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Puppy and Sum CodeChef Solution

Problem – Puppy and Sum CodeChef Solution

Yesterday, puppy Tuzik learned a magically efficient method to find the sum of the integers from 1 to N. He denotes it as sum(N). But today, as a true explorer, he defined his own new function: sum(D, N), which means the operation sum applied D times: the first time to N, and each subsequent time to the result of the previous operation.

For example, if D = 2 and N = 3, then sum(2, 3) equals to sum(sum(3)) = sum(1 + 2 + 3) = sum(6) = 21.

Tuzik wants to calculate some values of the sum(D, N) function. Will you help him with that?


The first line contains a single integer T, the number of test cases. Each test case is described by a single line containing two integers D and N.


For each testcase, output one integer on a separate line.


  • 1 ≤ T ≤ 16
  • 1 ≤ D, N ≤ 4

Sample 1:

1 4
2 3

Puppy and Sum CodeChef Solution in C++14

#include <iostream>
using namespace std;

int main() {
	int t,d,n;
	    int sum=(n*(n+1))/2;
	return 0;

Puppy and Sum CodeChef Solution in Pyth 3

#Solution Provided by Sloth Coders 
T = int(input())
for _ in range(T):
    a, b = map(int, input().split())
    for i in range(0, a):
        b = (b *(b +1)) // 2

Puppy and Sum CodeChef Solution in Java

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
    public static int sum(int b, int res) {
        if (b == 0 ) return res;
        return sum(b-1, res+b);
	public static void main (String[] args) throws java.lang.Exception
		Scanner sc = new Scanner(;
		int t = sc.nextInt();
		while(t-- > 0){
		    int a = sc.nextInt();
		    int b = sc.nextInt();
		    for (int i = 0; i < a; i++) {
		        b = sum(b, 0);
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