Physical Address

304 North Cardinal St.
Dorchester Center, MA 02124

Product of Array Except Self LeetCode Solution

Problem – Product of Array Except Self

Given an integer array nums, return an array answer such that answer[i] is equal to the product of all the elements of nums except nums[i].

The product of any prefix or suffix of nums is guaranteed to fit in a 32-bit integer.

You must write an algorithm that runs in O(n) time and without using the division operation.

Example 1:

Input: nums = [1,2,3,4]
Output: [24,12,8,6]

Example 2:

Input: nums = [-1,1,0,-3,3]
Output: [0,0,9,0,0]

Constraints:

  • 2 <= nums.length <= 105
  • -30 <= nums[i] <= 30
  • The product of any prefix or suffix of nums is guaranteed to fit in a 32-bit integer.

Follow up: Can you solve the problem in O(1) extra space complexity? (The output array does not count as extra space for space complexity analysis.)

Product of Array Except Self LeetCode Solution in Java

public class Solution {
public int[] productExceptSelf(int[] nums) {
    int n = nums.length;
    int[] res = new int[n];
    res[0] = 1;
    for (int i = 1; i < n; i++) {
        res[i] = res[i - 1] * nums[i - 1];
    }
    int right = 1;
    for (int i = n - 1; i >= 0; i--) {
        res[i] *= right;
        right *= nums[i];
    }
    return res;
}

Product of Array Except Self LeetCode Solution in C++

class Solution {
public:
    vector<int> productExceptSelf(vector<int>& nums) {
        int prod = 1, zeroCnt = count(begin(nums), end(nums), 0);
        if(zeroCnt > 1) return vector<int>(size(nums));               // Case-1
        for(auto c : nums) 
            if(c) prod *= c;                                          // calculate product of all elements except 0
        for(auto& c : nums)
            if(zeroCnt) c = c ? 0 : prod;                             // Case-2
            else c = prod / c;                                        // Case-3
        return nums;
    }
};

Product of Array Except Self LeetCode Solution in Python

class Solution:
    def productExceptSelf(self, nums):
        prod, zero_cnt = reduce(lambda a, b: a*(b if b else 1), nums, 1), nums.count(0)
        if zero_cnt > 1: return [0]*len(nums)
        for i, c in enumerate(nums):
            if zero_cnt: nums[i] = 0 if c else prod
            else: nums[i] = prod // c
        return nums
Product of Array Except Self LeetCode Solution Review:

In our experience, we suggest you solve this Product of Array Except Self LeetCode Solution and gain some new skills from Professionals completely free and we assure you will be worth it.

If you are stuck anywhere between any coding problem, just visit Queslers to get the Product of Array Except Self LeetCode Solution

Find on LeetCode

Conclusion:

I hope this Product of Array Except Self LeetCode Solution would be useful for you to learn something new from this problem. If it helped you then don’t forget to bookmark our site for more Coding Solutions.

This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.

Keep Learning!

More Coding Solutions >>

LeetCode Solutions

Hacker Rank Solutions

CodeChef Solutions

Leave a Reply

Your email address will not be published. Required fields are marked *