Pascal’s Triangle II LeetCode Solution – Queslers

Problem – Pascal’s Triangle II LeetCode Solution

Given an integer rowIndex, return the rowIndexth (0-indexed) row of the Pascal’s triangle.

In Pascal’s triangle, each number is the sum of the two numbers directly above it as shown:

Example 1:

Input: rowIndex = 3
Output: [1,3,3,1]

Example 2:

Input: rowIndex = 0
Output: [1]

Example 3:

Input: rowIndex = 1
Output: [1,1]

Constraints:

  • 0 <= rowIndex <= 33

Pascal’s Triangle II LeetCode Solution in Python

class Solution(object):
    def getRow(self, rowIndex):
        """
        :type rowIndex: int
        :rtype: List[int]
        """
        row = [1]
        for _ in range(rowIndex):
            row = [x + y for x, y in zip([0]+row, row+[0])]
        return row

Pascal’s Triangle II LeetCode Solution in Java

public class Solution {
    public List<Integer> getRow(int k) {
        Integer[] arr = new Integer[k + 1];
        Arrays.fill(arr, 0);
        arr[0] = 1;
        
        for (int i = 1; i <= k; i++) 
            for (int j = i; j > 0; j--) 
                arr[j] = arr[j] + arr[j - 1];
        
        return Arrays.asList(arr);
    }
}

Pascal’s Triangle II LeetCode Solution in C++

class Solution {
public:
    vector<int> getRow(int rowIndex) {
        vector<int> vi(rowIndex + 1);
       	vi[0] = 1;
        for (int i = 0; i <= rowIndex ; ++i)
        {
        	for (int j = i; j > 0; --j)
        	{
	        	vi[j] = vi[j] + vi[j-1];
        	}
        }
        return vi;
    }
};
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