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# Passes for Fair CodeChef Solution

## Problem – Passes for Fair CodeChef Solution

There is a fair going on in Chefland. Chef wants to visit the fair along with his N friends. Chef manages to collect K passes for the fair. Will Chef be able to enter the fair with all his N friends?

A person can enter the fair using one pass, and each pass can be used by only one person.

#### Input Format

• The first line of input will contain a single integer T, denoting the number of test cases.
• Each test case consists of a single line containing two space-separated integers N,K.

#### Output Format

For each test case, print on a new line YES if Chef will be able to enter the fair with all his N friends and NO otherwise.

You may print each character of the string in either uppercase or lowercase (for example, the strings yEsyesYes, and YES will all be treated as identical).

#### Constraints

• 1 \leq T \leq 1001≤T≤100
• 1 \leq N, K \leq 1001≤N,K≤100

#### Sample 1:

Input: 4
5 8
6 3
2 2
1 2
Output: YES
NO
NO
YES

### Explanation:

Test case 1: Chef needs 5 passes for his friends and one pass for himself and he collected 8 passes. Thus he will be able to enter the fair with all his friends.

Test case 2: Chef needs 6 passes for his friends and one pass for himself while he collected only 3 passes. Thus he will not be able to enter the fair with all his friends, only three of them can enter the fair.

Test case 3: Chef needs 2 passes for his friends and one pass for himself while he collected only 2 passes. Thus either Chef or one of his friends can’t enter the fair.

Test case 4: Chef needs a total of 2 passes, one for himself and one for his friend. He collected 2 passes. Thus he will be able to enter the fair with his friend.

### Passes for Fair CodeChef Solution in C++17

#include <iostream>
using namespace std;

int main() {
int t;
cin>>t;
while(t--)
{
int n,k;
cin>>n>>k;
if(k>=n+1)
cout<<"YES"<<endl;
else
cout<<"NO"<<endl;
}
return 0;
}


### Passes for Fair CodeChef Solution in Java

import java.util.*;
import java.lang.*;
import java.io.*;

class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int t= sc.nextInt();
for (int i=0;i<t;i++){
int n = sc.nextInt();
int k = sc.nextInt();
if(k>n){
System.out.println("yes");
}
else{
System.out.println("no");
}
}

}
}


### Passes for Fair CodeChef Solution in Python3

for i in range(int(input())):
a,b=map(int,input().split(" "))
if a+1<=b:
print("YES")
else:
print("NO")
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