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Reduce to zero CodeChef Solution

Problem -Reduce to zero CodeChef Solution

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Reduce to zero CodeChef Solution in C++17

#include <bits/stdc++.h>
using namespace std;
#define ll long long 
#define mod 1000000007
#define Time cerr << "time taken : " << (float)clock() / CLOCKS_PER_SEC << " secs" << endl;
#define pb push_back
#define mp make_pair
#define line cout << endl;
#define ff first
#define ss second
#define vi vector<int>
#define no cout << "NO" << endl;
#define yes cout << "YES" << endl;
#define printv(v)                      \
  for (int i = 0; i < (v.size()); i++) \
  {                                    \
    cout << v[i] << " ";               \
  }                                    \
  line;
#define onesbits(x) __builtin_popcountll(x)
#define zerobits(x) __builtin_ctzll(x)
#define sp(x, y) fixed << setprecision(y) << x
#define w(x) \
  int x;     \
  cin >> x;  \
  while (x--)
#define tk(x) \
  int x;      \
  cin >> x;
#define fast ios_base::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr);
#ifndef ONLINE_JUDGE
#define debug(x)     \
  cerr << #x << " "; \
  _print(x);         \
  cerr << endl;
#else
#define debug(x)
#endif
template <class T>
void _print(T t)
{
  cerr << t;
}

template <class T, class V>
void _print(pair<T, V> p)
{
  cerr << "{";
  _print(p.ff);
  cerr << ",";
  _print(p.ss);
  cerr << "}";
}

template <class T>
void _print(vector<T> v)
{
  cerr << "[ ";
  for (T i : v)
  {
    _print(i);
    cerr << " ";
  }
  cerr << "]";
}

template <class T>
void _print(vector<vector<T>> v)
{
  cerr << "[\n";
  for (int l = 0; l < v.size(); l++)
  {
    {
      for (int k = 0; k < v[l].size(); k++)
        cerr << v[l][k] << " ";
    }
    cerr << "\n";
  }
  cerr << "]";
}

template <class T, class V>
void _print(map<T, V> v)
{
  cerr << "[ ";
  for (auto i : v)
  {
    _print(i);
    cerr << " ";
  }
  cerr << "]";
}

template <class T>
void _print(set<T> v)
{
  cerr << "[ ";
  for (T i : v)
  {
    _print(i);
    cerr << " ";
  }
  cerr << "]";
}

const long long inf = 1e18;
const int MOD = 1e9 + 7;
const int MAX = 1e6;

bool isValid(string s)
{
  int len = s.size();
  for (int i = 0; i < len / 2; i++)
  {
    if (s[i] != s[len - 1 - i])
      return false;
  }
  return true;
}

bool isPalindrome(string S, int start, int end){
    
    int i=start;
    int j=end;
    
    while(i<j){
        if(S[i] != S[j])
            return false;
        i++;
        j--;
    }
    return true;
}

void rotateMatrix(vector<vector<int>> &v, int n)
{
  for (int i = 0; i < n / 2; i++)
  {
    for (int j = i; j < n - i - 1; j++)
    {
      int ptr = v[i][j];
      v[i][j] = v[n - 1 - j][i];
      v[n - 1 - j][i] = v[n - 1 - i][n - 1 - j];
      v[n - 1 - i][n - 1 - j] = v[j][n - 1 - i];
      v[j][n - 1 - i] = ptr;
    }
  }
}

vector<bool> is_prime(10001, 1);
vector<int> primes;

void seive() {
  is_prime[0] = 0;
  is_prime[1] = 0;
  for (int i = 2; i < 10001; i++) {
    if (is_prime[i]) {
      primes.push_back(i);
      for (int j = i + i; j < 10001; j += i) {
        is_prime[j] = 0;
      }
    }
  }
}

string makePalindrome(string S){
    
    int i=0;
    int j=S.length()-1;
    
    while(i<j){
        
        if(S[i] == S[j]){
            i++;
            j--;
        }else{
            
            if(isPalindrome(S, i+1, j))
                return "YES";
            
            if(isPalindrome(S, i, j-1))
                return "YES";
            
            return "NO";
        }
    }
    
    return "YES";
}

int32_t main() {

    int t;
    cin>>t;
    while(t--){
      ll n,k;cin>>n>>k;

      if(n==k){
        cout<<n<<" ";
        continue;
      } 

      if(n==0|| k==0){
        cout<<-1<<endl;
        continue;
      }


      ll a=min(n,k);
      ll b=max(n,k);
      ll ans=0;

      while(a<=b){
        a*=2;
        ans++;
      }

      a=a/2;
      ans--;

      if(a==b){
        ans+=b;
        cout<<ans<<endl;
      }else {
        ans+=b+1;
        cout<<ans<<endl;
      }
    }
  return 0;
}

