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# Rank Scores LeetCode Solution

## Problem – Rank Scores LeetCode Solution

SQL Schema

Table: `Scores`

``````+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| id          | int     |
| score       | decimal |
+-------------+---------+
id is the primary key for this table.
Each row of this table contains the score of a game. Score is a floating point value with two decimal places.
``````

Write an SQL query to rank the scores. The ranking should be calculated according to the following rules:

• The scores should be ranked from the highest to the lowest.
• If there is a tie between two scores, both should have the same ranking.
• After a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no holes between ranks.

Return the result table ordered by `score` in descending order.

The query result format is in the following example.

Example 1:

``````Input:
Scores table:
+----+-------+
| id | score |
+----+-------+
| 1  | 3.50  |
| 2  | 3.65  |
| 3  | 4.00  |
| 4  | 3.85  |
| 5  | 4.00  |
| 6  | 3.65  |
+----+-------+
Output:
+-------+------+
| score | rank |
+-------+------+
| 4.00  | 1    |
| 4.00  | 1    |
| 3.85  | 2    |
| 3.65  | 3    |
| 3.65  | 3    |
| 3.50  | 4    |
+-------+------+``````

## Rank Scores LeetCode Solution in MySQL

``````SELECT
Score,
@rank := @rank + (@prev <> (@prev := Score)) Rank
FROM
Scores,
(SELECT @rank := 0, @prev := -1) init
ORDER BY Score desc
``````

## Rank Scores LeetCode Solution in MS SQL Server

``````SELECT s.Score as Score,
DENSE_RANK() OVER (ORDER BY s.Score DESC) as Rank
FROM Scores s

``````

## Rank Scores LeetCode Solution in Oracle

``````select
s.score Score ,
r.rn Rank
from
Scores s,
(select s.score sc, rownum rn from
(select s.score from Scores s
group by s.Score order by s.score desc) s) r
where s.score = r.sc
``````
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