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Not All Flavours CodeChef Solution
Problem -Not All Flavours CodeChef Solution
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Not All Flavours CodeChef Solution in C++17
/*ॐ Arpit Blagan ॐ*/
#include<bits/stdc++.h>
using namespace std;
#define all(arr) arr.begin(),arr.end()
#define rep(i,s,e) for(int i=s;i<e;i++)
#define lli long long int
#define int long long
const long long INF=1e18;
const int mod=1e9+7,N=1e6+10;
int32_t main(){
ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
int t;cin>>t;
while(t--){
int n,k;cin>>n>>k;
vector<int>arr(n);for(int i=0;i<n;i++){cin>>arr[i];}
unordered_map<int,int>mp;
int j=0;int ans=0;
for(int i=0;i<n;i++){
mp[arr[i]]++;
if(mp.size()<k){
ans=max(ans,i-j+1);
}
else{
while(j<=i&&mp.size()==k){
mp[arr[j]]--;
if(mp[arr[j]]==0){mp.erase(arr[j]);}j++;
}
if(mp.size()<k){ans=max(ans,i-j+1);}
}
}cout<<ans<<"\n";
}
return 0;
}Not All Flavours CodeChef Solution in C++14
#include <bits/stdc++.h>
#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")
using namespace std;
struct PairHash {inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }};
// speed
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);
// alias
using ll = long long;
using ld = long double;
using ull = unsigned long long;
// constants
const ld PI = 3.14159265358979323846; /* pi */
const ll INF = 1e18;
const ld EPS = 1e-9;
const ll MAX_N = 1010101;
const ll mod = 1e9 + 7;
// typedef
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ld> vld;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef deque<ll> dqll;
typedef deque<pll> dqpll;
typedef pair<string, string> pss;
typedef vector<pss> vpss;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
typedef unordered_map<pll, ll, PairHash> umpll;
// macros
#define rep(i,m,n) for(ll i=m;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
#define INF(a) memset(a,0x3f3f3f3f3f3f3f3fLL,sizeof(a))
#define ASCEND(a) iota(all(a),0)
#define sz(x) ll((x).size())
#define BIT(a,i) (a & (1ll<<i))
#define BITSHIFT(a,i,n) (((a<<i) & ((1ll<<n) - 1)) | (a>>(n-i)))
#define pyes cout<<"YES\n";
#define pno cout<<"NO\n";
#define endl "\n"
#define pneg1 cout<<"-1\n";
#define ppossible cout<<"Possible\n";
#define pimpossible cout<<"Impossible\n";
#define TC(x) cout<<"Case #"<<x<<": ";
#define X first
#define Y second
// utility functions
template <typename T>
void print(T &&t) { cout << t << "\n"; }
template<typename T>
void printv(vector<T>v){ll n=v.size();rep(i,0,n){cout<<v[i];if(i+1!=n)cout<<' ';}cout<<endl;}
template<typename T>
void printvln(vector<T>v){ll n=v.size();rep(i,0,n)cout<<v[i]<<endl;}
void fileIO(string in = "input.txt", string out = "output.txt") {freopen(in.c_str(),"r",stdin); freopen(out.c_str(),"w",stdout);}
void readf() {freopen("", "rt", stdin);}
template<typename T>
void readv(vector<T>& v){rep(i,0,sz(v)) cin>>v[i];}
template<typename T, typename U>
void readp(pair<T,U>& A) {cin>>A.first>>A.second;}