Reduce to zero CodeChef Solution in C++14

#include <bits/stdc++.h>
using namespace std;
#define ll long long 
#define mod 1000000007
#define Time cerr << "time taken : " << (float)clock() / CLOCKS_PER_SEC << " secs" << endl;
#define pb push_back
#define mp make_pair
#define line cout << endl;
#define ff first
#define ss second
#define vi vector<int>
#define no cout << "NO" << endl;
#define yes cout << "YES" << endl;
#define printv(v)                      \
  for (int i = 0; i < (v.size()); i++) \
  {                                    \
    cout << v[i] << " ";               \
  }                                    \
  line;
#define onesbits(x) __builtin_popcountll(x)
#define zerobits(x) __builtin_ctzll(x)
#define sp(x, y) fixed << setprecision(y) << x
#define w(x) \
  int x;     \
  cin >> x;  \
  while (x--)
#define tk(x) \
  int x;      \
  cin >> x;
#define fast ios_base::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr);
#ifndef ONLINE_JUDGE
#define debug(x)     \
  cerr << #x << " "; \
  _print(x);         \
  cerr << endl;
#else
#define debug(x)
#endif
template <class T>
void _print(T t)
{
  cerr << t;
}

template <class T, class V>
void _print(pair<T, V> p)
{
  cerr << "{";
  _print(p.ff);
  cerr << ",";
  _print(p.ss);
  cerr << "}";
}

template <class T>
void _print(vector<T> v)
{
  cerr << "[ ";
  for (T i : v)
  {
    _print(i);
    cerr << " ";
  }
  cerr << "]";
}

template <class T>
void _print(vector<vector<T>> v)
{
  cerr << "[\n";
  for (int l = 0; l < v.size(); l++)
  {
    {
      for (int k = 0; k < v[l].size(); k++)
        cerr << v[l][k] << " ";
    }
    cerr << "\n";
  }
  cerr << "]";
}

template <class T, class V>
void _print(map<T, V> v)
{
  cerr << "[ ";
  for (auto i : v)
  {
    _print(i);
    cerr << " ";
  }
  cerr << "]";
}

template <class T>
void _print(set<T> v)
{
  cerr << "[ ";
  for (T i : v)
  {
    _print(i);
    cerr << " ";
  }
  cerr << "]";
}

const long long inf = 1e18;
const int MOD = 1e9 + 7;
const int MAX = 1e6;

bool isValid(string s)
{
  int len = s.size();
  for (int i = 0; i < len / 2; i++)
  {
    if (s[i] != s[len - 1 - i])
      return false;
  }
  return true;
}

bool isPalindrome(string S, int start, int end){
    
    int i=start;
    int j=end;
    
    while(i<j){
        if(S[i] != S[j])
            return false;
        i++;
        j--;
    }
    return true;
}

void rotateMatrix(vector<vector<int>> &v, int n)
{
  for (int i = 0; i < n / 2; i++)
  {
    for (int j = i; j < n - i - 1; j++)
    {
      int ptr = v[i][j];
      v[i][j] = v[n - 1 - j][i];
      v[n - 1 - j][i] = v[n - 1 - i][n - 1 - j];
      v[n - 1 - i][n - 1 - j] = v[j][n - 1 - i];
      v[j][n - 1 - i] = ptr;
    }
  }
}

vector<bool> is_prime(10001, 1);
vector<int> primes;

void seive() {
  is_prime[0] = 0;
  is_prime[1] = 0;
  for (int i = 2; i < 10001; i++) {
    if (is_prime[i]) {
      primes.push_back(i);
      for (int j = i + i; j < 10001; j += i) {
        is_prime[j] = 0;
      }
    }
  }
}

string makePalindrome(string S){
    
    int i=0;
    int j=S.length()-1;
    
    while(i<j){
        
        if(S[i] == S[j]){
            i++;
            j--;
        }else{
            
            if(isPalindrome(S, i+1, j))
                return "YES";
            
            if(isPalindrome(S, i, j-1))
                return "YES";
            
            return "NO";
        }
    }
    
    return "YES";
}

int32_t main() {

    int t;
    cin>>t;
    while(t--){
      ll n,k;cin>>n>>k;

      if(n==k){
        cout<<n<<" ";
        continue;
      } 

      if(n==0|| k==0){
        cout<<-1<<endl;
        continue;
      }


      ll a=min(n,k);
      ll b=max(n,k);
      ll ans=0;

      while(a<=b){
        a*=2;
        ans++;
      }

      a=a/2;
      ans--;

      if(a==b){
        ans+=b;
        cout<<ans<<endl;
      }else {
        ans+=b+1;
        cout<<ans<<endl;
      }
    }
  return 0;
}

