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Given an integer `x`

, return `true`

if `x`

is palindrome integer.

An integer is a **palindrome** when it reads the same backward as forward.

- For example,
`121`

is a palindrome while`123`

is not.

**Example 1:**

```
Input: x = 121
Output: true
Explanation: 121 reads as 121 from left to right and from right to left.
```

**Example 2:**

```
Input: x = -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
```

**Example 3:**

```
Input: x = 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
```

**Constraints:**

`-2`

^{31}<= x <= 2^{31}- 1

**Follow up:** Could you solve it without converting the integer to a string?

```
public boolean isPalindrome(int x) {
if (x<0 || (x!=0 && x%10==0)) return false;
int rev = 0;
while (x>rev){
rev = rev*10 + x%10;
x = x/10;
}
return (x==rev || x==rev/10);
}
```

```
class Solution {
public:
bool isPalindrome(int x) {
if(x<0|| (x!=0 &&x%10==0)) return false;
int sum=0;
while(x>sum)
{
sum = sum*10+x%10;
x = x/10;
}
return (x==sum)||(x==sum/10);
}
};
```

```
class Solution:
# @param x, an integer
# @return a boolean
def isPalindrome(self, x):
if x < 0:
return False
ranger = 1
while x / ranger >= 10:
ranger *= 10
while x:
left = x / ranger
right = x % 10
if left != right:
return False
x = (x % ranger) / 10
ranger /= 100
return True
```

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