Reduce to 1 CodeChef Solution

Problem -Reduce to 1 CodeChef Solution

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Reduce to 1 CodeChef Solution in C++17

#include <bits/stdc++.h>
using namespace std;

// long long abs (long long x, long long y)
// {
//     long long z;
//     z = x - y;

//     if (z < 0)
//     {
//         z *= (-1);
//     }

//     return z;
// }

int main()
{
    long long t, v, m, n, x, y, z, i, j, k, a, b, d, p, q;
    long long num, val, check, count, sum, maxm, minm, mid;
    long long c0, c1;
    string s;
    cin >> t;
    v = t;
    // v = 1;

    while (v > 0)
    {
        v --;
        cin >> n;
        // cin >> s;

        // long long arr[n], ori[n], ref[n];
        // n = s.length ();

        // for (i = 0; i < n; i++)
        // {
        //     cin >> arr[i];
        // }

       if (n == 1)
       {
           cout << "0" << endl;
       } 
       else if (n % 2 == 1)
       {
           cout << "1" << endl;
       }
       else
       {
           x = n;
           while (x % 4 == 0)
           {
               x /= 4;
           }
           
           if (x % 2 == 0)
           {
               cout << "-1" << endl;
           }
           else
           {
               y = sqrt (n);
               if (n == (y * y))
               {
                   cout << "1" << endl;
               }
               else
               {
                   cout << "2" << endl;
               }

            //     j = 2;
            //     check = 0;
            //    for (i = y; i >= 2; i--)
            //    {
            //        while (j < 100)
            //        {
            //            if (pow (i, j) == n)
            //            {
            //                cout << "1" << endl;
            //                check = 1;
            //                break;
            //            }
            //            else if (pow (i, j) > n)
            //            {
            //                i --;
            //            }
            //            else
            //            {
            //                i /= 2;
            //                i ++;
            //                j ++;
            //            }

            //            if (i <= 2)
            //            {
            //                break;
            //            }
            //        }
                   
            //        if (i <= 2)
            //        {
            //            break;
            //        }

            //        if (check == 1)
            //        {
            //            break;
            //        }
            //    }

            //    if (check == 0)
            //    {
            //        cout << "2" << endl;
            //    }               
           }
       }
    }
    
    return 0;
}

Reduce to 1 CodeChef Solution in C++14

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef unsigned long ul;
typedef unsigned long long ull;
#define rep(i,a,b) for(ull i=a; i<b; i++)
#define repeat(n)  for(int i=0; i<n; i++) 	
#define err 1e-5
#define _z ios_base::sync_with_stdio(false); cin.tie(NULL);
#define endl "\n"
#define pii pair<int,int>

void solve()
{
	ll n;
	cin>>n;
	if(n==1)
	{
		cout<<"0"<<endl;
		return;
	}
    else if(n%2==1)
    {
    	cout<<"1"<<endl;
    	return;
    }
    int count=0;
    while(n%2==0)
    {
    	count++;
    	n/=2;
    }
    if(count%2==1)
    {
    	cout<<"-1"<<endl;
    	return;
    }
    else
    {
    	ll x= sqrt(n);
    	if(n==x*x)
    	{
    		cout<<"1"<<endl;
    		return;
    	}
    }
    cout<<"2"<<endl;
}

int main()
{
	_z;
	int t;
	cin>>t;
	while(t--)
	{
        solve();
	}
		
}

Reduce to 1 CodeChef Solution in PYTH 3

import math
t = int(input())
for _ in range(t):
    n = int(input())
    r = math.sqrt(n)
    if n % 2 == 1:
        print(min(n-1,1))
    elif r == math.floor(r):
        print(1)
    else:
        while n >= 4 and n % 4 == 0:
            n /= 4
        if n == 1:
            print(1)
        elif n % 2 == 1:
            print(2)
        else:
            print(-1)

Reduce to 1 CodeChef Solution in C

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>

long long int numberof2(long long int n)
{
    long long int t=0;
    while(n%2==0)
    {
        n=n/2;
        t++;
    }
    return t;
}
void loki()
{
    int t;
    scanf("%d",&t);
    while(t--)
    {
        long long int n;
        scanf("%lld",&n);
        long long int nof2=numberof2(n);
        long long int square=sqrt(n);
        long long int num=pow(square,2);
        if(n==1)
        printf("0\n");
        else if(n%2==1||num==n)
        printf("1\n");
        else
        {
            if(nof2%2==1)
            printf("-1\n");
            else
            {
                long long int p=pow(2,nof2);
                n=n/p;
                if(n==1)
                printf("1\n");
                else
                printf("2\n");
            }
        }
    }
}
int main(void) {
	loki();
	return 0;
}

Reduce to 1 CodeChef Solution in JAVA

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		 Scanner in = new Scanner(System.in);
        int t = in.nextInt();
        
        for (int k = 0; k < t; k++) {
            
            long n = in.nextLong();
            
            if (n == 1) {
                System.out.println(0);
                continue;
            }
            
            if (n % 2 == 1) {
                System.out.println(1);
                continue;
            }
            
            int cnt = 0;
            
            while (n % 2 == 0) {
                cnt += 1;
                n /= 2;
            }
            
            if (cnt % 2 == 0) {
                boolean flag = false;
                
                for (int i = 2; i <= cnt; i+= 2) {
                    if (cnt % i != 0) {
                        continue;
                    }
                    
                    double p = 1.0 / i;
                    if ( Math.pow((double)n, p) == (int) Math.pow((double)n, p)) {
                        flag = true;
                        break;
                    }
                    