template<typename T, typename U>
void readvp(vector<pair<T,U>>& A) {rep(i,0,sz(A)) readp(A[i]); }
void readvall3(vall3& A) {rep(i,0,sz(A)) cin>>A[i][0]>>A[i][1]>>A[i][2];}
void readvall5(vall5& A) {rep(i,0,sz(A)) cin>>A[i][0]>>A[i][1]>>A[i][2]>>A[i][3]>>A[i][4];}
void readvvll(vvll& A) {rep(i,0,sz(A)) readv(A[i]);}
struct Combination {
vll fac, inv;
ll n, MOD;
ll modpow(ll n, ll x, ll MOD = mod) { if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }
Combination(ll _n, ll MOD = mod): n(_n + 1), MOD(MOD) {
inv = fac = vll(n,1);
rep(i,1,n) fac[i] = fac[i-1] * i % MOD;
inv[n - 1] = modpow(fac[n - 1], MOD - 2, MOD);
rrep(i,1,n - 2) inv[i] = inv[i + 1] * (i + 1) % MOD;
}
ll fact(ll n) {return fac[n];}
ll nCr(ll n, ll r) {
if(n < r or n < 0 or r < 0) return 0;
return fac[n] * inv[r] % MOD * inv[n-r] % MOD;
}
};
struct Matrix {
ll r,c;
vvll matrix;
Matrix(ll r, ll c, ll v = 0): r(r), c(c), matrix(vvll(r,vll(c,v))) {}
Matrix operator*(const Matrix& B) const {
Matrix res(r, B.c);
rep(i,0,r) rep(j,0,B.c) rep(k,0,B.r) {
res.matrix[i][j] = (res.matrix[i][j] + matrix[i][k] * B.matrix[k][j] % mod) % mod;
}
return res;
}
Matrix copy() {
Matrix copy(r,c);
copy.matrix = matrix;
return copy;
}
Matrix pow(ll n) {
assert(r == c);
Matrix res(r,r);
Matrix now = copy();
rep(i,0,r) res.matrix[i][i] = 1;
while(n) {
if(n & 1) res = res * now;
now = now * now;
n /= 2;
}
return res;
}
};
// geometry data structures
template <typename T>
struct Point {
T y,x;
Point(T y, T x) : y(y), x(x) {}
Point(pair<T,T> p) : y(p.first), x(p.second) {}
Point() {}
void input() {cin>>y>>x;}
friend ostream& operator<<(ostream& os, const Point<T>& p) { os<<p.y<<' '<<p.x<<'\n'; return os;}
Point<T> operator+(Point<T>& p) {return Point<T>(y + p.y, x + p.x);}
Point<T> operator-(Point<T>& p) {return Point<T>(y - p.y, x - p.x);}
Point<T> operator*(ll n) {return Point<T>(y*n,x*n); }
Point<T> operator/(ll n) {return Point<T>(y/n,x/n); }
bool operator<(const Point &other) const {if (x == other.x) return y < other.y;return x < other.x;}
Point<T> rotate(Point<T> center, ld angle) {
ld si = sin(angle * PI / 180.), co = cos(angle * PI / 180.);
ld y = this->y - center.y;
ld x = this->x - center.x;
return Point<T>(y * co - x * si + center.y, y * si + x * co + center.x);
}
ld distance(Point<T> other) {
T dy = abs(this->y - other.y);
T dx = abs(this->x - other.x);
return sqrt(dy * dy + dx * dx);
}
T norm() { return x * x + y * y; }
};
template<typename T>
struct Line {
Point<T> A, B;
Line(Point<T> A, Point<T> B) : A(A), B(B) {}
Line() {}
void input() {
A = Point<T>();
B = Point<T>();
A.input();
B.input();
}
T ccw(Point<T> &a, Point<T> &b, Point<T> &c) {
T res = a.x * b.y + b.x * c.y + c.x * a.y;
res -= (a.x * c.y + b.x * a.y + c.x * b.y);
return res;
}
bool isIntersect(Line<T> o) {
T p1p2 = ccw(A,B,o.A) * ccw(A,B,o.B);
T p3p4 = ccw(o.A,o.B,A) * ccw(o.A,o.B,B);
if (p1p2 == 0 && p3p4 == 0) {
pair<T,T> p1(A.y, A.x), p2(B.y,B.x), p3(o.A.y, o.A.x), p4(o.B.y, o.B.x);
if (p1 > p2) swap(p2, p1);
