Penalty Shots CodeChef Solution

Problem – Penalty Shots CodeChef Solution

It’s the soccer match finals in Chefland and as always it has reached the penalty shotouts. Each team is given 5 shots to make and the team scoring a goal on the maximum number of shots wins the game. If both the teams’ scores are equal, then the game is considered a draw and we would have 2 champions.

Given ten integers A1​,A2​,…,A10​, where the odd indexed integers(A1​,A3​,A5​,A7​,A9​) represent the outcome of the shots made by team 1 and even indexed integers(A2​,A4​,A6​,A8​,A10​) represent the outcome of the shots made by team 2 (here Ai​=1 indicates that it’s a goal and Ai​=0 indicates a miss), determine the winner or find if the game ends in a draw.

Input Format

• The first line of input contains a single integer T denoting the number of test cases. The description of T test cases follows.
• The first and only line of each test case contains ten space-separated integers A1​,A2​,…,A10​.

Output Format

For each test case, print a single line containing one integer – 0 if the game ends in a draw or 1 if the first team wins or 2 if the second team wins.

Constraints

• 1≤T≤1024
• 0≤Ai​≤1

Sample 1:

Input:
4
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 1
1 0 1 0 0 0 0 0 0 0 
1 1 1 1 1 1 1 1 1 0
Output:
0
2
1
1

Explanation:

Test case 1: No team scores any goal, so the game ends in a draw.

Test case 2: The second team is able to score in their final shot, while the first team has scored 0 goals and hence the second team wins.

Test case 3: The first team is successfully able to make their first 2 shots count and whereas the second team has not scored any goals. Therefore the first team wins.

Test case 4: Team 2 misses their final shot and hence team 1 wins the game with the final score of 5−4.

Penalty Shots CodeChef Solution in Java

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public.
*/
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
	 Scanner sc=new Scanner(System.in);
	int t=sc.nextInt();
	while(t>0){
	    int a[]=new int[10];
	    for(int i=0;i<10;i++){
	        a[i]=sc.nextInt();
	        
	    }
	    int te1=0;
	    int te2=0;
	    for(int i=0;i<10;i++){
	        if(i%2==0){
	            te1=a[i]+te1;
	        }
	        else{
	            te2+=a[i];
	        }
	    }
	    if(te1>te2){
	        System.out.println("1");
	    }
	    else if(te1<te2){
	        System.out.println("2");
	    }
	    else{
	         System.out.println("0");
	    }
	    --t;
	}
	}
}

Penalty Shots CodeChef Solution in Pyth 3

# cook your dish here
t = int(input())
for _ in range(t):
    lis = list(map(int,input().split()))
    t1 = []
    t2 = []
    for i in range(10):
        if i%2==0:
            t1.append(lis[i])
        else:
            t2.append(lis[i])
    s1 = sum(t1)
    s2 = sum(t2)
    if s1>s2:
        print(1)
    elif s2>s1:
        print(2)
    else:
        print(0)

Penalty Shots CodeChef Solution in C++17

#include <iostream>
using namespace std;

int main() {
	int t;
	cin>>t;
	while(t--)
	{
	    int x1,y1,x2,y2,x3,y3,x4,y4,x5,y5;
	    cin>>x1>>y1>>x2>>y2>>x3>>y3>>x4>>y4>>x5>>y5;
	    
	    int a=x1+x2+x3+x4+x5;
	    int b=y1+y2+y3+y4+y5;
	    
	    if(a==b)
	    {
	        cout<<"0"<<endl;
	    }
	    else if(a>b)
	    {
	        cout<<"1"<<endl;
	    }
	    else
	    {
	        cout<<"2"<<endl;
	    }
	}
	return 0;
}

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