                    
                }
                
                if (flag == true) {
                        System.out.println(1);
                    } else {
                        System.out.println(2);
                    }
            } else {
                System.out.println(-1);
            }
            
            
        }
	}
}

Reduce to 1 CodeChef Solution in PYPY 3

import math
N = int(input())
for i in range(N):
    n = int(input())
    r = math.sqrt(n)
    if n % 2 == 1:
        print(min(n-1,1))
    elif r == math.floor(r):
        print(1)
    else:
        while n >= 4 and n % 4 == 0:
            n /= 4
        if n == 1:
            print(1)
        elif n % 2 == 1:
            print(2)
        else:
            print(-1)

Reduce to 1 CodeChef Solution in PYTH

import math
t = int(input())
for i in range(t):
    n = int(input())
    if n == 1:
        print(0)
        continue
    if int(math.sqrt(n))**2 == n:
        print(1)
        continue
    if n%2==1:
        print(1)
    else:
        e = 0
        d = n
        while d%2==0:
            d //= 2
            e+=1
        if e%2==1:
            print(-1)
        elif d==1:
            print(1)
        else:
            print(2)

Reduce to 1 CodeChef Solution in C#

using System;
using System.Linq;
using System.Collections.Generic;
using System.Text.RegularExpressions;
using System.Text;
using System.Numerics;


public class Test
{
    public static int GetInt() => int.Parse(Console.ReadLine());
    public static long GetLong() => long.Parse(Console.ReadLine());
    
    public static int[] GetIntArray() =>  Console.ReadLine().Trim().Split(' ').Select(int.Parse).ToArray();
    public static long[] GetLongArray() =>  Console.ReadLine().Trim().Split(' ').Select(long.Parse).ToArray();
	
	public static int Gcd(int a, int b) => b == 0 ? a : Gcd(b, a%b);
	public static int Gcd(int[] n) => n.Aggregate((a,b) => Gcd(a,b));

	public static void Main()
	{
    var t=GetInt(); for(int i = 0; i<t; i++) { Solve(); }
  	// Solve(); 
	}
	
	public static void Solve()
	{
    long n = GetLong();
    long ncopy = n;
    if(n == 1)
    {
      Console.WriteLine(0);
      return;
    }
    int p2 = 0;
    while(n%2 == 0)
    {
      n /=2;
      p2++;
    }
    if(p2 == 0)
    {
      Console.WriteLine(1);
      return;
    }
    if(p2 % 2 != 0)
    {
      Console.WriteLine(-1);
      return;
    }
    int ans = 1;
    long q = (long)Math.Sqrt(ncopy);
    if(ncopy != q * q)
    {
        ans++;
    }
    Console.WriteLine(ans);
	}
}

Reduce to 1 CodeChef Solution in GO

package main

import (
	"bufio"
	"bytes"
	"fmt"
	"math"
	"os"
)

func main() {
	reader := bufio.NewReader(os.Stdin)

	var buf bytes.Buffer

	tc := readNum(reader)

	for tc > 0 {
		tc--
		var n uint64

		s, _ := reader.ReadBytes('\n')

		readUint64(s, 0, &n)

		res := solve(int64(n))

		buf.WriteString(fmt.Sprintf("%d\n", res))
	}

	fmt.Print(buf.String())
}

func readUint64(bytes []byte, from int, val *uint64) int {
	i := from

	var tmp uint64
	for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
		tmp = tmp*10 + uint64(bytes[i]-'0')
		i++
	}
	*val = tmp

	return i
}

func readInt(bytes []byte, from int, val *int) int {
	i := from
	sign := 1
	if bytes[i] == '-' {
		sign = -1
		i++
	}
	tmp := 0
	for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
		tmp = tmp*10 + int(bytes[i]-'0')
		i++
	}
	*val = tmp * sign
	return i
}

func readString(reader *bufio.Reader) string {
	s, _ := reader.ReadString('\n')
	for i := 0; i < len(s); i++ {
		if s[i] == '\n' {
			return s[:i]
		}
	}
	return s
}

func readNum(reader *bufio.Reader) (a int) {
	bs, _ := reader.ReadBytes('\n')
	readInt(bs, 0, &a)
	return
}

func readTwoNums(reader *bufio.Reader) (a int, b int) {
	res := readNNums(reader, 2)
	a, b = res[0], res[1]
	return
}

func readThreeNums(reader *bufio.Reader) (a int, b int, c int) {
	res := readNNums(reader, 3)
	a, b, c = res[0], res[1], res[2]
	return
}

func readNNums(reader *bufio.Reader, n int) []int {
	res := make([]int, n)
	x := 0
	bs, _ := reader.ReadBytes('\n')
	for i := 0; i < n; i++ {
		for x < len(bs) && (bs[x] < '0' || bs[x] > '9') && bs[x] != '-' {
			x++
		}
		x = readInt(bs, x, &res[i])
	}
	return res
}

func solve(n int64) int64 {
	if n == 1 {
		return 0
	}
	//sqrt(n) LTE
	var count int

	for n%2 == 0 {
		n /= 2
		count++
	}

	if count == 0 {
		return 1
	}

	if count%2 == 1 {
		return -1
	}

	x := int64(math.Sqrt(float64(n)))

	if x*x == n {
		return 1
	}

	return 2
}

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