Reduce to zero CodeChef Solution in PYTH 3

from math import log2, ceil

def soln(x, y):
    if x == 0 and y == 0:
        return 0
    if x == 0 or y == 0:
        return -1
    if x == y:
        return x
    elif x > y:
        return ceil(log2(x/y)) + x
    else:
        return ceil(log2(y/x)) + y
    return -1

for _ in range(int(input())):
    x, y = map(int, input().split())
    print(int(soln(x, y)))

Reduce to zero CodeChef Solution in C

#include <stdio.h>
int main(void) {
	// your code goes here
	int t; long int x,y,l,i;
	scanf("%d",&t);
	for( ;t>0;t--)
	{  scanf("%ld %ld",&x,&y);
	  if(x>y)
	  {
	      i=x;
	      x=y;
	      y=i;
	  }
	  if(x==y)
	   printf("%ld\n",x);
	  else if(x==0)
	   printf("-1\n");
	  else
	  {  i=0;
	      while(2*x<y)
	     {   x*=2;
	         i++;
	     }
	     l=y-x;
	    for( ;x!=l;x--,y--,i++);
	    printf("%ld\n",i+y+1);
	  }
	}
	return 0;
}

Reduce to zero CodeChef Solution in JAVA

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */





class io{
    BufferedReader bin;
    StringTokenizer st=new StringTokenizer("");
    public io(){
        bin=new BufferedReader(new InputStreamReader(System.in));
        return;
    }
    
    public String next(){
        while(!st.hasMoreTokens()){
            try{
                st=new StringTokenizer(bin.readLine());
            }
            catch(Exception e){
                e.printStackTrace();
            }
        }
        return st.nextToken();
    }
    
    public int nextInt(){
        return Integer.parseInt(next());
    }
    
    public long nextLong(){
        return Long.parseLong(next());
    }
    public double nextDouble(){
        return Double.parseDouble(next());
    }
    public String nextLine(){
        try{
        return bin.readLine();
        }
        catch(Exception e){}
        return null;
    }
    public boolean hasNext(){
        String next=null;
        try{
            next=bin.readLine();
        }
        catch(Exception e){
        }
        if(next==null)
            return false;
        st=new StringTokenizer(next);
        return true;
    }
}
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		// your code goes here
		io sc = new io();
		int T = sc.nextInt();
		while(T-->0){
		    long one = sc.nextLong();
		    long two = sc.nextLong();
		    long res = 0;
		    
		    if(one ==two){
		        System.out.println(one);
		        continue;
		    }
		    if(one==0){
		        System.out.println("-1");
		        continue;
		    }
		    if(two==0){
		        System.out.println("-1");
		        continue;
		        
		    }
		  //  boolean flag=  false;
		    if(one>two){
		        long temp = one;
		        one=  two;
		        two=temp;
		    }
		    if(one<two){
		        while(one<two){
		            one*=2;
		            res++;
		            
		        }
		        
		        
		            res+=two;
		        
		        
		    }
		    
		        
		    System.out.println(res);
		    
		}
	}
}

Reduce to zero CodeChef Solution in PYPY 3


def helper(x,y,count):
    if x > y:
        x,y = y,x
    if x == 0 and y == 0:
        return 0
    if x == 0:
        return -1
    while y > x:
        x = 2*x
        count += 1
    return count + y 
for t in range(int(input())):
    a,b = (map(int,input().split(' ')))
    print(helper(a,b,0))

Reduce to zero CodeChef Solution in PYTH

# cook your code here
class Zero:
	def __init__(self, x, y):
		self.x = x
		self.y = y

	def solve(self):
		x = self.x
		y = self.y
		if x == y:
			return x
		if x > y:
			(x, y) = (y, x)
		if x == 0:
			return -1
		rez = 0
		while 2 * x < y:
			x *= 2
			rez += 1
		d = x - (y - x)
		rez += d
		y -= d
		rez += y
		rez += 1
		return rez

def main():
	T = int(raw_input())
	while T > 0:
		T -= 1
		s = [int(a) for a in raw_input().split(' ')]
		ob = Zero(s[0], s[1])
		print ob.solve()

if __name__ == '__main__':
	main()

