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# Re.findall() & Re.finditer() Hacker Rank Solution – Queslers

## Problem : Re.findall() & Re.finditer() Hacker Rank Solution

The expression re.findall() returns all the non-overlapping matches of patterns in a string as a list of strings.
Code :

``````>>> import re
>>> re.findall(r'\w','http://www.hackerrank.com/')
['h', 't', 't', 'p', 'w', 'w', 'w', 'h', 'a', 'c', 'k', 'e', 'r', 'r', 'a', 'n', 'k', 'c', 'o', 'm']
``````

re.finditer()
The expression re.finditer() returns an iterator yielding MatchObject instances over all non-overlapping matches for the re pattern in the string.
Code :

``````>>> import re
>>> re.finditer(r'\w','http://www.hackerrank.com/')
<callable-iterator object at 0x0266C790>
>>> map(lambda x: x.group(),re.finditer(r'\w','http://www.hackerrank.com/'))
['h', 't', 't', 'p', 'w', 'w', 'w', 'h', 'a', 'c', 'k', 'e', 'r', 'r', 'a', 'n', 'k', 'c', 'o', 'm']
``````

You are given a string S. It consists of alphanumeric characters, spaces and symbols(+,-).
Your task is to find all the substrings of S that contains 2 or more vowels.
Also, these substrings must lie in between 2 consonants and should contain vowels only.
Note :
Vowels are defined as: AEIOU and aeiou.
Consonants are defined as: QWRTYPSDFGHJKLZXCVBNM and qwrtypsdfghjklzxcvbnm.

#### Input Format :

A single line of input containing string S.

#### Constraints :

• 0 < len(s)<100

#### Output Format :

Print the matched substrings in their order of occurrence on separate lines.
If no match is found, print -1.

#### Sample Input :

``````>>> import re
>>> re.finditer(r'\w','http://www.hackerrank.com/')
<callable-iterator object at 0x0266C790>
>>> map(lambda x: x.group(),re.finditer(r'\w','http://www.hackerrank.com/'))
['h', 't', 't', 'p', 'w', 'w', 'w', 'h', 'a', 'c', 'k', 'e', 'r', 'r', 'a', 'n', 'k', 'c', 'o', 'm']
``````

#### Sample Output :

``````ee
Ioo
Oeo
eeeee
``````

#### Explanation :

ee is located between consonant d and f.
Ioo is located between consonant k and m.
Oeo is located between consonant p and r.
eeeee is located between consonant t and t.

### Re.findall() & Re.finditer() Hacker Rank Solution in python 2

``````import re
consonants = 'qwrtypsdfghjklzxcvbnm'
vowels = 'aeiou'
match = re.findall(r'(?<=['+consonants+'])(['+vowels+']{2,})(?=['+consonants+'])',raw_input(),flags = re.I)
if match:
for i in match:
print i
else:
print -1
``````

### Re.findall() & Re.finditer() Hacker Rank Solution in python 3

``````# Enter your code here. Read input from STDIN. Print output to STDOUT

import re
v = "aeiou"
c = "qwrtypsdfghjklzxcvbnm"
m = re.findall(r"(?<=[%s])([%s]{2,})[%s]" % (c, v, c), input(), flags = re.I)
print('\n'.join(m or ['-1']))``````

## Re.findall() & Re.finditer() Hacker Rank Solution in pypy

``````# Enter your code here. Read input from STDIN. Print output to STDOUT
from __future__ import print_function
import re
list = re.findall(r'(?<=[qwrtypsdfghjklzxcvbnm])([aeiou]{2,})[qwrtypsdfghjklzxcvbnm]', raw_input(), flags=re.I)
print('\n'.join(list or ['-1']))``````

### Re.findall() & Re.finditer() Hacker Rank Solution in pypy 3

``````import re

m = re.findall(r"(?<=[^aeiou])([aeiou]{2,})(?=[^aeiou])", input(), re.IGNORECASE)

if m:
print(*m, sep="\n")
else:
print(-1)``````
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