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*Recent Contest Problems – contains only problems from the last 2 contests**Separate Un-Attempted, Attempted, and All tabs**Problem Difficulty Rating – the Recommended dropdown menu has various difficulty ranges so that you can attempt the problems most suited to your experience**Popular Topics and Tags*

Like most users, Chef didn’t know that he could add problems to a personal to-do list by clicking on the magic **‘+’** symbol on the top-right of each problem page. But once he found out about it, he went crazy and added loads of problems to his to-do list without looking at their difficulty rating.

Chef is a beginner and should ideally try and solve only problems with difficulty rating strictly less than 1000. Given a list of difficulty ratings for problems in the Chef’s to-do list, please help him identify how many of those problems Chef should **remove** from his to-do list, so that he is only left with problems of difficulty rating less than 1000.

- The first line of input will contain a single integer
*T*, the number of test cases. Then the testcases follow. - Each testcase consists of 2 lines of input.
- The first line of input of each test case contains a single integer,
*N*, which is the total number of problems that the Chef has added to his to-do list. - The second line of input of each test case contains
*N*space-separated integers*D*1,*D*2,…,*D**N*, which are the difficulty ratings for each problem in the to-do list.

For each test case, output in a single line the number of problems that Chef will have to remove so that all remaining problems have a difficulty rating strictly less than 1000.

- 1≤
*T*≤1000 - 1≤
*N*≤1000 - 1≤
*D**i*≤5000

**Subtask 1 (100 points):**- Original constraints

**Input**: 5
3
800 1200 900
4
999 1000 1001 1002
5
1 2 2 2 5000
5
1000 1000 1000 1000 1000
3
900 700 800
**Output**: 1
3
1
5
0

**Test case 1:** Among the three difficulty ratings, Chef only needs to remove the problem with difficulty rating 1200, since it is ≥1000. So, the answer is 1.

**Test case 2:** Among the four difficulty ratings, Chef needs to remove the problems with difficulty ratings of 1000, 1001, and 1002, since they are ≥1000. So, the answer is 3.

**Test case 3:** Among the five difficulty ratings, Chef needs to remove the problem with a difficulty rating of 5000, since it is ≥1000. So, the answer is 1.

**Test case 4:** Chef needs to remove all the five problems, since they are all rated ≥1000. So, the answer is 5.

**Test case 5:** Chef does not need to remove any problem, since they are all rated <1000. So, the answer is 0.

```
#include <bits/stdc++.h>
using namespace std;
int main()
{
ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
int t; cin >> t;
while(t--)
{
int n; cin >> n;
int cnt = 0;
for(int i = 0; i < n; ++i)
{
int x; cin >> x;
cnt += x >= 1000;
}
cout<<cnt<<"\n";
}
}
```

```
/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner hello=new Scanner(System.in);
int T=hello.nextInt();
while(T>0){
T--;
int N=hello.nextInt();
int[] D=new int[N];
for(int i=0;i<N;i++){
D[i]=hello.nextInt();
}
int count=0;
for(int i=0;i<N;i++){
if(D[i]>=1000){
count++;
}
}
System.out.println(count);
}
}
}
```

```
# cook your dish here
for x in range(int(input ())):
l=int(input ())
c=0
a=list(map(int, input ().split()))
for i in a:
if i>=1000:
c=c+1
print(c)
```

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