:
            h.incr()
        elif num in B_set:
            h.decr()
    print h.val

class Happiness():
    def __init__(self):
        self.val = 0
    def incr(self):
        self.val += 1
    def decr(self):
        self.val -= 1

def get_input():
        input_m_n = sys.stdin.readline().strip()
        input_n_array = sys.stdin.readline().strip()
        input_A_set = sys.stdin.readline().strip()
        input_B_set = sys.stdin.readline().strip()
        m, n = input_m_n.split(' ')
        n_array = input_n_array.split(' ')
        A_set = set(input_A_set.split(' '))
        B_set = set(input_B_set.split(' '))
        result = {"m":m, "n":n, "n_array": n_array, "A_set": A_set, "B_set": B_set}
        return result

if __name__ == '__main__':
    main()

No Idea Hacker Rank Solution in python 3

# Enter your code here. Read input from STDIN. Print output to STDOUT
n, m = input().split()

sc_ar = input().split()

A = set(input().split())
B = set(input().split())
print(sum([(i in A) - (i in B) for i in sc_ar]))

No Idea Hacker Rank Solution in pypy

# Enter your code here. Read input from STDIN. Print output to STDOUT
n, m = raw_input().split()

arr = raw_input().split()

A = set(raw_input().split())
B = set(raw_input().split())
print sum([(i in A) - (i in B) for i in arr])

No Idea Hacker Rank Solution in pypy 3

# Enter your code here. Read input from STDIN. Print output to STDOUT
numlst =input().split()
l = input().split()
A = set(input().split())
B = set(input().split())
print(len(list(filter(lambda x: x in A, l))) - len(list(filter(lambda x: x in B, l))))

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