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# Node With Highest Edge Score LeetCode Solution

## Problem – Node With Highest Edge Score LeetCode Solution

You are given a directed graph with `n` nodes labeled from `0` to `n - 1`, where each node has exactly one outgoing edge.

The graph is represented by a given 0-indexed integer array `edges` of length `n`, where `edges[i]` indicates that there is a directed edge from node `i` to node `edges[i]`.

The edge score of a node `i` is defined as the sum of the labels of all the nodes that have an edge pointing to `i`.

Return the node with the highest edge score. If multiple nodes have the same edge score, return the node with the smallest index.

Example 1:

``````Input: edges = [1,0,0,0,0,7,7,5]
Output: 7
Explanation:
- The nodes 1, 2, 3 and 4 have an edge pointing to node 0. The edge score of node 0 is 1 + 2 + 3 + 4 = 10.
- The node 0 has an edge pointing to node 1. The edge score of node 1 is 0.
- The node 7 has an edge pointing to node 5. The edge score of node 5 is 7.
- The nodes 5 and 6 have an edge pointing to node 7. The edge score of node 7 is 5 + 6 = 11.
Node 7 has the highest edge score so return 7.
``````

Example 2:

``````Input: edges = [2,0,0,2]
Output: 0
Explanation:
- The nodes 1 and 2 have an edge pointing to node 0. The edge score of node 0 is 1 + 2 = 3.
- The nodes 0 and 3 have an edge pointing to node 2. The edge score of node 2 is 0 + 3 = 3.
Nodes 0 and 2 both have an edge score of 3. Since node 0 has a smaller index, we return 0.
``````

Constraints:

• `n == edges.length`
• `2 <= n <= 105`
• `0 <= edges[i] < n`
• `edges[i] != i`

### Node With Highest Edge Score LeetCode Solution in C++

``````int edgeScore(vector<int>& edges) {
vector<long long> score(edges.size());
for (int i = 0; i < edges.size(); ++i)
score[edges[i]] += i;
return max_element(begin(score), end(score)) - begin(score);
}
``````

### Node With Highest Edge Score LeetCode Solution in Java

``````class Solution {
public int edgeScore(int[] edges) {
int n_length=edges.length;
//to avoid overflow we will take long size score array
long score_of_node[]=new long[n_length];
for(int i=0; i<n_length; i++){
score_of_node[edges[i]]+=i; //score of the node will be update to (prev score + incomming node) here every i denotes income incomming vertex
}
int max_ans_index=0;

for(int i=0; i<n_length; i++){
if(score_of_node[i]>score_of_node[max_ans_index]){
max_ans_index=i; // simply just find the node with maximum score and
}
}
return max_ans_index; // return the node
}
}
``````

### Node With Highest Edge Score LeetCode Solution in Python

``````class Solution:
def edgeScore(self, edges: List[int]) -> int:

n = len(edges)
cnt = defaultdict(int)
ans = 0

for i in range(n):
cnt[edges[i]] += i

m = max(cnt.values())

for i in range(n):
if cnt[i] == m:
ans = i
break

return ans
``````
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