Number of 1 Bits LeetCode Solution

Problem – Number of 1 Bits

Write a function that takes an unsigned integer and returns the number of ‘1’ bits it has (also known as the Hamming weight).

Note:

  • Note that in some languages, such as Java, there is no unsigned integer type. In this case, the input will be given as a signed integer type. It should not affect your implementation, as the integer’s internal binary representation is the same, whether it is signed or unsigned.
  • In Java, the compiler represents the signed integers using 2’s complement notation. Therefore, in Example 3, the input represents the signed integer. -3.

Example 1:

Input: n = 00000000000000000000000000001011
Output: 3
Explanation: The input binary string 00000000000000000000000000001011 has a total of three '1' bits.

Example 2:

Input: n = 00000000000000000000000010000000
Output: 1
Explanation: The input binary string 00000000000000000000000010000000 has a total of one '1' bit.

Example 3:

Input: n = 11111111111111111111111111111101
Output: 31
Explanation: The input binary string 11111111111111111111111111111101 has a total of thirty one '1' bits.

Constraints:

  • The input must be a binary string of length 32.

Follow up: If this function is called many times, how would you optimize it?

Number of 1 Bits LeetCode Solution in Java

public static int hammingWeight(int n) {
	int ones = 0;
    	while(n!=0) {
    		ones = ones + (n & 1);
    		n = n>>>1;
    	}
    	return ones;
}

Number of 1 Bits LeetCode Solution in C++

int hammingWeight(uint32_t n) {
    int count = 0;
    
    while (n) {
        n &= (n - 1);
        count++;
    }
    
    return count;
}

Number of 1 Bits LeetCode Solution in Python

def hammingWeight(self, n):
    """
    :type n: int
    :rtype: int
    """
    return bin(n).count('1')
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