Reduce to zero CodeChef Solution in C#

using System;

public class Test
{
    static void Main(string[] args)
    {
        int t = 1;
        t = int.Parse(Console.ReadLine());
        while (t-- > 0) Console.WriteLine(Solve());
    }


    private static long Solve()
    {
        string[] input = Console.ReadLine().Split(' ');
        int si = 0;
        long x = StringToLong(input[0], 0, out si);
        long y = StringToLong(input[1], 0, out si);
        long res = 0;

        if (x < y)
        {
            long z = x;
            x = y;
            y = z;
        }

        if (x == 0 && y == 0) return 0;
        else if (x == 0 || y == 0) return -1;

        while (y * 2 <= x)
        {
            y *= 2;
            res++;
        }

        if (x == y) return x + res;
        return x + res + 1;
    }

    static long StringToLong(string s, int index, out int space_i)
    // Convert string from index up to next space or end to integer.
    // Return space_i = index of next space encountered, or off end of string.
    {
        const int c_zero = '0';
        long n = s[index] - c_zero;
        int len = s.Length;
        while (++index < len)
        {
            if (s[index] < c_zero)
                break;
            n = n * 10 + (s[index] - c_zero);
        }
        space_i = index;
        return n;
    }
    const string c_digits = "0123456789";
    static string LongToString(long a)
    // Convert zero or positive integer to string
    {
        char[] str = new char[20]; // maximum number of chars
        int i = 20;
        str[--i] = ' ';  // space after
        do
        {
            str[--i] = c_digits[(int)(a % 10)];
            a /= 10;
        } while (a != 0);
        return new string(str, i, str.Length - i);
    }
}

Reduce to zero CodeChef Solution in GO 

package main

import (
	"bufio"
	"bytes"
	"fmt"
	"os"
)

func main() {

	reader := bufio.NewReader(os.Stdin)

	tc := readNum(reader)
	var buf bytes.Buffer
	for tc > 0 {
		tc--

		var x uint64
		var y uint64

		s, _ := reader.ReadBytes('\n')

		pos := readUint64(s, 0, &x) + 1
		readUint64(s, pos, &y)
		res := solve(x, y)

		buf.WriteString(fmt.Sprintf("%d\n", res))
	}
	fmt.Print(buf.String())
}

func readUint64(bytes []byte, from int, val *uint64) int {
	i := from

	var tmp uint64
	for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
		tmp = tmp*10 + uint64(bytes[i]-'0')
		i++
	}
	*val = tmp

	return i
}

func readInt(bytes []byte, from int, val *int) int {
	i := from
	sign := 1
	if bytes[i] == '-' {
		sign = -1
		i++
	}
	tmp := 0
	for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
		tmp = tmp*10 + int(bytes[i]-'0')
		i++
	}
	*val = tmp * sign
	return i
}

func readString(reader *bufio.Reader) string {
	s, _ := reader.ReadString('\n')
	for i := 0; i < len(s); i++ {
		if s[i] == '\n' {
			return s[:i]
		}
	}
	return s
}

func readNum(reader *bufio.Reader) (a int) {
	bs, _ := reader.ReadBytes('\n')
	readInt(bs, 0, &a)
	return
}

func readTwoNums(reader *bufio.Reader) (a int, b int) {
	res := readNNums(reader, 2)
	a, b = res[0], res[1]
	return
}

func readThreeNums(reader *bufio.Reader) (a int, b int, c int) {
	res := readNNums(reader, 3)
	a, b, c = res[0], res[1], res[2]
	return
}

func readNNums(reader *bufio.Reader, n int) []int {
	res := make([]int, n)
	x := 0
	bs, _ := reader.ReadBytes('\n')
	for i := 0; i < n; i++ {
		for x < len(bs) && (bs[x] < '0' || bs[x] > '9') && bs[x] != '-' {
			x++
		}
		x = readInt(bs, x, &res[i])
	}
	return res
}

func solve(x, y uint64) int64 {
	// x => 2 * x, shifts left
	// y => 2 * y, shifts right
	// x-- and y--
	if x > y {
		x, y = y, x
	}
	// x < y
	if x == y {
		return int64(x)
	}

	if x == 0 {
		return -1
	}
	var res int64
	for x < y {
		res++
		x *= 2
	}
	// x * 2 > y
	return res + int64(y)
}
Reduce to zero CodeChef Solution Review:

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