if (p3 > p4) swap(p3, p4);
return p3 <= p2 && p1 <= p4;
}
return p1p2 <= 0 && p3p4 <= 0;
}
pair<bool,Point<ld>> intersection(Line<T> o) {
if(!this->intersection(o)) return {false, {}};
ld det = 1. * (o.B.y-o.A.y)*(B.x-A.x) - 1.*(o.B.x-o.A.x)*(B.y-A.y);
ld t = ((o.B.x-o.A.x)*(A.y-o.A.y) - (o.B.y-o.A.y)*(A.x-o.A.x)) / det;
return {true, {A.y + 1. * t * (B.y - A.y), B.x + 1. * t * (B.x - A.x)}};
}
//@formula for : y = ax + b
//@return {a,b};
pair<ld, ld> formula() {
T y1 = A.y, y2 = B.y;
T x1 = A.x, x2 = B.x;
if(y1 == y2) return {1e9, 0};
if(x1 == x2) return {0, 1e9};
ld a = 1. * (y2 - y1) / (x2 - x1);
ld b = -x1 * a + y1;
return {a, b};
}
};
template<typename T>
struct Circle {
Point<T> center;
T radius;
Circle(T y, T x, T radius) : center(Point<T>(y,x)), radius(radius) {}
Circle(Point<T> center, T radius) : center(center), radius(radius) {}
Circle() {}
void input() {
center = Point<T>();
center.input();
cin>>radius;
}
bool circumference(Point<T> p) {
return (center.x - p.x) * (center.x - p.x) + (center.y - p.y) * (center.y - p.y) == radius * radius;
}
bool intersect(Circle<T> c) {
T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
return (radius - c.radius) * (radius - c.radius) <= d and d <= (radius + c.radius) * (radius + c.radius);
}
bool include(Circle<T> c) {
T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
return d <= radius * radius;
}
};
ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
all3 __exgcd(ll x, ll y) { if(!y) return {x,1,0}; auto [g,x1,y1] = __exgcd(y, x % y); return {g, y1, x1 - (x/y) * y1}; }
ll __lcm(ll x, ll y) { return x / __gcd(x,y) * y; }
ll modpow(ll n, ll x, ll MOD = mod) { n%=MOD; if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }
ll solve(vll A, ll k) {
ll res = 0;
umll freq;
ll l = 0, r = 0, n = sz(A);
while(r < n) {
while(r < n and sz(freq) < k) {
res = max(res, r - l);
freq[A[r++]]++;
}
if(sz(freq) < k) res = max(res, r - l);
while(r < n and sz(freq) >= k) {
if(--freq[A[l]] == 0) freq.erase(A[l]);
l += 1;
}
}
return res;
}
int main() {
Code By Sumfi
cout.precision(12);
ll tc = 1;
cin>>tc;
rep(i,1,tc+1) {
ll n,k;
cin>>n>>k;
vll A(n);
readv(A);
print(solve(A,k));
}
return 0;
}Not All Flavours CodeChef Solution in PYTH 3
for i in range(int(input())):
n,k=map(int,input().split())
l=list(map(int,input().split()))
j,i,mx=0,0,0
d=dict()
while(j<n):
if l[j] in d:
d[l[j]]+=1
else:
d[l[j]]=1
if(len(d)<=k-1):
mx=max(mx,j-i+1)
j+=1
else:
while(len(d)>k-1):
d[l[i]]-=1
if(d[l[i]]==0):
d.pop(l[i])
i+=1
j+=1
print(mx)
Not All Flavours CodeChef Solution in C
#include <stdio.h>
int main(void) {
int t;
scanf("%d",&t);
while(t--){
int n,k;
scanf("%d %d",&n,&k);
int i,a[n];
int b[k];
for(i=0;i<n;i++)
scanf("%d",&a[i]);
for(i=0;i<=k;i++)
b[i]=0;
int l=0,max=0,z=0,m=0;
for(i=0;i<n;i++){
if(b[a[i]] == 0)
m++;
l++;
b[a[i]]++;
if(m < k){
if(l > max)
max = l;
}else{
l--;
if(b[a[z]] == 1)
m--;
b[a[z++]]--;
}
}
printf("%d\n",max);
}
return 0;
}Not All Flavours CodeChef Solution in JAVA
