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Patching Array LeetCode Solution

Problem – Patching Array LeetCode Solution

Given a sorted integer array `nums` and an integer `n`, add/patch elements to the array such that any number in the range `[1, n]` inclusive can be formed by the sum of some elements in the array.

Return the minimum number of patches required.

Example 1:

``````Input: nums = [1,3], n = 6
Output: 1
Explanation:
Combinations of nums are [1], [3], [1,3], which form possible sums of: 1, 3, 4.
Now if we add/patch 2 to nums, the combinations are: [1], [2], [3], [1,3], [2,3], [1,2,3].
Possible sums are 1, 2, 3, 4, 5, 6, which now covers the range [1, 6].
So we only need 1 patch.
``````

Example 2:

``````Input: nums = [1,5,10], n = 20
Output: 2
Explanation: The two patches can be [2, 4].
``````

Example 3:

``````Input: nums = [1,2,2], n = 5
Output: 0
``````

Constraints:

• `1 <= nums.length <= 1000`
• `1 <= nums[i] <= 104`
• `nums` is sorted in ascending order.
• `1 <= n <= 231 - 1`

Patching Array LeetCode Solution in C++

``````class Solution {
public:
int minPatches(vector<int>& nums, int n) {
int cnt=0,i=0;
long long maxNum=0;
while (maxNum<n){
if (i<nums.size() && nums[i]<=maxNum+1)
maxNum+=nums[i++];
else{
maxNum+=maxNum+1;cnt++;
}
}
return cnt;
}
};
``````

Patching Array LeetCode Solution in Python

``````class Solution:
def merge(self, intervals):
intervals.sort(key=lambda x: x[0])
merged = []

for interval in intervals:
if not merged or merged[-1][1] < interval[0] - 1:
merged.append(interval)
else:
merged[-1][1] = max(merged[-1][1], interval[1])

return merged

def minPatches(self, nums, n):
ints, patches = [[0,0]], 0
for num in nums:
ints = self.merge(ints + [[i+num, j+num] for i,j in ints])

while ints[0][1] < n:
ints = self.merge(ints + [[i+ints[0][1]+1, j+ints[0][1]+1] for i,j in ints])
patches += 1

return patches
``````

Patching Array LeetCode Solution in Java

``````public static int minPatches(int[] nums, int n) {
long max = 0;
int cnt = 0;
for (int i = 0; max < n;) {
if (i >= nums.length || max < nums[i] - 1) {
max += max + 1;
cnt++;
} else {
max += nums[i];
i++;
}
}
return cnt;
}
``````
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