Palindrome Number LeetCode Solution

Problem – Palindrome Number LeetCode Solution

Given an integer x, return true if x is palindrome integer.

An integer is a palindrome when it reads the same backward as forward.

• For example, 121 is a palindrome while 123 is not.

Example 1:

Input: x = 121
Output: true
Explanation: 121 reads as 121 from left to right and from right to left.

Example 2:

Input: x = -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.

Example 3:

Input: x = 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.

Constraints:

• -231 <= x <= 231 - 1

 Follow up: Could you solve it without converting the integer to a string?

Palindrome Number LeetCode Solution in Java

public boolean isPalindrome(int x) {
    if (x<0 || (x!=0 && x%10==0)) return false;
    int rev = 0;
    while (x>rev){
    	rev = rev*10 + x%10;
    	x = x/10;
    }
    return (x==rev || x==rev/10);
}

Palindrome Number LeetCode Solution in C++

class Solution {
public:
    bool isPalindrome(int x) {
        if(x<0|| (x!=0 &&x%10==0)) return false;
        int sum=0;
        while(x>sum)
        {
            sum = sum*10+x%10;
            x = x/10;
        }
        return (x==sum)||(x==sum/10);
    }
};

Palindrome Number LeetCode Solution in Python

class Solution:
    # @param x, an integer
    # @return a boolean
    def isPalindrome(self, x):
        if x < 0:
            return False

        ranger = 1
        while x / ranger >= 10:
            ranger *= 10

        while x:
            left = x / ranger
            right = x % 10
            if left != right:
                return False
            
            x = (x % ranger) / 10
            ranger /= 100

        return True

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