/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
// your code goes here
Scanner sc=new Scanner(System.in);
int t=sc.nextInt();
while(t-->0){
int n=sc.nextInt();
int k=sc.nextInt();
int a[]=new int[n];
for(int i=0;i<n;i++){
a[i]=sc.nextInt();
}
k=k-1;
int diff=0;
int start=0;
int end=0;
int curr_count=0;
int prev_ele=0;
int freq[]=new int[100001];
for(int i=0;i<n;i++){
freq[a[i]]+=1;
if(freq[a[i]]==1){
curr_count=curr_count+1;
}
while(curr_count>k){
freq[a[prev_ele]]-=1;
if(freq[a[prev_ele]]==0){
curr_count=curr_count-1;
}
prev_ele = prev_ele + 1;
}
if(i-prev_ele+1>=end-start+1){
end=i;
start=prev_ele;
}
}
System.out.println(end+1-start);
/*
int n=sc.nextInt();
int a[]=new int[n];
int freq[]=new int[100001];
for(int i=0;i<n;i++){
a[i]=sc.nextInt();
}
int count=0;
for(int i=0;i<n;i++){
freq[a[i]]+=1;
System.out.println(freq[a[i]]);
if(freq[a[i]]==1){
System.out.println("hh");
}
}
for(int i=0;i<n;i++) {
System.out.println(freq[a[i]]);
}
*/
}
}
}Not All Flavours CodeChef Solution in PYPY 3
def main():
t=int(input())
while(t>0):
n,k=map(int,input().split())
arr=list(map(int,input().split()))
freq=[0]*100001
k=k-1
st=0
end=0
currentcount=0
prevelement=0
for i in range(n):
freq[arr[i]]+=1
if(freq[arr[i]])==1:
currentcount+=1
while(currentcount>k):
freq[arr[prevelement]]-=1
if(freq[arr[prevelement]]==0):
currentcount-=1
prevelement+=1
if(i-prevelement+1>=end-st+1):
end=i
st=prevelement
print(end-st+1)
t=t-1
if __name__=='__main__':
main()Not All Flavours CodeChef Solution in PYTH
sinput = raw_input
def intput(s =''):
''' To get data in the form of an integer'''
return int(sinput(s) )
def lintput(s=''):
''' To get data in the form of space separated integers and return a tuple containing them'''
return map(int,sinput(s).split() )
def intputs(s=''):
'''To get data in the form of space separated integers and return a tuple containing them'''
return tuple(lintput(s) )
def lprint(l):
for i in l:
print i
'''Main structer for testcased problems'''
T = intput()
R = [0]*T
for Q in range(T):
N,K = intputs()
s = lintput()
pre = [-1,]*(K+1) # Previous
pre[0] = None
mg = [0,]*(K+1) # Max gap
mg[0] = None
for i in range(N):
#print mg[s[i]], i-pre[s[i]]
mg[s[i]] = max(mg[s[i]], (i - pre[s[i]]))
pre[s[i]] = i
for i in range(1,K+1):
mg[i] = max(mg[i], N-pre[i])
#print mg
if -1 in pre: # A flavour has not been used
R[Q] = N
else:
R[Q] = max(mg)-1
lprint(R)Not All Flavours CodeChef Solution in C#
using System;
using System.Collections.Generic;
using System.Linq;
public class Program
{
public static void Main(string[] args)
{
NotAllFravours();
}
public static void NotAllFravours()
{
int n = int.Parse(Console.ReadLine());
string[] NK;
int nn;
int k;
for (int testCase = 0; testCase < n; testCase++)
{
NK = Console.ReadLine().Split(' ');
nn = int.Parse(NK[0]);
k = int.Parse(NK[1]);
var integers = Console.ReadLine().Split(' ').ToList().Select(integ => int.Parse(integ)).ToList();
var appearence = new List<int>();
var set = new HashSet<int>();
var order = new List<int>() { integers[0] };
