Power of Two LeetCode Solution

Problem – Power of Two LeetCode Solution

Given an integer n, return true if it is a power of two. Otherwise, return false.

An integer n is a power of two, if there exists an integer x such that n == 2x.

Example 1:

Input: n = 1
Output: true
Explanation: 20 = 1

Example 2:

Input: n = 16
Output: true
Explanation: 24 = 16

Example 3:

Input: n = 3
Output: false

Constraints:

  • -231 <= n <= 231 - 1

 Follow up: Could you solve it without loops/recursion?

Power of Two LeetCode Solution in Python

class Solution(object):
    def isPowerOfTwo(self, n):
        return n and not (n & n - 1)

Power of Two LeetCode Solution in Java

class Solution {
    public boolean isPowerOfTwo(int n) {
        return n > 0 && (n & n - 1) == 0;
    }
}

Power of Two LeetCode Solution in C++

class Solution {
public:
    bool isPowerOfTwo(int n) {
        return n > 0 && not (n & n - 1);
    }
};
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