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# Number of Steps to Reduce a Number to Zero LeetCode Solution

## Problem – Number of Steps to Reduce a Number to Zero LeetCode Solution

Given an integer num, return the number of steps to reduce it to zero.

In one step, if the current number is even, you have to divide it by 2, otherwise, you have to subtract 1 from it.

Example 1:

Input: num = 14
Output: 6
Explanation:
Step 1) 14 is even; divide by 2 and obtain 7.
Step 2) 7 is odd; subtract 1 and obtain 6.
Step 3) 6 is even; divide by 2 and obtain 3.
Step 4) 3 is odd; subtract 1 and obtain 2.
Step 5) 2 is even; divide by 2 and obtain 1.
Step 6) 1 is odd; subtract 1 and obtain 0.

Example 2:

Input: num = 8
Output: 4
Explanation:
Step 1) 8 is even; divide by 2 and obtain 4.
Step 2) 4 is even; divide by 2 and obtain 2.
Step 3) 2 is even; divide by 2 and obtain 1.
Step 4) 1 is odd; subtract 1 and obtain 0.

Example 3:

Input: num = 123
Output: 12

Constraints:

• 0 <= num <= 106

### Number of Steps to Reduce a Number to Zero LeetCode Solution in C++

int numberOfSteps (int num) {
return num == 0 ? 0 : log2(num) + bitset<32>(num).count();
}

### Number of Steps to Reduce a Number to Zero LeetCode Solution in Python

class Solution:
def numberOfSteps (self, num: int) -> int:
bitstring = bin(num)[2:] # [2:] will remove the '0b' that is prepended to each bitstring by bin()
return len(bitstring) - 1 + bitstring.count('1')

### Number of Steps to Reduce a Number to Zero LeetCode Solution in Java

public int numberOfSteps (int num) {
return Integer.toBinaryString(num).length() - 1 + Integer.bitCount(num);
}
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