var lastChar = integers[0];
set.Add(integers[0]);
appearence.Add(1);
var maxResult = 0;
var currentResult = 1;
for (int i = 1; i < integers.Count; i++)
{
if (integers[i] == lastChar)
{
appearence[appearence.Count - 1]++;
currentResult++;
}
else
{
if (set.Count >= k - 1 && !set.Contains(integers[i]))
{
if (currentResult > maxResult)
{
maxResult = currentResult;
}
while (set.Count >= k - 1)
{
currentResult -= appearence[0];
appearence.RemoveAt(0);
var removedChar = order[0];
order.RemoveAt(0);
if (!order.Contains(removedChar))
{
set.Remove(removedChar);
}
}
appearence.Add(1);
set.Add(integers[i]);
order.Add(integers[i]);
currentResult++;
}
else
{
appearence.Add(1);
set.Add(integers[i]);
order.Add(integers[i]);
currentResult++;
}
lastChar = integers[i];
}
}
Console.WriteLine(Math.Max(currentResult, maxResult));
}
}
public static void AtTheGate()
{
int numberOfTestCases = int.Parse(Console.ReadLine());
for (int testCase = 0; testCase < numberOfTestCases; testCase++)
{
string[] NK = Console.ReadLine().Split(' ');
int n = int.Parse(NK[0]);
int k = int.Parse(NK[1]);
string[] coinsLine = Console.ReadLine().Split(' ');
int nrOfRolls = 0;
bool currentHead = true;
for (int j = n - 1; j >= n - k; j--)
{
if (coinsLine[j] == (currentHead ? "H" : "T"))
{
nrOfRolls++;
currentHead = !currentHead;
}
}
bool showHead = nrOfRolls % 2 == 0;
int ans = 0;
for (int l = 0; l < n - k; l++)
{
if (coinsLine[l] == (showHead ? "H" : "T"))
ans++;
}
Console.WriteLine(ans);
}
}
public static void SwappingToPlaindrome()
{
int numberOfTestCases = int.Parse(Console.ReadLine());
for (int testCase = 0; testCase < numberOfTestCases; testCase++)
{
}
}
public static bool CheckIfCanBePalindrom(string s)
{
var characterCount = new Dictionary<char, int>();
foreach (var c in s)
{
if (characterCount.ContainsKey(c))
{
characterCount[c]++;
}
else
{
characterCount.Add(c, 1);
}
}
var numberOfOdds = 0;
foreach (var value in characterCount.Values)
{
if (value % 2 != 0)
numberOfOdds++;
if (numberOfOdds > 1)
return false;
}
return true;
}
}Not All Flavours CodeChef Solution in GO
package main
import (
"bufio"
"fmt"
"os"
)
var reader = bufio.NewReader(os.Stdin)
var writer = bufio.NewWriter(os.Stdout)
func scanf(f string, a ...interface{}) { fmt.Fscanf(reader, f, a...) }
func printf(f string, a ...interface{}) { fmt.Fprintf(writer, f, a...) }
func main() {
// STDOUT MUST BE FLUSHED MANUALLY!!!
defer writer.Flush()
var nt int
scanf("%d\n", &nt)
for t := 0; t < nt; t++ {
var n, k int
scanf("%d %d\n", &n, &k)
cakes := make([]int, n)
for i := 0; i < n; i++ {
scanf("%d", &cakes[i])
}
scanf("\n")
ml := 0
include := make(map[int]int)
l, r := 0, 0
count := 0
for ; r < n; r++ {
if include[cakes[r]] == 0 {
count++
}
include[cakes[r]]++
for ; count == k && l < r; l++ {
if include[cakes[l]] == 1 {
count--
}
include[cakes[l]]--
}
if ml < r-l+1 {
ml = r - l + 1
}
}
printf("%d\n", ml)
}
}Not All Flavours CodeChef Solution Review:
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